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The dimensions of the culvert are calculated to be 3 m x 2 m based on trying different cross-sectional areas. The total head loss is calculated using the given discharge of 3 m3/s, upstream velocity of 1 m/s, and downstream velocity of 0.5 m/s. A cross-section of 3 m x 2 m results in a head loss of 0.45 m, which is less than the maximum allowed head rise of 0.5 m. Sketches are provided showing the elevation of the total head and pressure lines.

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Cu06997 lecture 6_exercises

- The document contains examples of calculating head loss and pressure differences in pipes due to changes in diameter or flow rate.
- In example 1, the slope of a pipe needed to be calculated to maintain equilibrium based on a given flow rate, diameter, and friction coefficient.
- Example 2 involves calculating the head loss and pressure difference across a sudden enlargement in pipe diameter.
- Example 3 is similar but calculates values for a sudden contraction in pipe diameter.

Cu06997 lecture 4_answer

1. The flow between points P1 and P2 is steady, non-uniform flow since the water depth changes along the length of the ditch but the discharge is constant.
2. Comparing the total head at P1 and P2 using Bernoulli's equation with an energy loss term shows that there is a 0.3 m energy loss between the two points over a 1500 m length of ditch.
3. The flow is classified as one-dimensional flow since the width and depth of flow are much smaller than the length between P1 and P2.

Cu06997 lecture 4_bernoulli-17-2-2013

The document discusses principles of fluid dynamics including the application of conservation laws and the energy equation to fluid flows. It covers topics such as Bernoulli's equation, velocity and pressure measurement techniques like Pitot tubes, flow through orifices, open channels, and pipes with head losses. Formulas are presented for flow rate calculation using concepts like velocity head, pressure head, and total head.

Cu06997 lecture 3_principles_of_flow-17-2-2013

This document provides an overview of fluid dynamics principles including:
1. It classifies flows as steady or unsteady, uniform or non-uniform based on changes over time and distance.
2. It describes fundamental equations like conservation of mass, energy, and momentum. Bernoulli's equation relates pressure, velocity, and elevation.
3. It gives examples of applying these principles like calculating pressure differences in pipes using Bernoulli's equation and assuming no energy losses.

Cu06997 lecture 6_flow in pipes 1_2013

This document discusses fluid dynamics concepts related to pipe flow, including laminar and turbulent flow. It covers fundamental concepts such as Reynolds number, laminar flow equations for frictional head loss and wall shear stress. Turbulent flow equations are presented for head loss, Darcy-Weisbach, and Colebrook-White transition formula. Local head losses are discussed for sudden pipe enlargement and contraction.

Cu06997 lecture 2_hydrostatics_17-2-2013

Here are the steps to solve this problem using Pascal's law:
1) Wall AB and CD are both vertical surfaces with an area of 2.44 m x 5 m = 12.2 m^2
Pressure at the bottom is due to a water column of 5 m
Pressure = Density x Gravity x Height = 1000 x 10 x 5 = 50,000 N/m^2
Force on wall AB/CD = Pressure x Area = 50,000 x 12.2 = 610,000 N
2) Bottom BC is a horizontal surface with an area of 2.44 x 5 = 12.2 m^2
Pressure due to water above it is the pressure at the bottom = 50,

Cu06997 lecture 7_culvert_2013

This document discusses fluid dynamics concepts related to flow in pipes and closed conduits including turbulent flow, local head losses, and partially full pipes. It then provides equations and explanations for calculating head losses and discharge in culverts under various conditions: with and without upstream/downstream velocities, for submerged culverts, and examples of calculating discharge given water level changes and culvert dimensions. Formulas are given for inlet, friction, and outlet losses as well as calculating total head loss, discharge coefficients, and drawing head and water level lines.

Cu06997 computation lecture3

The document calculates the difference in pressure between two points in a pipe with different diameters but constant flow rate, assuming no energy loss. It shows that with a diameter of 0.15m the pressure is 3.14m and with a diameter of 0.3m the pressure is 0.2m, giving a pressure difference of 2.94m. It then repeats the calculation with the diameters reversed, giving a pressure difference of -2.94m.

Cu06997 lecture 6_exercises

- The document contains examples of calculating head loss and pressure differences in pipes due to changes in diameter or flow rate.
- In example 1, the slope of a pipe needed to be calculated to maintain equilibrium based on a given flow rate, diameter, and friction coefficient.
- Example 2 involves calculating the head loss and pressure difference across a sudden enlargement in pipe diameter.
- Example 3 is similar but calculates values for a sudden contraction in pipe diameter.

Cu06997 lecture 4_answer

1. The flow between points P1 and P2 is steady, non-uniform flow since the water depth changes along the length of the ditch but the discharge is constant.
2. Comparing the total head at P1 and P2 using Bernoulli's equation with an energy loss term shows that there is a 0.3 m energy loss between the two points over a 1500 m length of ditch.
3. The flow is classified as one-dimensional flow since the width and depth of flow are much smaller than the length between P1 and P2.

Cu06997 lecture 4_bernoulli-17-2-2013

The document discusses principles of fluid dynamics including the application of conservation laws and the energy equation to fluid flows. It covers topics such as Bernoulli's equation, velocity and pressure measurement techniques like Pitot tubes, flow through orifices, open channels, and pipes with head losses. Formulas are presented for flow rate calculation using concepts like velocity head, pressure head, and total head.

