Controller Modes
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ON-OFF controller/two position controller
Three-position controller
Proportional Action Control
Integral/Reset Action Control
Derivative/Rate Action Control
P+I Control
P+D Control
P+I+D Control
ON-OFF Control
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Discontinuous control mode
Also called two-position control
The simplest form of control
It is very commonly used in industry
The manipulated variable is quickly changed to
either a maximum or a minimum value
• The minimum value of the manipulated variable
is usually zero (off)
• Transmit only two output signals: ON (100%), OFF
(0%)
• Only responds when it’s above or below the
setpoint
ON-OFF Controller
• Example :
Process : Water tank of 10 litres
Target: Reach + maintain a temperature of
o
90 C.

Water : 10 Litres

Heater

Sensor
Two-positions controller with hysteresis
ON-OFF Controller made from Op- amps

Vin reaches VH  Comparator ON state(V0)
Vin falls below a value VL  Comparator OFF
state (0)

The HIGH (ON) or V1=Vsp switch
voltage is
VH = Vsp

Vsp = Setpoint voltage

The LOW (OFF) switch voltage is
VL = Vsp – R1/R2 V0
Vout

(ON) V0

(OFF)

0

VL

VH

Vin
Example:
Level measurement in a sump tank is provided
by a transducer scaled as 0.2 V/m. A pump is to
be turned on by application of +5V when the
sump level exceeds 2.0m. The pump is to be
turned back off when the sump level drops to
1.5m. Find R2 if R1 is given 5kΩ
Three-Position Controller made from Op- amps
• In this circuit assumed:
The output of the comparators is 0V for the
OFF state
Vo volts for the ON state
• The summing amplifier includes a bias voltage
input VB which allows the three-position
mode response to be biased up or down in
voltage to suit particular needs.
• The inverter is to convert the sign of the
inverting action of the summing amplifier
• Equation presented the generic three-mode
controller response:
Vin < Vsp1
Vout = VB
Vsp1 < Vin < Vsp2 Vout = VB + R3/R1 Vo
Vin > Vsp2
Vout = VB + R3/R1 Vo + R3/R2 Vo
Response of the three-position controller with the bias
equal to zero
Example:
The level in a sump tank is to be controlled with a
three-position controller. The following
specifications are given:
1. The level measurement sensor has a transfer
function of 0.45 V/m
2. The valve is linearly driven from fully open to
fully closed by a voltage from 0 to 8V
3. The following specifications are given:
level < 2m
valve 20% open
level > 2m < 3m
valve 65% open
level > 3m
valve 100% open
Comparators are available that have outputs of
0 V for OFF and 5V for ON. Design a three
position op amp controller. R3 is given by 10kΩ
Proportional Controller (P Mode)
• Continuous control mode
• Typical behavior/characteristics:
 The signal output of a controller is proportional to

the input or error
 Stay at the same ratio

• Proportional control is a pure gain adjustment
acting on the error signal to provide the driving
input to the process.
• Implementation of this mode requires a circuit
which has a response given by

Where: U =controller output (0 100%)
K = Proportional gain (controller transfer function)
PB = proportional band in percentage
Ep = error in percent of variable range
Pp = controller output with no error (bias)
Example:
A proportional controller has the scale 0-10 volts
corresponds to a 0-100% output. If R2 = 10 KΩ,
and full scale error is 10 volt, find the value of V0
and R1 to support a 20% proportional band about
a 50% zero-error controller output.
Advantages:
 Simple
 Easiest of the continuous controllers tune
 Provides good stability, rapid response and
relatively stable.

