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SolPowerPeople #SolarMOOC final inter-row shading solution..

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- 1. Final Trig Problem Solution? SolPowerPeople, Inc. Austin, TX March 10, 2012
- 2. Last Trig Problem
- 3. 24”? 20°
- 4. opposite sin(q )° = 24” hypotenuse opposite sin(20)° =? 24" 20° opposite .342 = 24" 24 *.342 = opposite 8.2" = opposite
- 5. opposite sin(q )° = 24” hypotenuse opposite sin(20)° =8.2” 24" 20° opposite .342 = 24" 24 *.342 = opposite 8.2" = opposite
- 6. Last Trig Problem
- 7. Angle of a 4/12 roof Tangent of the angle is equal to the4/12=rise/run opposite over the hypotenuse. Therefore 4/12 = tangent of the angle 4” 4/12= 0.3333333 12” Arctan of 0.333333= 18.4° (see earlier slideshow on “arctan”)
- 8. 6° 8.2” 18.4°
- 9. 6° 8.2” bring up byBringdown to roof pitchzero° amount 18.4°
- 10. 8.2” 24.4°(18.4° + 6°)
- 11. 8.2”24.4° ?
- 12. oppositetan(q )° = adjacent 8.2"tan(24.4)° = adjacent 8.2".4536 = adjacent 8.2"adjacent = .4536adjacent = 18.077" 8.2” 24.4° 18.077”
- 13. adjacentcos(q )° = hypotenuse adjacentcos(53)° = 18.077" ? adjacent 53° 18.077”.6018 = 18.707"18.077 *.6018 = adjacentadjacent = 10.87"
- 14. adjacentcos(q )° = hypotenuse adjacentcos(53)° = 18.077" 10.87” adjacent 53° 18.077”.6018 = 18.707"18.077 *.6018 = adjacentadjacent = 10.87"

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