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To prepare a pH 3.15 buffer from an acid/base pair with a pKa of 3.15, the A -
/HA ratio must be
1. which of the following would produce this ratio
a. 2 mol HA and 2 mol A -
b. adding 0.5 mol HCL to 1 mol A -
c. Adding 1 mol NaOH to 2 mol HA
d. All of the above
The answer is D but can someone please explain!
Solution
pH = pKa
if [A -
] = [HA]
[A -
] / [HA] = 1.0
so pH = pKa = 3.15
a) moles of HA = moles of A -
so [A -
] / [HA] = 1.0
b) if we add 0.5 moles HCl
A -
+ HCl --------> HA + Cl -
50% A -
becomes HA
so HA = A -
[A -
] /[HA] = 1.0
c) HA + NaOH --------> NaA + H2O
1 mole NaOH reacts with 1 mole HA
so 1 mole NaA -
will form
1 mole HA will be left over
so HA =A -
[A -
] / [HA] = 1.0
so alll options are correct only.

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To prepare a pH 3-15 buffer from an acid-base pair with a pKa of 3-15-.docx

  • 1. To prepare a pH 3.15 buffer from an acid/base pair with a pKa of 3.15, the A - /HA ratio must be 1. which of the following would produce this ratio a. 2 mol HA and 2 mol A - b. adding 0.5 mol HCL to 1 mol A - c. Adding 1 mol NaOH to 2 mol HA d. All of the above The answer is D but can someone please explain! Solution pH = pKa if [A - ] = [HA] [A - ] / [HA] = 1.0 so pH = pKa = 3.15 a) moles of HA = moles of A - so [A - ] / [HA] = 1.0 b) if we add 0.5 moles HCl A - + HCl --------> HA + Cl - 50% A - becomes HA so HA = A - [A - ] /[HA] = 1.0
  • 2. c) HA + NaOH --------> NaA + H2O 1 mole NaOH reacts with 1 mole HA so 1 mole NaA - will form 1 mole HA will be left over so HA =A - [A - ] / [HA] = 1.0 so alll options are correct only.