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# Simplest Formula01a

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### Simplest Formula01a

1. 1. Simplest Formula <br />Prepared by: Stephen Boylan<br />October 20, 2009 <br />
2. 2. Simplest Formula .<br />.<br />.<br />
3. 3. Simplest Formula - Simple001<br />A. Combustion in Excess oxygen <br />12.795 g. HC ----&gt; 32.689 g. CO2 + 13.377 g. H2O<br />B. 5 Step Calculation <br />C. The Simplest Formula<br />.CxHy Oz<br />
4. 4. Molar Mass CO2 <br />Element Number Atomic Mass Formula<br /> n Units, amu Mass, <br /> C 1 12.01 12.01<br /> O 2 16.00 32.00<br /> 44.01grams per mole CO2<br />
5. 5. Molar Mass H2O<br /> <br />Element Number Atomic Mass Formula<br /> n Units, amu Mass, n(amu)<br /> H 2 1.008 2.016<br /> <br /> O 1 16.00 16.00<br /> 18.02 grams per<br /> mole H2O<br /> <br />
6. 6.  <br />2.0 Calculate the grams of carbon, hydrogen and oxygen.<br /> <br />12.795g. HC --&gt; 32.689 g CO2 + 13.377 g. H2O<br />C:<br />32.689 grams CO2 12.01 grams C = 8.921 g. C<br /> 44.01 grams CO2<br />H:<br />13.377 grams H2O 2x1.008 grams H = 1.497 g H<br /> 18.02 grams H2O<br />O:<br />12.795 g HC - 8.921g C - 1.497 g H= 2.377 g O<br /> <br />
7. 7. Moles of carbon, hydrogen and oxygen.<br /> <br />C: 8.921 g. C 1 mole C = 0.7429 moles C<br /> 12.01 grams C <br /> <br />H: 1.497 g. H 1 mole H = 1.485 mole H<br /> 1.008 grams H<br /> <br /> <br />O: 2.377 g. O 1 mole O = 0.1485 mole O<br /> 16.00 grams O <br />
8. 8. Ratios Divide by smallest<br /> <br />C: 0.7429 moles C 1 = 5.003 ~ 5 moles C <br /> 0.1485<br />H: 1.485 mole H 1 = 10 moles H <br /> 0.1485<br />O: 0.1485 mole O 1 = 1 moles O <br /> 0.1485<br /> <br />
9. 9. C5 H10 O1<br />
10. 10.  <br />The End <br />