Cu06997 lecture 3_principles_of_flow-17-2-2013

This document provides an overview of fluid dynamics principles including:
1. It classifies flows as steady or unsteady, uniform or non-uniform based on changes over time and distance.
2. It describes fundamental equations like conservation of mass, energy, and momentum. Bernoulli's equation relates pressure, velocity, and elevation.
3. It gives examples of applying these principles like calculating pressure differences in pipes using Bernoulli's equation and assuming no energy losses.

Cu06997 lecture 6_flow in pipes 1_2013

This document discusses fluid dynamics concepts related to pipe flow, including laminar and turbulent flow. It covers fundamental concepts such as Reynolds number, laminar flow equations for frictional head loss and wall shear stress. Turbulent flow equations are presented for head loss, Darcy-Weisbach, and Colebrook-White transition formula. Local head losses are discussed for sudden pipe enlargement and contraction.

Cu06997 lecture 2_hydrostatics_17-2-2013

Here are the steps to solve this problem using Pascal's law:
1) Wall AB and CD are both vertical surfaces with an area of 2.44 m x 5 m = 12.2 m^2
Pressure at the bottom is due to a water column of 5 m
Pressure = Density x Gravity x Height = 1000 x 10 x 5 = 50,000 N/m^2
Force on wall AB/CD = Pressure x Area = 50,000 x 12.2 = 610,000 N
2) Bottom BC is a horizontal surface with an area of 2.44 x 5 = 12.2 m^2
Pressure due to water above it is the pressure at the bottom = 50,

Cu06997 lecture 7_culvert_2013

This document discusses fluid dynamics concepts related to flow in pipes and closed conduits including turbulent flow, local head losses, and partially full pipes. It then provides equations and explanations for calculating head losses and discharge in culverts under various conditions: with and without upstream/downstream velocities, for submerged culverts, and examples of calculating discharge given water level changes and culvert dimensions. Formulas are given for inlet, friction, and outlet losses as well as calculating total head loss, discharge coefficients, and drawing head and water level lines.

Cu06997 computation lecture3

The document calculates the difference in pressure between two points in a pipe with different diameters but constant flow rate, assuming no energy loss. It shows that with a diameter of 0.15m the pressure is 3.14m and with a diameter of 0.3m the pressure is 0.2m, giving a pressure difference of 2.94m. It then repeats the calculation with the diameters reversed, giving a pressure difference of -2.94m.

Cu06997 lecture 9_open channel

This document summarizes key concepts in fluid dynamics related to open channel flow:
1) It describes different types of open channel flow including steady uniform/non-uniform flow and unsteady uniform/non-uniform flow.
2) Common equations for mean flow velocity are presented, including the Chezy and Manning's formulas which relate velocity to hydraulic radius and slope.
3) The concepts of hydraulic radius, roughness coefficients, shear stress, specific energy, and equilibrium/normal depth are defined and their representative equations shown.

Cu06997 lecture 5_reynolds_and_r

The document discusses hydraulic radius, viscosity, laminar and turbulent flow, Reynolds number, and boundary layers in fluid dynamics. It defines hydraulic radius as the ratio of a pipe or channel's cross-sectional area to its wetted perimeter. It also explores laminar versus turbulent flow and uses the Reynolds number to characterize the transition between these flow regimes based on fluid properties and flow velocities. Finally, it introduces the boundary layer concept to explain the region of fluid that is influenced by solid boundaries.

Cu06997 lecture 9-10_exercises

This document provides instructions for two exercises involving calculations for open channel flow. The first exercise is for a channel with a bed slope of 1:2000 over a length of 1000m, asking to calculate velocity, discharge, boundary shear stress, and determine if flow is turbulent or not. The second exercise considers a horizontal channel with a downstream water level of +1m NAP and depth of 0.7m, flow rate of 1.5m3/s, and asks to calculate upstream water level and other parameters using Manning's equation.

Cu06997 lecture 2_answer

This document discusses concepts related to forces, densities, and fluid pressures. It defines key terms like force, weight, gravity, density of water and soil. It also discusses concepts like buoyancy, Pascal's law, and calculating fluid pressure. It provides an example problem about calculating forces on walls and bottom of a water tank based on the pressure, density and depth of the water.

Cu06997 lecture 8_sewers

Here are the key steps to solve this problem:
1. Calculate the total flow rate at each manhole:
- P4: Q = Rain + Waste = 66 + 10 = 76 l/s
- P3: Q = Rain + Waste = 225 + 10 = 235 l/s
2. Use continuity equation to calculate flow rates in pipes:
- P4-P3 pipe: Q1 = 76 l/s
- P3-P2 pipe: Q2 = 235 l/s
3. Calculate head losses in each pipe and check if above or below allowable head.
- Use Darcy-Weisbach or Chezy equation based on pipe material and roughness

Cu06997 lecture 12_sediment transport and back water

This document discusses sediment transport in open channels. It describes the different types of sediment transport including rolling, sliding, saltation, suspension, and dissolution. It outlines the three main steps of sediment transport: 1) particles start to move through erosion or scour, 2) particles move horizontally through transport, and 3) deposition or sedimentation where particles settle out of the flow. Key parameters that influence erosion include density, grain size, shape, cohesion, turbulence, and bed slope. Sediment transport occurs when the shear stress of the flowing water exceeds the critical shear stress of the sediment material.

