1. what amount of 0.50 mol/L NaOH is required to titrate 10.0 ml of a 2.00 moll/L H2SO4
solution?
Solution
volume of H2SO4 solution = 10 ml = 0.01 L
concentration of H2SO4 solution = 2 mol / L
now
moles of H2SO4 = 0.01 L x 2 mol / L = 0.02 mol
now
H2SO4 + 2 NaOH ---> Na2SO4 + 2 H2O
so
moles of NaOH required = 0.02 mol H2SO4 x ( 2 mol NaOH / 1 mol H2SO4)
moles of NaOH required = 0.04 mol
now
volume of NaOH solution = 0.04 mol / (0.5 mol/L)
volume of NaOH solution = 0.08 L
volume of NaOH solution = 0.08 L x 1000 ml / 1 L = 80 ml
so
80 ml of NaOH is required