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Statistics – Level 2
C.S.VEERARAGAVAN
The mid value of the class
27.5 – 37.5 is
32
32.5
33
33.5
0
4
The mid value of the class 27.5 – 37.5 is
32
32.5
33
33.5
Mid value =
Lower limit+Upper Limit
2
0
4
The mid value of the class 27.5 – 37.5 is
32
32.5
33
33.5
Mid value =
Lower limit+Upper Limit
2
Mid value =
27.5 + 37.5
2
...
If the mid value of an inclusive
class of size 7 is 9, Then the
class interval is
5 – 13
6 – 12
8 – 10
None of these
0
3
If the mid value of an inclusive
class of size 7 is 9, Then the
class interval is
5 – 13
6 – 12
8 – 10
None of these
Lower...
If the mid value of an
inclusive class of size 7 is 9,
Then the class interval is
5 – 13
6 – 12
8 – 10
None of these
Lower...
The size of the exclusive class
interval 24 – 34 is
9
11
10
24
0
1
The difference between the lower (
or upper) limits of two successive
classes is the
Lower bound
Upper bound
Mid value of ...
The arithmetic mean of the
series 2,5,8,11,14
8
6
9
7
0
5
The arithmetic mean of the
series 2,5,8,11,14
8
6
9
7
Mean of A.P =
First Number + Last number
2
0
5
Mean deviation of 8 and 17 is
4
3.5
4.5
5.5
0
6
Mean deviation of 8 and 17 is
4
3.5
4.5
5.5
Mean deviation =
17 −8
2
= 4.5
0
6
Mode of 3, 1 , 2 , 3 , 2 , 1, x , 3 , 4 , 3, 6
3
2
x
Cannot be determined
0
7
The upper boundary of an
inclusive type class 10 – 14 is
14
10
14.5
9.5
0
8
The upper boundary of an
inclusive type class 10 – 14 is
14
10
14.5
9.5
Boundaries of a class are obtained by
Subtracting ...
The range of the values
7, 8, 12, 9, 6, 13, 15, 21, 19, 5 is
15
13
14
16
0
9
The range of the values
7, 8, 12, 9, 6, 13, 15, 21, 19, 5 is
15
13
14
16
Range = 21 – 5 = 16
0
9
When a constant ‘c’ is subtracted from
every observation of given individual data
then the standard deviation of the data ...
The sum of the deviations about
mean of an individual data is equal
to
0
its arithmetic mean
its mean deviation
its range
...
The sum of deviations is least
when taken about
Mean
Median
Mode
All of the above
1
2
If the variance of x1, x2,x3…xn is p, then the s.d of
2x1 + 3, 2x2 + 3, …2xn + 3 is
𝑝
2 𝑝 + 3
2p + 3
2 𝑝
3
0
When 10 < x < 15, then the median
of the data 6, 18 , 21, 9 , 23, 5 and
x is
9
21
x
Cannot be determined
1
3
The A.M and the sum of
observations of individual data is 9
and 108 resp. The no. of
observations = ?12
10
11
5
1
4
The A.M and the sum of
observations of individual data is 9
and 108 resp. The no. of
observations = ?12
10
11
5
A.M =
Sum ...
For a symmetric distribution, the
mode is 24. The A.M of the
distribution is
22
26
24
Cannot be distributed
1
5
For a moderately symmetric distribution,
Mode – Median = ?
Median – Mean
Mode – Mean
3(Median – Mean)
2(Median – mean)
1
6
For a moderately symmetric distribution,
Mode – Median = ?
Median – Mean
Mode – Mean
3(Median – Mean)
2(Median – mean)
For...
The arithmetic mean of
the first n natural
numbers is
n n+1
2
n
2
n+1
2
n+1
2n
1
7
The A.M of the series x1, x2,x3… is 𝑥 then
the A.M of x1 – a , x2 – a , x3 – a , … xn – a is
𝑥
𝑥 – a
𝑥 – a
a 𝑥
2
9
Median of 8, 12, 13, 17 and 19 is
12.5
13
13.5
6.5
1
8
Median of the data
6, 15, 21, 28, 32 and 40
is24.5
24
21.5
28
1
9
The median of the first five prime
numbers is
11
5
7
2
2
7
The median of five
observations is the third
observation.