Answers assignment 4 real fluids-fluid mechanics

1) The document provides calculations to determine dynamic similitude between a model submarine and full-scale prototype based on Reynolds number. It is found that the prototype would need to operate at an unrealistically low speed of 0.044 m/s.
2) Additional calculations determine the corresponding prototype force of 7.4 N would be required for kinematic similarity.
3) Further calculations determine the prototype velocity and propulsion force required for surface propulsion based on Froude number, finding a velocity of 48 m/s but propulsion force of 6.2 MN, which is also unrealistic.

Answers assignment 3 integral methods-fluid mechanics

The document describes calculations related to fluid flow problems involving pipes, nozzles, and turbines. It includes calculations of:
1) Velocity, pressure, density, and mass/volume flow rates at two points in a pipe with gas flow.
2) Pressure change and head loss in a water-filled pipe due to wall shear stress.
3) Initial velocity of ammonia gas flowing from a tank through a pipe, assuming constant vs variable density.
4) Pressure change and jet force from an air flow constricting in a duct.
5) Reaction force of water flowing from a hole in a tank.
6) Flow rate and required turbine diameter to deliver power under different heads.

Cu06997 exercise5

The document defines the hydraulic radius and Reynolds number, which are important concepts in fluid mechanics. The hydraulic radius is the ratio of the wetted area to the wetted perimeter of a flow channel. The Reynolds number is a dimensionless number that quantifies the ratio of inertial to viscous forces and can be used to characterize different flow regimes, with turbulent flow occurring at a Reynolds number greater than 4000 and laminar flow at less than 2000. It is calculated based on variables like fluid velocity, hydraulic diameter or radius, fluid properties, and temperature.

assignment 1 properties of fluids-Fluid mechanics

The document contains 6 physics questions regarding properties of fluids. Question 1 asks about pressure in a water pipe using a manometer. Question 2 involves using the ideal gas law to determine pressure and mass of air in a tire at different temperatures. Question 3 calculates residual pressure in a tank with two chambers connected by a sluice opening.

Physics LO 4

This document summarizes key concepts about sound waves, including:
1) Sound waves are longitudinal waves that cause alternating high and low pressure areas as molecules are displaced in the propagation direction.
2) The speed of sound depends on the medium and can be calculated using the bulk modulus and density.
3) Sound waves can be described by displacement, pressure, wavelength, frequency, and other variables, with displacement and pressure 90 degrees out of phase.

Cu06997 lecture 10_froude

This document discusses concepts in fluid dynamics including specific energy, critical depth, the Froude number, subcritical and supercritical flow, critical velocity, and hydraulic jumps. It provides equations for calculating critical depth, Froude number, critical velocity, and critical bed slope in open channels. Diagrams show the relationship between total head, water depth, and Froude number below and above critical depth.

Answers assignment 2 fluid statics-fluid mechanics

1. The document contains worked examples calculating hydrostatic forces and pressures on submerged objects of various shapes, including a ball plugging a hole, portholes on a ship, gates, and a steel pipe.
2. Key concepts covered include calculating hydrostatic pressure as a function of depth, determining buoyant forces, calculating net forces and moments, and sizing structural elements based on allowable stresses.
3. Formulas used include those for pressure, buoyancy, force, moment, stress, and thickness required for a given safety factor.

Solution manual for water resources engineering 3rd edition - david a. chin

Solution Manual for Water-Resources Engineering - 3rd Edition
Author(s) : David A. Chin
This solution manual include all problems (Chapters 1 to 17) of textbook. in second section of solution manual, Problems answered using mathcad software .

Solutions Manual for Water-Resources Engineering 3rd Edition by Chin

Full download : https://goo.gl/P6arbY Solutions Manual for Water-Resources Engineering 3rd Edition by Chin

Local Energy (Head) Losses (Lecture notes 03)

1) Local head losses occur in pipes due to changes in cross-sectional area, flow direction, or devices in the pipe. They are called minor losses and can usually be neglected for long pipe systems.
2) The document derives equations for calculating loss coefficients and head losses due to abrupt enlargements and contractions in pipes based on impuls-momentum and Bernoulli equations. It provides example loss coefficient values from experiments.
3) It discusses applying the same methods to model head losses in pipe junctions and conduits with multiple reservoirs.

Flows under Pressure in Pipes (Lecture notes 02)

This document discusses fluid flow in pipes under pressure. It presents equations to describe laminar and turbulent flow. For laminar flow, the Hagen-Poiseuille equation gives the relationship between pressure drop and flow rate. For turbulent flow, the velocity profile consists of a thin viscous sublayer near the wall and a fully turbulent center zone. Equations are derived to describe velocity profiles in both the sublayer and center zone based on viscosity and turbulence effects. Pipes are classified as smooth or rough depending on roughness size compared to the sublayer thickness.

Chapter 11

This document contains examples and solutions related to fluid statics concepts such as pressure, density, buoyancy, and Pascal's principle. It begins with examples calculating the mass, weight, density, and pressure using given values. Later examples apply concepts like buoyancy, pressure at depths, and pressure transmission using hydraulic jacks. Key formulas introduced include pressure (p=F/A), fluid pressure (p=hρg), and buoyancy (B=Vfluidρfluid). Overall, the document provides practice problems and solutions for understanding fundamental fluid statics principles.

