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10 7 circles - segments

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10 7 circles - segments

1. 1. CIRCLES AND SEGMENT MEASUREMENT Jim Smith JCHS Section 10-7
2. 2. COPY THESE NOTES AND DRAW THE DIAGRAMS. USE THESE AND THE PRACTICE PROBLEMS AT THE END AS EXAMPLES FOR THE CLASS ASSIGNMENT
3. 3. THE PRODUCT OF THE PARTS OF ONE CHORD = THE PRODUCT OF THE PARTS OF THE OTHER CHORD ab = cd a b c d
4. 4. 7x = 20 7x= 20 7 7 X = 2.86 7x = 4(5) 7 x 4 5
5. 5. . 6 x 4 (6+x) (6-x) = 4∙4 36-x²=16 36-x²-36 = 16-36 -x²= -20 -x²/-1 = -20/-1 x² = 20 √ x² = √20 X = 4.47 FOIL Radius = 6, so one part= 6+x and the other part= 6-x The diameter is perpendicular to the chord, so it bisects the chord
6. 6. The outside part of segment AB x the whole segment AB = the outside part of segment CB x the whole segment CB A B C Whole segment Outside part
7. 7. 5 7 15 x Outside x Whole = Outside x Whole 5x+25 = 7(22) 5x+25 = 154 5x = 129 X = 25.8 5( x+5 ) = 7( 15+7 ) little+little = big
8. 8. x 4 9 Outside x Whole = Outside x Whole x∙x = 4∙9 We know the whole so we don’t need to add the little parts x² = 36 √ x² = √36 X = 6 Tangent (the outside is also the whole)
9. 9. TRY THESE 8 5 7 X 3 X 5 14 1 2
10. 10. 1) 7X = 8(5) 7X = 40 X = 40/7 X = 5.71 2) 3(X+3) = 5(14) 3X+9 = 70 3X+9-9 = 70-9 3X = 61 X = 61/3 X = 20.33 Answers