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PLOT THE
FOLLOWING POINTS
(𝟎,𝟎)
(𝟏,𝟎)
(𝟎,𝟏)
(βˆ’πŸ,πŸ’)
(πŸ’,βˆ’πŸ)
(πŸ“,πŸ–)
(πŸ‘,πŸ•)
(βˆ’πŸ‘,βˆ’πŸ•)
(πŸ”,𝟎)
Solves
Quadratic
Inequalities
(Two Variables)
Learning Objectives
At the end of the lesson, the learners should be
able to:
β€’ Identify the boundary graph of a quadratic
inequality in two variables.
β€’ Represent the solution region of quadratic
inequalities on the coordinate plane.
β€’ Interpret the shaded region and
determine whether given points satisfy the
inequality.
There are quadratic inequalities that involve
two variables. These inequalities can be
written in any of the following forms.
𝑦 >π‘Žπ‘₯2
+𝑏π‘₯+𝑐
𝑦 <π‘Žπ‘₯2
+𝑏π‘₯+𝑐
𝑦 β‰₯ π‘Žπ‘₯2
+𝑏π‘₯+𝑐
𝑦 ≀ π‘Žπ‘₯2
+𝑏π‘₯+𝑐
where are real numbers and
EXAMPLES
𝑦 >2π‘₯2
βˆ’ 5 π‘₯+1
𝑦 <π‘₯2
+3 π‘₯ +2
𝑦 + 9 β‰₯ βˆ’ 4 π‘₯2
𝑦 βˆ’7 π‘₯ ≀ 2 π‘₯2
The solution set of quadratic inequalities
in two variables can be determined
graphically.
To do this, write the inequality as an
function, then show the graph. The graph
of the resulting parabola will be used to
graph the inequality.
REMEMBER THIS!
EXAMPLE
Example 1: Find the solution set of
Solution:
Write the inequality to its corresponding equation
Construct table of values for
-5 -4 -3 -2 -1 0 1 2
12 6 2 0 0 2 6 12
Use these points to graph a
parabola.
(𝟎,πŸ–)
πŸ–<𝟐FALSE
(𝟎,𝟎)
𝟎<𝟐TRUE
(βˆ’πŸ,βˆ’πŸ‘)
βˆ’πŸ‘<πŸ”βˆ’ πŸ”
βˆ’πŸ‘<πŸ’βˆ’πŸ”+𝟐
βˆ’πŸ‘< 𝟎
TRUE
(βˆ’πŸ”,πŸ•)
βˆ’πŸ”<πŸ•πŸTRUE
The shaded
region are the
solution set
EXAMPLE
Example 2: Find the solution set of
Solution:
Write the inequality to its corresponding equation
𝐲 β‰₯𝟐 π’™πŸ
βˆ’πŸ‘ 𝒙 +𝟏 𝐲=𝟐 π’™πŸ
βˆ’πŸ‘ 𝒙 +𝟏
Construct table of values for
-3 -2 -1 0 1 2 3 4
28 15 6 1 0 3 10 21
Use these points to graph a
parabola. 𝐲 β‰₯ 𝟐 π’™πŸ
βˆ’πŸ‘ 𝒙 +𝟏
(𝟏,πŸ‘)
πŸ‘β‰₯ πŸβˆ’ πŸ‘+𝟏
FALSE
(βˆ’πŸ’ ,πŸ”)
(πŸ”,πŸ”)
TRUE
(βˆ’πŸ‘,βˆ’πŸ)
πŸ‘β‰₯ πŸ‘βˆ’πŸ‘
πŸ‘ β‰₯ 𝟎
πŸ”β‰₯𝟐(πŸ‘πŸ”)βˆ’πŸπŸ–+𝟏
πŸ”β‰₯πŸ•πŸβˆ’πŸπŸ–+𝟏
πŸ” β‰₯ πŸ“πŸ“
FALSE
πŸ”β‰₯𝟐(πŸπŸ”)+𝟏𝟐+𝟏
πŸ”β‰₯πŸ‘πŸ+𝟏𝟐+𝟏
πŸ” β‰₯ πŸ’πŸ“
FALSE
βˆ’πŸβ‰₯ 𝟐(𝟏)+πŸ‘+𝟏
βˆ’πŸ β‰₯ 𝟐+πŸ‘+𝟏
βˆ’πŸ β‰₯ πŸ”
Use these points to graph a
parabola. 𝐲 β‰₯ 𝟐 π’™πŸ
βˆ’πŸ‘ 𝒙 +𝟏
The shaded
region are the
solution set
1. Find the solution set of then graph.
YOUR TURN!
2. Determine whether or not each of the
following points is a solution of the inequality .
Justify your answer.
THANK YOU!