Unit 3 Fluid Static

This document provides objectives and information about pressure measurement techniques. It discusses piezometers, barometers, bourdon gauges, and several types of manometers. The key points are:
- Piezometers, barometers, bourdon gauges, and manometers can be used to measure pressure.
- Piezometers use the height of liquid in a tube to determine pressure. Barometers measure atmospheric pressure using the height of a mercury column.
- Bourdon gauges use the deflection of a curved tube to indicate pressure differences over 1 bar.
- Manometers like the simple and differential types utilize the relationship between pressure and liquid height to measure pressures.

Solucionario de fluidos_white

This document provides solutions to problems from Chapter 1 of an introductory fluid mechanics textbook. The key information is:
1) Problem 1.10 asks if the Stokes-Oseen formula for drag on a sphere is dimensionally homogeneous. The formula contains terms with dimensions of force, viscosity, diameter, velocity, density, and the student confirms it is homogeneous.
2) Problem 1.12 asks for the dimensions of the parameter B in an equation relating pressure drop, viscosity, radius, and velocity in laminar pipe flow. The student determines B has dimensions of inverse length.
3) Problem 1.13 calculates the efficiency of a pump given values for volume flow rate, pressure rise, and input power

14.pdf

This document discusses pipe flow and fluid mechanics concepts including:
1) Pipes connected in parallel and calculating flow rates using the continuity and energy equations.
2) Branched pipe systems with three reservoirs and calculating unknown flow rates by guessing the total head and applying the continuity and energy equations.
3) Non-stationary pipe flow where the outflow from a reservoir varies with changing pressure levels over time according to integration of the continuity equation.

Solucionário Introdução à mecânica dos Fluidos - Chapter 01

The document provides solutions to multiple physics problems involving calculations of mass, viscosity, drag force, and speed over time. Problem 1.24 asks to find the maximum speed of a small aluminum sphere falling through air from rest, the time to reach 95% of maximum speed, and plot speed versus time. The solution shows:
- Maximum speed is calculated as 0.0499 m/s
- Speed over time is modeled as an exponential approach to maximum speed
- Time to reach 95% of maximum speed is calculated by solving the exponential model
- A plot of speed versus time is provided showing the exponential curve

Cu06997 lecture 9_open channel

This document summarizes key concepts in fluid dynamics related to open channel flow:
1) It describes different types of open channel flow including steady uniform/non-uniform flow and unsteady uniform/non-uniform flow.
2) Common equations for mean flow velocity are presented, including the Chezy and Manning's formulas which relate velocity to hydraulic radius and slope.
3) The concepts of hydraulic radius, roughness coefficients, shear stress, specific energy, and equilibrium/normal depth are defined and their representative equations shown.

Cu06997 lecture 5_reynolds_and_r

The document discusses hydraulic radius, viscosity, laminar and turbulent flow, Reynolds number, and boundary layers in fluid dynamics. It defines hydraulic radius as the ratio of a pipe or channel's cross-sectional area to its wetted perimeter. It also explores laminar versus turbulent flow and uses the Reynolds number to characterize the transition between these flow regimes based on fluid properties and flow velocities. Finally, it introduces the boundary layer concept to explain the region of fluid that is influenced by solid boundaries.

Cu06997 lecture 9-10_exercises

This document provides instructions for two exercises involving calculations for open channel flow. The first exercise is for a channel with a bed slope of 1:2000 over a length of 1000m, asking to calculate velocity, discharge, boundary shear stress, and determine if flow is turbulent or not. The second exercise considers a horizontal channel with a downstream water level of +1m NAP and depth of 0.7m, flow rate of 1.5m3/s, and asks to calculate upstream water level and other parameters using Manning's equation.

Cu06997 lecture 2_answer

This document discusses concepts related to forces, densities, and fluid pressures. It defines key terms like force, weight, gravity, density of water and soil. It also discusses concepts like buoyancy, Pascal's law, and calculating fluid pressure. It provides an example problem about calculating forces on walls and bottom of a water tank based on the pressure, density and depth of the water.

Cu06997 lecture 8_sewers

Here are the key steps to solve this problem:
1. Calculate the total flow rate at each manhole:
- P4: Q = Rain + Waste = 66 + 10 = 76 l/s
- P3: Q = Rain + Waste = 225 + 10 = 235 l/s
2. Use continuity equation to calculate flow rates in pipes:
- P4-P3 pipe: Q1 = 76 l/s
- P3-P2 pipe: Q2 = 235 l/s
3. Calculate head losses in each pipe and check if above or below allowable head.
- Use Darcy-Weisbach or Chezy equation based on pipe material and roughness

Cu06997 lecture 12_sediment transport and back water

This document discusses sediment transport in open channels. It describes the different types of sediment transport including rolling, sliding, saltation, suspension, and dissolution. It outlines the three main steps of sediment transport: 1) particles start to move through erosion or scour, 2) particles move horizontally through transport, and 3) deposition or sedimentation where particles settle out of the flow. Key parameters that influence erosion include density, grain size, shape, cohesion, turbulence, and bed slope. Sediment transport occurs when the shear stress of the flowing water exceeds the critical shear stress of the sediment material.

Answers assignment 4 real fluids-fluid mechanics

1) The document provides calculations to determine dynamic similitude between a model submarine and full-scale prototype based on Reynolds number. It is found that the prototype would need to operate at an unrealistically low speed of 0.044 m/s.
2) Additional calculations determine the corresponding prototype force of 7.4 N would be required for kinematic similarity.
3) Further calculations determine the prototype velocity and propulsion force required for surface propulsion based on Froude number, finding a velocity of 48 m/s but propulsion force of 6.2 MN, which is also unrealistic.

