2.0 Diode Applications 1 of 312.1 Introduction2.2 Load-Line Analysis
2.0 Diode Applications 2 of 31Drawing the load line and finding the point of operation.Drawing the load line.1) Redraw the circuit with the diode on the right.2) Remove the diode and find a couple of points on the curve of VD vs. ID. Convenient points are, the current when VD = 0 and the voltage when ID = 0.Draw the line connecting these two points and note the voltage on the horizontal axis.Note the intersection point. VD VR
2.0 Diode Applications 3 of 31Example 2.1VD = 0.7
2.0 Diode Applications 4 of 312.3 Diode ApproximationsSeries Diode Configurations with DC Inputs(a) Circuit; (b) characteristics Silicon 0.7 Germanium 0.3Series Diode Configurations.Circuit for Example 2.11.
2.0 Diode Applications 5 of 312.5 Parallel and Series-Parallel ConfiguationsTwo diodes sharing the load current.
2.0 Diode Applications 6 of 31Network for Example 2.15.
2.0 Diode Applications 7 of 312.6 AND/OR GatesOR gate
2.0 Diode Applications 9 of 312.7 Sinusoidal Inputs: Half-Wave RectificationConduction region (0→T/2).
2.0 Diode Applications 10 of 31Average voltage outputVavg ≈ 0.318(Vm - VT )Effect of VT on half-wave rectified signal.Silicon diode, VT = 0.7Vavg ≈ 0.318(Vm - VT )
2.0 Diode Applications 11 of 312.8 Full-Wave Recification
2.0 Diode Applications 12 of 31Conduction path for the positive region of vi.Conduction path for the negative region of vi.Input and output waveforms for a full-wave rectifier.Vavg ≈ 0.636Vm Vavg ≈ 0.636(Vm - VT )
2.0 Diode Applications 13 of 31Center-tapped transformer full-wave rectifier.Network conditions for the positive region of vi.
2.0 Diode Applications 14 of 31Network conditions for the negative region of vi.
2.0 Diode Applications 15 of 31Bridge network for Example 2.19.
2.0 Diode Applications 16 of 31Network of Fig. 2-65 for the positive region of vi.
2.0 Diode Applications 17 of 31Redrawn network of Fig. 2-66.
2.0 Diode Applications 27 of 31 The output voltage across the Zener is Vz. The minimum value of R Lmin is given by the equation, RLmin Vz Vi. R RLmin R RLmin Vz. Vi Vz Now to find the maximum value of RL. As the value of RL is increased the current through the Zener is increased. Izm IR IRLmin Vz IRLmin RLmax Vz Izm IR RLmax Vz RLmax IR Izm Vz RLmax Vi Vz Izm R