Disadvantages:
 Only control results in offset – Never reaches SP
 Action is instantaneous – As soon as error is
produced, control action is taken.
 Used to stabilize unstable output
Integral Action Control
• Also called Reset Action Control
• Continuous control mode
• Typical behavior/characteristic:
- The controller output is proportional to the
integral of the error with respect to time
- The value of the controller output is changed
at a rate proportional to the error “e”
• Used to removed offset
• As long as error exist, integral action will work
to eliminate the error
Integral control is implemented through the
introduction of an integrator. Implementation of this
mode requires a circuit which has a response given by
Example:
• Suppose that V(0)=0 for an integral controller.
• It is required that the controller output should
saturate 15 seconds after a constant 5% error
is applied.
• The input range is 0-5 volts and the output
range is 0-10 volts. Calculate the integration
gain and the suitable values of R and C.
Assume C=50μF
Derivative Control
• Also called Rate Control Action
• Continuous control mode
• Typical behavior/characteristic:
- The controller output is proportional to the rate
of the error (time derivative)
• Faster/quick response compared to P
• Can cause the damage to the FCE because of too
fast rate of change of the error
• Can amplify the noise in the system
• Cannot compensating the system error: e = w-x=0
• The derivative mode is never used alone
because it cannot provide a controller output
when the error is zero.
• Implementation of this mode requires a circuit
which has a response given by
The value of R1 is selected so that the circuit will be
stable for high frequencies by setting
where f is the frequency in Hz.
Summary
Remark: Each mode has its advantages and drawbacks
individually
• P mode Advantage: Fast response action
• Drawback: Produces steady state error (offset)
• I mode Advantage: Steady state error is null
• Drawback: Increases the response time
• D Mode Advantage: increases the damping of the system
• Drawback: Amplifies the noise which can cause problems
including instability
• Therefore, the pure controller mode (P or I or D) is seldom
used in process control because of the advantage of
composite modes in providing good control.
Composite Controller
Proportional- Integral Control (PI Mode)
This controller can:
 eliminate an offset due to integral action
 the system response is slow due to lag introduced = -90o
 better dynamic response than integral alone
 I action repeats P action in Ti seconds
 the slope depends on Ti
Kp

Ki

Parallel controller - Mathematical

Gp
Gp

100/PB
1/Ti

Series controller - Practical
I
t

Ti – Time for integral action
after the proportional
action

I
t
I

P+I

t
Example:
PI controller has a proportional band of 30% and an
integration time =10 seconds. The 4-20mA input volts
converts to a 0.4-2 volt error signal and the controller
output range is 0-10 volts.Calculate values of Kp, KI,
R1, and R2. C is given by 10μF
Proportional-Derivative Control (PD Mode)

This controller can:
 experience the offset but less than proportional only
 the system response is faster due to lead introduced = -90o
 better dynamic response than integral alone
 I action repeats P action in Ti seconds
 the slope depends on Ti
Proportional-Derivative Control (PD Mode)
Three term Controller (PID Mode)
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller
PID Controller