Answers assignment 3 integral methods-fluid mechanics

The document describes calculations related to fluid flow problems involving pipes, nozzles, and turbines. It includes calculations of:
1) Velocity, pressure, density, and mass/volume flow rates at two points in a pipe with gas flow.
2) Pressure change and head loss in a water-filled pipe due to wall shear stress.
3) Initial velocity of ammonia gas flowing from a tank through a pipe, assuming constant vs variable density.
4) Pressure change and jet force from an air flow constricting in a duct.
5) Reaction force of water flowing from a hole in a tank.
6) Flow rate and required turbine diameter to deliver power under different heads.

Cu06997 exercise5

The document defines the hydraulic radius and Reynolds number, which are important concepts in fluid mechanics. The hydraulic radius is the ratio of the wetted area to the wetted perimeter of a flow channel. The Reynolds number is a dimensionless number that quantifies the ratio of inertial to viscous forces and can be used to characterize different flow regimes, with turbulent flow occurring at a Reynolds number greater than 4000 and laminar flow at less than 2000. It is calculated based on variables like fluid velocity, hydraulic diameter or radius, fluid properties, and temperature.

assignment 1 properties of fluids-Fluid mechanics

The document contains 6 physics questions regarding properties of fluids. Question 1 asks about pressure in a water pipe using a manometer. Question 2 involves using the ideal gas law to determine pressure and mass of air in a tire at different temperatures. Question 3 calculates residual pressure in a tank with two chambers connected by a sluice opening.

Physics LO 4

This document summarizes key concepts about sound waves, including:
1) Sound waves are longitudinal waves that cause alternating high and low pressure areas as molecules are displaced in the propagation direction.
2) The speed of sound depends on the medium and can be calculated using the bulk modulus and density.
3) Sound waves can be described by displacement, pressure, wavelength, frequency, and other variables, with displacement and pressure 90 degrees out of phase.

Cu06997 lecture 10_froude

This document discusses concepts in fluid dynamics including specific energy, critical depth, the Froude number, subcritical and supercritical flow, critical velocity, and hydraulic jumps. It provides equations for calculating critical depth, Froude number, critical velocity, and critical bed slope in open channels. Diagrams show the relationship between total head, water depth, and Froude number below and above critical depth.

Answers assignment 2 fluid statics-fluid mechanics

1. The document contains worked examples calculating hydrostatic forces and pressures on submerged objects of various shapes, including a ball plugging a hole, portholes on a ship, gates, and a steel pipe.
2. Key concepts covered include calculating hydrostatic pressure as a function of depth, determining buoyant forces, calculating net forces and moments, and sizing structural elements based on allowable stresses.
3. Formulas used include those for pressure, buoyancy, force, moment, stress, and thickness required for a given safety factor.

Solution manual for water resources engineering 3rd edition - david a. chin

Solution Manual for Water-Resources Engineering - 3rd Edition
Author(s) : David A. Chin
This solution manual include all problems (Chapters 1 to 17) of textbook. in second section of solution manual, Problems answered using mathcad software .

Solutions Manual for Water-Resources Engineering 3rd Edition by Chin

Full download : https://goo.gl/P6arbY Solutions Manual for Water-Resources Engineering 3rd Edition by Chin

Local Energy (Head) Losses (Lecture notes 03)

1) Local head losses occur in pipes due to changes in cross-sectional area, flow direction, or devices in the pipe. They are called minor losses and can usually be neglected for long pipe systems.
2) The document derives equations for calculating loss coefficients and head losses due to abrupt enlargements and contractions in pipes based on impuls-momentum and Bernoulli equations. It provides example loss coefficient values from experiments.
3) It discusses applying the same methods to model head losses in pipe junctions and conduits with multiple reservoirs.

Flows under Pressure in Pipes (Lecture notes 02)

This document discusses fluid flow in pipes under pressure. It presents equations to describe laminar and turbulent flow. For laminar flow, the Hagen-Poiseuille equation gives the relationship between pressure drop and flow rate. For turbulent flow, the velocity profile consists of a thin viscous sublayer near the wall and a fully turbulent center zone. Equations are derived to describe velocity profiles in both the sublayer and center zone based on viscosity and turbulence effects. Pipes are classified as smooth or rough depending on roughness size compared to the sublayer thickness.

Chapter 11

This document contains examples and solutions related to fluid statics concepts such as pressure, density, buoyancy, and Pascal's principle. It begins with examples calculating the mass, weight, density, and pressure using given values. Later examples apply concepts like buoyancy, pressure at depths, and pressure transmission using hydraulic jacks. Key formulas introduced include pressure (p=F/A), fluid pressure (p=hρg), and buoyancy (B=Vfluidρfluid). Overall, the document provides practice problems and solutions for understanding fundamental fluid statics principles.

Unit 3 Fluid Static

This document provides objectives and information about pressure measurement techniques. It discusses piezometers, barometers, bourdon gauges, and several types of manometers. The key points are:
- Piezometers, barometers, bourdon gauges, and manometers can be used to measure pressure.
- Piezometers use the height of liquid in a tube to determine pressure. Barometers measure atmospheric pressure using the height of a mercury column.
- Bourdon gauges use the deflection of a curved tube to indicate pressure differences over 1 bar.
- Manometers like the simple and differential types utilize the relationship between pressure and liquid height to measure pressures.