12-06-2015VEERARAGAVAN C S
veeraa1729@gmail.com 9894834264
34
The median of five
observations is the third
observation.
The third prime no is 5.
12-06-2015VEERARAGAVAN C S
veeraa1729@g...
In some individual data consisting of 20
observations, the observation a0 occurs
for the greatest number of times. The
mod...
The G.M of the data 1, 3, 12 is
36
6
3
36
3
2
1
If A, G and H are A.M, G.M & H.M of
2 +ve nos. a and b, then which is
true? A
G
=
H
A
G
H
=
H
A
A
G
=
G
A
A
G
=
G
H
2
2
If each observation is increased by
5, then the range of the data
Increases by 5
Decreases by 5
Does not change
May or may...
If the range and the minimum value of
the observations are 17 and 88 resp.,
then the maximum value of the data
is
100
105
...
The first quartile (Q1) of the observations
4, 8, 10, 15, 17, 29 and 32 is
8
16
29
53
2
5
The first quartile (Q1) of the observations
4, 8, 10, 15, 17, 29 and 32 is
53
29
16
8
If the data is in ascending order,
t...
The third quartile ( Q3) of the data 16,
21, 23, 25, 29, 32, 46, 48, 51, 53
, 54
51
48
29
53
2
6
The third quartile ( Q3) of the data 16,
21, 23, 25, 29, 32, 46, 48, 51, 53
, 54
51
48
29
53
2
6
The third quartile is the...
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Statistics – level 2

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Statistics – level 2

  1. 1. Statistics – Level 2 C.S.VEERARAGAVAN
  2. 2. The mid value of the class 27.5 – 37.5 is 32 32.5 33 33.5 0 4
  3. 3. The mid value of the class 27.5 – 37.5 is 32 32.5 33 33.5 Mid value = Lower limit+Upper Limit 2 0 4
  4. 4. The mid value of the class 27.5 – 37.5 is 32 32.5 33 33.5 Mid value = Lower limit+Upper Limit 2 Mid value = 27.5 + 37.5 2 0 4
  5. 5. If the mid value of an inclusive class of size 7 is 9, Then the class interval is 5 – 13 6 – 12 8 – 10 None of these 0 3
  6. 6. If the mid value of an inclusive class of size 7 is 9, Then the class interval is 5 – 13 6 – 12 8 – 10 None of these Lower limit is 9 – 7−1 2 = 9 – 3 = 6 0 3
  7. 7. If the mid value of an inclusive class of size 7 is 9, Then the class interval is 5 – 13 6 – 12 8 – 10 None of these Lower limit is 9 – 7−1 2 = 9 – 3 = 6 Upper limit is 9 + 7−1 2 = 9 + 3 = 12 0 3
  8. 8. The size of the exclusive class interval 24 – 34 is 9 11 10 24 0 1
  9. 9. The difference between the lower ( or upper) limits of two successive classes is the Lower bound Upper bound Mid value of the class Size of the class, for a continous distribution 0 2
  10. 10. The arithmetic mean of the series 2,5,8,11,14 8 6 9 7 0 5
  11. 11. The arithmetic mean of the series 2,5,8,11,14 8 6 9 7 Mean of A.P = First Number + Last number 2 0 5
  12. 12. Mean deviation of 8 and 17 is 4 3.5 4.5 5.5 0 6
  13. 13. Mean deviation of 8 and 17 is 4 3.5 4.5 5.5 Mean deviation = 17 −8 2 = 4.5 0 6
  14. 14. Mode of 3, 1 , 2 , 3 , 2 , 1, x , 3 , 4 , 3, 6 3 2 x Cannot be determined 0 7
  15. 15. The upper boundary of an inclusive type class 10 – 14 is 14 10 14.5 9.5 0 8
  16. 16. The upper boundary of an inclusive type class 10 – 14 is 14 10 14.5 9.5 Boundaries of a class are obtained by Subtracting 0.5 from Lower limit and Adding 0.5 to Upper limit. 0 8
  17. 17. The range of the values 7, 8, 12, 9, 6, 13, 15, 21, 19, 5 is 15 13 14 16 0 9
  18. 18. The range of the values 7, 8, 12, 9, 6, 13, 15, 21, 19, 5 is 15 13 14 16 Range = 21 – 5 = 16 0 9