PID Controller

  • 1.
    Controller Modes 1. 2. 3. 4. 5. 6. 7. 8. ON-OFF controller/twoposition controller Three-position controller Proportional Action Control Integral/Reset Action Control Derivative/Rate Action Control P+I Control P+D Control P+I+D Control
  • 2.
    ON-OFF Control • • • • • Discontinuous controlmode Also called two-position control The simplest form of control It is very commonly used in industry The manipulated variable is quickly changed to either a maximum or a minimum value • The minimum value of the manipulated variable is usually zero (off) • Transmit only two output signals: ON (100%), OFF (0%) • Only responds when it’s above or below the setpoint
  • 3.
    ON-OFF Controller • Example: Process : Water tank of 10 litres Target: Reach + maintain a temperature of o 90 C. Water : 10 Litres Heater Sensor
  • 10.
  • 11.
    ON-OFF Controller madefrom Op- amps Vin reaches VH  Comparator ON state(V0) Vin falls below a value VL  Comparator OFF state (0) The HIGH (ON) or V1=Vsp switch voltage is VH = Vsp Vsp = Setpoint voltage The LOW (OFF) switch voltage is VL = Vsp – R1/R2 V0
  • 12.
  • 13.
    Example: Level measurement ina sump tank is provided by a transducer scaled as 0.2 V/m. A pump is to be turned on by application of +5V when the sump level exceeds 2.0m. The pump is to be turned back off when the sump level drops to 1.5m. Find R2 if R1 is given 5kΩ
  • 14.
  • 15.
    • In thiscircuit assumed: The output of the comparators is 0V for the OFF state Vo volts for the ON state • The summing amplifier includes a bias voltage input VB which allows the three-position mode response to be biased up or down in voltage to suit particular needs. • The inverter is to convert the sign of the inverting action of the summing amplifier
  • 16.
    • Equation presentedthe generic three-mode controller response: Vin < Vsp1 Vout = VB Vsp1 < Vin < Vsp2 Vout = VB + R3/R1 Vo Vin > Vsp2 Vout = VB + R3/R1 Vo + R3/R2 Vo
  • 17.
    Response of thethree-position controller with the bias equal to zero
  • 18.
    Example: The level ina sump tank is to be controlled with a three-position controller. The following specifications are given: 1. The level measurement sensor has a transfer function of 0.45 V/m 2. The valve is linearly driven from fully open to fully closed by a voltage from 0 to 8V 3. The following specifications are given: level < 2m valve 20% open level > 2m < 3m valve 65% open level > 3m valve 100% open
  • 19.
    Comparators are availablethat have outputs of 0 V for OFF and 5V for ON. Design a three position op amp controller. R3 is given by 10kΩ
  • 20.
    Proportional Controller (PMode) • Continuous control mode • Typical behavior/characteristics:  The signal output of a controller is proportional to the input or error  Stay at the same ratio • Proportional control is a pure gain adjustment acting on the error signal to provide the driving input to the process.
  • 21.
    • Implementation ofthis mode requires a circuit which has a response given by Where: U =controller output (0 100%) K = Proportional gain (controller transfer function) PB = proportional band in percentage Ep = error in percent of variable range Pp = controller output with no error (bias)
  • 23.
    Example: A proportional controllerhas the scale 0-10 volts corresponds to a 0-100% output. If R2 = 10 KΩ, and full scale error is 10 volt, find the value of V0 and R1 to support a 20% proportional band about a 50% zero-error controller output.
  • 24.
    Advantages:  Simple  Easiestof the continuous controllers tune  Provides good stability, rapid response and relatively stable. Disadvantages:  Only control results in offset – Never reaches SP  Action is instantaneous – As soon as error is produced, control action is taken.  Used to stabilize unstable output
  • 25.
    Integral Action Control •Also called Reset Action Control • Continuous control mode • Typical behavior/characteristic: - The controller output is proportional to the integral of the error with respect to time - The value of the controller output is changed at a rate proportional to the error “e” • Used to removed offset • As long as error exist, integral action will work to eliminate the error
  • 26.
    Integral control isimplemented through the introduction of an integrator. Implementation of this mode requires a circuit which has a response given by
  • 28.
    Example: • Suppose thatV(0)=0 for an integral controller. • It is required that the controller output should saturate 15 seconds after a constant 5% error is applied. • The input range is 0-5 volts and the output range is 0-10 volts. Calculate the integration gain and the suitable values of R and C. Assume C=50μF
  • 29.
    Derivative Control • Alsocalled Rate Control Action • Continuous control mode • Typical behavior/characteristic: - The controller output is proportional to the rate of the error (time derivative) • Faster/quick response compared to P • Can cause the damage to the FCE because of too fast rate of change of the error • Can amplify the noise in the system • Cannot compensating the system error: e = w-x=0
  • 30.
    • The derivativemode is never used alone because it cannot provide a controller output when the error is zero. • Implementation of this mode requires a circuit which has a response given by
  • 31.
    The value ofR1 is selected so that the circuit will be stable for high frequencies by setting where f is the frequency in Hz.
  • 32.
    Summary Remark: Each modehas its advantages and drawbacks individually • P mode Advantage: Fast response action • Drawback: Produces steady state error (offset) • I mode Advantage: Steady state error is null • Drawback: Increases the response time • D Mode Advantage: increases the damping of the system • Drawback: Amplifies the noise which can cause problems including instability • Therefore, the pure controller mode (P or I or D) is seldom used in process control because of the advantage of composite modes in providing good control.
  • 33.
    Composite Controller Proportional- IntegralControl (PI Mode) This controller can:  eliminate an offset due to integral action  the system response is slow due to lag introduced = -90o  better dynamic response than integral alone  I action repeats P action in Ti seconds  the slope depends on Ti Kp Ki Parallel controller - Mathematical Gp
  • 34.
    Gp 100/PB 1/Ti Series controller -Practical I t Ti – Time for integral action after the proportional action I t I P+I t
  • 36.
    Example: PI controller hasa proportional band of 30% and an integration time =10 seconds. The 4-20mA input volts converts to a 0.4-2 volt error signal and the controller output range is 0-10 volts.Calculate values of Kp, KI, R1, and R2. C is given by 10μF
  • 37.
    Proportional-Derivative Control (PDMode) This controller can:  experience the offset but less than proportional only  the system response is faster due to lead introduced = -90o  better dynamic response than integral alone  I action repeats P action in Ti seconds  the slope depends on Ti
  • 38.
  • 40.