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![Δ3. Να λύσετε την εξίσωση:
5 3 5 3
g (x) g (x) g(x) (x 1) (x 1) (x 1)+ + = + + + + + στο [ ]g 1,1Α = − :
ΜΟΝΑΔΕΣ 4
Δ4. Αν ...](https://image.slidesharecdn.com/prosomoiosiglukeiou2019-sourmpis-kousteris-190520201532/75/2019-5-2048.jpg?cb=1666180503)
![Δ2.
( )
2 0 2
1 1 2
λΒ∆
−
= =
− −
άρα ( )0 1 1y x y x− = + ⇔ = +
Θεωρώ ( ) ( ) 1x g x xϕ = − −
H φ συνεχής στο [ ]1,1−
( )...](https://image.slidesharecdn.com/prosomoiosiglukeiou2019-sourmpis-kousteris-190520201532/75/2019-8-2048.jpg?cb=1666180503)