Solucionario de fluidos_white

This document provides solutions to problems from Chapter 1 of an introductory fluid mechanics textbook. The key information is:
1) Problem 1.10 asks if the Stokes-Oseen formula for drag on a sphere is dimensionally homogeneous. The formula contains terms with dimensions of force, viscosity, diameter, velocity, density, and the student confirms it is homogeneous.
2) Problem 1.12 asks for the dimensions of the parameter B in an equation relating pressure drop, viscosity, radius, and velocity in laminar pipe flow. The student determines B has dimensions of inverse length.
3) Problem 1.13 calculates the efficiency of a pump given values for volume flow rate, pressure rise, and input power

Cu06997 lecture 9_open channel

Cu06997 lecture 9_open channel

Cu06997 lecture 5_reynolds_and_r

Cu06997 lecture 5_reynolds_and_r

Cu06997 lecture 9-10_exercises

Cu06997 lecture 9-10_exercises

Cu06997 lecture 2_answer

Cu06997 lecture 2_answer

Cu06997 lecture 8_sewers

Cu06997 lecture 8_sewers

Cu06997 lecture 12_sediment transport and back water

Cu06997 lecture 12_sediment transport and back water

Answers assignment 4 real fluids-fluid mechanics

Answers assignment 4 real fluids-fluid mechanics

Answers assignment 3 integral methods-fluid mechanics

Answers assignment 3 integral methods-fluid mechanics

Cu06997 exercise5

Cu06997 exercise5

assignment 1 properties of fluids-Fluid mechanics

assignment 1 properties of fluids-Fluid mechanics

Physics LO 4

Physics LO 4

Cu06997 lecture 10_froude

Cu06997 lecture 10_froude

Answers assignment 2 fluid statics-fluid mechanics

Answers assignment 2 fluid statics-fluid mechanics

Solution manual for water resources engineering 3rd edition - david a. chin

Solution manual for water resources engineering 3rd edition - david a. chin

Solutions Manual for Water-Resources Engineering 3rd Edition by Chin

Solutions Manual for Water-Resources Engineering 3rd Edition by Chin

Local Energy (Head) Losses (Lecture notes 03)

Local Energy (Head) Losses (Lecture notes 03)

Flows under Pressure in Pipes (Lecture notes 02)

Flows under Pressure in Pipes (Lecture notes 02)

Chapter 11

Chapter 11

Unit 3 Fluid Static

Unit 3 Fluid Static

Solucionario de fluidos_white

Solucionario de fluidos_white

14.pdf

This document discusses pipe flow and fluid mechanics concepts including:
1) Pipes connected in parallel and calculating flow rates using the continuity and energy equations.
2) Branched pipe systems with three reservoirs and calculating unknown flow rates by guessing the total head and applying the continuity and energy equations.
3) Non-stationary pipe flow where the outflow from a reservoir varies with changing pressure levels over time according to integration of the continuity equation.

Solucionário Introdução à mecânica dos Fluidos - Chapter 01

The document provides solutions to multiple physics problems involving calculations of mass, viscosity, drag force, and speed over time. Problem 1.24 asks to find the maximum speed of a small aluminum sphere falling through air from rest, the time to reach 95% of maximum speed, and plot speed versus time. The solution shows:
- Maximum speed is calculated as 0.0499 m/s
- Speed over time is modeled as an exponential approach to maximum speed
- Time to reach 95% of maximum speed is calculated by solving the exponential model
- A plot of speed versus time is provided showing the exponential curve

Momentum equation.pdf

1. The chapter discusses momentum and forces in fluid flow, including the development of the momentum principle using Newton's second law and the impulse-momentum principle.
2. The momentum equation is developed for two-dimensional and three-dimensional flow through a control volume, accounting for forces, velocities, flow rates, and momentum correction factors.
3. Examples of applying the momentum equation are presented, including forces on bends, nozzles, jets, and vanes.

Problema 5

This document analyzes the power required to pump 565 L/s of water through a 91m long pipe with an internal diameter of 200mm.
Given the flow rate, pipe dimensions, and fluid properties, the head loss due to friction and fittings is calculated to be 155.5m.
Using this head loss along with the flow rate and fluid properties in an energy balance equation, the required pumping power is calculated to be approximately 717 kW.

Solutions fox

This document contains 20 problems related to fluid mechanics and thermodynamics. Problem 1.20 provides data on measuring the height of a building using horizontal distance and angle measurements, and asks the reader to calculate height, uncertainty, and optimal measurement angle to minimize uncertainty. An Excel file shows calculations and plots uncertainty versus angle. The optimal angle is 31.4 degrees, which minimizes the height uncertainty of 0.95%.

Jamuna Oil Comany Ltd recruitment question & ans (5th july 2018)

This document contains information about an exam for Jamuna Oil Company Ltd, including:
- The exam date is July 5th and will take place from 3:30-5:00 PM at BUET.
- The exam contains 50 multiple choice questions worth 25 marks and 12 departmental questions worth 50 marks, for a total of 75 marks.
- Sample multiple choice and departmental questions are provided.
- Solutions to two of the departmental questions are provided, calculating the thickness required for a pressure vessel and the velocity of a pendulum bob.
- The document requests feedback on any mistakes found in the solutions.

