Trigonometry

767 views

Published on

This video is about the Trigonometric Values present in Mt. Banahaw

Published in: Education
0 Comments
0 Likes
Statistics
Notes
  • Be the first to comment

  • Be the first to like this

No Downloads
Views
Total views
767
On SlideShare
0
From Embeds
0
Number of Embeds
119
Actions
Shares
0
Downloads
12
Comments
0
Likes
0
Embeds 0
No embeds

No notes for slide

Trigonometry

  1. 1. TRIGONOMETRYGEOGRAPHICAL SETTING OFMT. BANAHAWGroup 4-SJEPada NoconMijares LaygoPasiliao Sityar
  2. 2. Starting Point
  3. 3. Kalbaryo Base Camp
  4. 4. • We started at the Ciudad de Misticade Dios 45• Then we walked 30 mins. uptowards the base camp• Then we trekked up at the Kalbaryo 2158 ft• According to Wikimapia, theelevation of the mountain is at 2158 45ft.• By the direction of our trek, we cansee a 90-degree angle which canform a right triangle• A 45 by 45 triangle is formed basedfrom the direction of the trek
  5. 5. 2158 ft 4545
  6. 6. Kalbaryo Base Camp
  7. 7. • We went down the Kalbaryo, thenfrom the base camp, we went towards 45Ilog Lagnos.•From the direction of the trek 2158 ftdownward, we can form anothertriangle with angle of 15 x 30 degrees•From the illustration, we have already 45formed the 30 x 60 triangle
  8. 8. 2158 ft 4545
  9. 9. • Then we went down towards IlogLagnos which is 158 ft below 45• From the directions given, wecan say the we can form another 2158 ft45 x 45 triangle. 45
  10. 10. 2158 ft 4545
  11. 11. y g• Now, we have to solve for themissing values of the triangles 45• Solutions for sides A,B,X,Y,Z X 2158 ft Z f 45 k B Y 158 ft A
  12. 12. SOLUTION FOR SIDE AGiven:158 ft (Side D)45-degree angle (Angle d)Find: Side Asin d= D/Asin 45= 158/AA= 158/sin45A~~223.44 ft
  13. 13. SOLUTION FOR SIDE BGiven:158 ft (Side D)45 degrees (Angle d)Find: Side Btan d= D/BTan 45= 158 ft/BB= 158 ft/tan 45B= 158 ft
  14. 14. SOLUTION FOR SIDE YGiven:2000 ft45 degrees (angle k)Find: Side YSolution:Tan k= K/YTan 45= 2000/YY=2000/tan 45Y= 2000 ft
  15. 15. SOLUTION FOR SIDE ZGiven:2000 ft45 degrees (angle k)Find: Side ZSolution:Sin k= K/ZSin 45= 2000/ZZ= 2000/sin 45Z~~2828.42 ft
  16. 16. SOLUTION FOR SIDE XGiven:2000 ft30 degreesFind= Side XSin f= K/XSin 30= 2000/XX= 2000/sin 30X= 4000 ft
  17. 17. y g• The values of the sides are:•A= 223 ft 45 15•B= 158 ft 4000 ft•X= 4000 ft•Y= 2000 ft 2828 ft•Z= 2828 ft 2158 ft f 158 ft 45 k 2000 ft 158 ft 223 ft

×