  19. 19. When a constant ‘c’ is subtracted from every observation of given individual data then the standard deviation of the data is Increases by c Decreases by c Unchanged Cannot be determined 1 0
  20. 20. The sum of the deviations about mean of an individual data is equal to 0 its arithmetic mean its mean deviation its range 11
  21. 21. The sum of deviations is least when taken about Mean Median Mode All of the above 1 2
  22. 22. If the variance of x1, x2,x3…xn is p, then the s.d of 2x1 + 3, 2x2 + 3, …2xn + 3 is 𝑝 2 𝑝 + 3 2p + 3 2 𝑝 3 0
  23. 23. When 10 < x < 15, then the median of the data 6, 18 , 21, 9 , 23, 5 and x is 9 21 x Cannot be determined 1 3
  24. 24. The A.M and the sum of observations of individual data is 9 and 108 resp. The no. of observations = ?12 10 11 5 1 4
  25. 25. The A.M and the sum of observations of individual data is 9 and 108 resp. The no. of observations = ?12 10 11 5 A.M = Sum of observations No of observations 1 4
  26. 26. For a symmetric distribution, the mode is 24. The A.M of the distribution is 22 26 24 Cannot be distributed 1 5
  27. 27. For a moderately symmetric distribution, Mode – Median = ? Median – Mean Mode – Mean 3(Median – Mean) 2(Median – mean) 1 6
  28. 28. For a moderately symmetric distribution, Mode – Median = ? Median – Mean Mode – Mean 3(Median – Mean) 2(Median – mean) For a moderately symmetric distribution Mode = 3 median – 2 mean 1 6
  29. 29. The arithmetic mean of the first n natural numbers is n n+1 2 n 2 n+1 2 n+1 2n 1 7
  30. 30. The A.M of the series x1, x2,x3… is 𝑥 then the A.M of x1 – a , x2 – a , x3 – a , … xn – a is 𝑥 𝑥 – a 𝑥 – a a 𝑥 2 9
  31. 31. Median of 8, 12, 13, 17 and 19 is 12.5 13 13.5 6.5 1 8
  32. 32. Median of the data 6, 15, 21, 28, 32 and 40 is24.5 24 21.5 28 1 9
  33. 33. The median of the first five prime numbers is 11 5 7 2 2 7
  34. 34. The median of five observations is the third observation. 12-06-2015VEERARAGAVAN C S veeraa1729@gmail.com 9894834264 34
  35. 35. The median of five observations is the third observation. The third prime no is 5. 12-06-2015VEERARAGAVAN C S veeraa1729@gmail.com 9894834264 35
  36. 36. In some individual data consisting of 20 observations, the observation a0 occurs for the greatest number of times. The mode isa0 a0 2 2a0 Cannot determine 2 0
  37. 37. The G.M of the data 1, 3, 12 is 36 6 3 36 3 2 1
  38. 38. If A, G and H are A.M, G.M & H.M of 2 +ve nos. a and b, then which is true? A G = H A G H = H A A G = G A A G = G H 2 2
  39. 39. If each observation is increased by 5, then the range of the data Increases by 5 Decreases by 5 Does not change May or may not change 2 3
  40. 40. If the range and the minimum value of the observations are 17 and 88 resp., then the maximum value of the data is 100 105 71 110 2 4
  41. 41. The first quartile (Q1) of the observations 4, 8, 10, 15, 17, 29 and 32 is 8 16 29 53 2 5
  42. 42. The first quartile (Q1) of the observations 4, 8, 10, 15, 17, 29 and 32 is 53 29 16 8 If the data is in ascending order, then Q1 = n+1 4 𝑡ℎ data. 2 5
  43. 43. The third quartile ( Q3) of the data 16, 21, 23, 25, 29, 32, 46, 48, 51, 53 , 54 51 48 29 53 2 6
  44. 44. The third quartile ( Q3) of the data 16, 21, 23, 25, 29, 32, 46, 48, 51, 53 , 54 51 48 29 53 2 6 The third quartile is the 3 4 Q3 is 3 4 n+1 th data = 9th data

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