Hidraulica ejercicios

This document contains 5 exercises calculating hydraulic factors like friction factor (f) and head loss (hf) in pipes. The exercises provide pipe diameter, flow rate, roughness, length and other parameters to calculate f using equations appropriate for the Reynolds number flow regime. The calculated f is then used to find head loss and pressure drop for the given pipe system. The exercises demonstrate the importance of selecting the right equation based on flow type and help apply hydraulic concepts to practical pipe network design and analysis.

Answers assignment 5 open channel hydraulics-fluid mechanics

This document contains the solutions to 5 questions regarding open channel hydraulics.
Q1 calculates that a weed-overgrown drainage channel needs to be cleared and maintained to convey a 5-year storm flow of 0.23 m3/s with a roughness coefficient of less than 0.045.
Q2 determines that a 2.7m wide concrete channel needs to be constructed 2.79m deep to convey 22.8 m3/s of flow with 0.3m of freeboard.
Q3 finds that a 7m wide spillway will flow at critical depth of 1.496m for a flowrate of 40.1 m3/s, with a corresponding still water depth behind

Hardycross method

The document discusses the Hardy Cross Method for analyzing water distribution systems to determine pressures and flows. It involves the following steps:
1. Assume pipe diameters and initial flows such that the sum of inflows equals outflows at junctions.
2. Calculate head losses in each pipe using the Hazen-Williams equation.
3. Calculate flow corrections using an equation that sets the sum of head losses around loops to zero.
4. Repeat using corrected flows until flow corrections become small.
An example problem applies the method to determine suitable pipe diameters for a branching system given pressure requirements at nodes.

Inclass ass

The document contains solutions to two problems involving fluid mechanics. The first problem calculates the difference in elevation h between two water reservoirs using a manometer reading of 25 cm. The second problem calculates the force F on a gate submerged in oil and the center-of-pressure position X, given the gate's dimensions, oil density, and the water depth and angle. It finds F to be 38.83 kN and X to be 0.615 m.

Presentation 4 ce 801 OCF by Rabindraa ranjan Saha

Velocity distribution, coefficients, pattern of velocity distribution,examples, velocity measurement, derivation of velocity distribution coefficients, problems and solution, Bernoulli's theorem and energy equation, specific energy and equation.

Flow visualization

1. The document describes experiments using venture and nozzle meters to measure fluid flow rate. It provides the theory behind how each meter works and equations to calculate flow rate based on pressure differences.
2. Experiments were conducted to measure the actual flow rate of water through each meter and calculate the theoretical flow rate. Discharge coefficients were then determined.
3. Results showed that actual flow rates were lower than theoretical due to frictional losses, and discharge coefficients generally decreased with flow rate for venture meters but increased for nozzle meters.

Introduction to basic principles of fluid mechanics

1) The document introduces basic principles of fluid mechanics, including Lagrangian and Eulerian descriptions of fluid flow. The Lagrangian description follows individual particles, while the Eulerian description observes flow properties at fixed points in space.
2) It describes three governing laws of fluid motion within a control volume: conservation of mass (the net flow in and out of a control volume is zero), conservation of momentum (Newton's second law applied to a fluid system), and conservation of energy.
3) It derives Bernoulli's equation, which relates pressure, velocity, and elevation along a streamline for inviscid, steady, incompressible flow. Bernoulli's equation is an application of conservation of momentum along a streamline.

groundwater flood routing presentationhazard.pptx

Flood routing methods like hydrologic and hydraulic approaches are used to predict how a flood wave propagates through a river channel or reservoir. Hydrologic routing uses the continuity equation to relate inflow, outflow, and storage changes within a reach. The Modified Pul's Method and Goodrich Method are commonly used semi-graphical hydrologic routing techniques. Flood routing is important for applications like flood forecasting, reservoir design, and flood protection. It can help attenuate flood peaks and determine lag times as flood waves pass through storage areas.

@Pipeflow

The document discusses fluid flow in pipes and provides examples of applying key principles like continuity, Bernoulli's equation, and Torricelli's theorem. It summarizes the Trans-Alaskan pipeline that transports oil over 800 miles through a single 48-inch diameter pipe. Key equations are defined for volume, weight, and mass flow rates. Bernoulli's equation relates pressure, elevation, and velocity changes between two points. Examples show applying continuity to find velocity and Bernoulli's equation to find pressure. Torricelli's theorem governs velocity from an orifice based on fluid height.

pipe lines lec 2.pptx

1. The document discusses principles of pipe flow, including siphon action where a pipeline rises above the hydraulic gradient line. It provides equations to calculate head loss due to friction in pipes.
2. An example problem is presented to calculate residual pressure at the end of a pipe outlet for a pumping system with different pipe fittings, applying equations for head loss calculations.
3. Common pipe flow problems like nodal head, discharge, and diameter problems are introduced and equations are provided to solve each type of problem.

006

The document discusses concepts related to fluid flow including continuity equations, conservation of mass, Bernoulli's equation, and venturi meters. It provides examples of calculating volume flow rate, fluid velocity, mass flow rate, and pressure given pipe dimensions and fluid properties. It also discusses how venturi meters can be used to measure flow rates based on pressure changes through the converging and diverging sections.

BASIC EQUATIONS FOR ONE-DIMENSIONAL FLOW (Chapter 04)

1) Bernoulli's equation states that for steady flow in an inviscid fluid, the total mechanical energy per unit weight remains constant along a streamline. This includes potential energy, kinetic energy, and pressure energy.
2) It summarizes that an applied force equals the rate of change of mechanical energy, and derives the one-dimensional Euler and Bernoulli equations from conservation of energy and momentum principles.
3) The document provides examples of applying Bernoulli's equation to problems involving pipe flow and nozzle discharge to determine quantities like jet velocity and suction pressure.

Steady flow energy eq....by Bilal Ashraf

This document provides information about a group presentation on the steady flow energy equation (SFEE). It defines steady and unsteady flow, derives the SFEE, and discusses its applications to nozzles, diffusers, steam turbines, throttling valves, heat exchangers, and systems with multiple outlets. It also covers the non-flow energy equation and provides examples of using the SFEE to solve problems involving turbines, duct flow, isentropic expansion in a turbine, air compression in a nozzle, and isentropic expansion in a nozzle.

Solutions Manual for Foundations Of MEMS 2nd Edition by Chang Liu

Full download : https://goo.gl/rLRJBK Solutions Manual for Foundations Of MEMS 2nd Edition by Chang Liu

14.pdf

14.pdf

Solucionário Introdução à mecânica dos Fluidos - Chapter 01

Solucionário Introdução à mecânica dos Fluidos - Chapter 01

Momentum equation.pdf

Momentum equation.pdf

Problema 5

Problema 5

Solutions fox

Solutions fox

Jamuna Oil Comany Ltd recruitment question & ans (5th july 2018)

Jamuna Oil Comany Ltd recruitment question & ans (5th july 2018)

Hidraulica ejercicios

Hidraulica ejercicios

Answers assignment 5 open channel hydraulics-fluid mechanics

Answers assignment 5 open channel hydraulics-fluid mechanics

Hardycross method

Hardycross method

Inclass ass

Inclass ass

Presentation 4 ce 801 OCF by Rabindraa ranjan Saha

Presentation 4 ce 801 OCF by Rabindraa ranjan Saha

Flow visualization

Flow visualization

Introduction to basic principles of fluid mechanics

Introduction to basic principles of fluid mechanics

groundwater flood routing presentationhazard.pptx

groundwater flood routing presentationhazard.pptx

@Pipeflow

@Pipeflow

pipe lines lec 2.pptx

pipe lines lec 2.pptx

006

006

BASIC EQUATIONS FOR ONE-DIMENSIONAL FLOW (Chapter 04)

BASIC EQUATIONS FOR ONE-DIMENSIONAL FLOW (Chapter 04)

Steady flow energy eq....by Bilal Ashraf

Steady flow energy eq....by Bilal Ashraf

Solutions Manual for Foundations Of MEMS 2nd Edition by Chang Liu

Solutions Manual for Foundations Of MEMS 2nd Edition by Chang Liu

Cu07821 ppt9 recapitulation

This document discusses water management goals and models for two agricultural areas covering 1000 hectares each. It aims for optimal water levels for farming and nature while preventing water issues. The Sobek model simulates a rainstorm over 96 hours, calculating water levels every 5 minutes for 1 month. Questions address water storage capacities in soil and surface water. Calibration requires precipitation data and variances in water levels. Simulations examine summer and winter conditions under different drainage scenarios and capacities. Maintaining infrastructure is important to ensure proper water discharge and storage.

Gastcollege mli

ICT in het onderwijs 28-10-2015

Cu07821 10management and maintenance2015

Management and maintenance of water systems involves complying with various regulations at the European, national, provincial and local levels. It requires managing surface waters, beds, embankments, structures, water levels and other components. Key instruments used include the "Legger" which establishes the situation and dimensions, the "Peilbesluit" which sets water levels, and the "Keur" which establishes regulations. Maintenance activities include dredging, mowing, reconstructing side structures and embankments, and removing new growth. Maintenance of structures involves removing dredgings and repairing structures as needed.

Cu07821 9 zoning plan2015

The document discusses zoning plans, water assessments, and ledgers related to land development and water management. A zoning plan describes allowed land and building uses, and can regulate details like building heights and distances. Changing a zoning plan's designation requires stakeholder input and can take years. A water assessment analyzes how a zoning change, like converting farmland to urban use, will impact the water system. Ledgers document requirements for waterways regarding location, form, size, and construction, and define management boundaries and protection zones. The case involves stakeholders debating a developer's proposed zoning change, with topics including impacts to the water system and potential problems.

Cu07821 8 weirs

This document discusses different types of weirs used to measure water discharge, including broad crested weirs, thin plate weirs, and Rehbock, Romijn, Cipoletti, circular, and Thomson weirs. Broad crested weirs can be long or short, and influence discharge measurements differently depending on whether water downstream affects flow. Thin plate weirs have a sharp crest and allow measuring the upstream water level where it is streamlined with atmospheric pressure under the nappe. The document also provides a link to a video about a hydrosystem and field trip in Macedonia.

Cu07821 7 culverts new

Culverts are civil engineering structures used to allow water to pass under roads or embankments. There are several types of culverts including round concrete tubes, rectangular precast concrete elements, and metal culverts. Culverts require appropriate foundations depending on the material and site conditions, including shallow foundations, foundations on improved soil, or foundations on wooden or concrete poles. Culvert endings can have various shapes like long front walls, receding wings, or return walls to connect to surrounding terrain.

Cu07821 6 pumping stations_update

The document discusses various types of pumping stations including Archimedean screws, axial pumps, centrifugal pumps, and submerged pumps. It notes key components of centrifugal pumps like impellers, volutes, and casings. It also covers pump installation methods, switching levels, frequency drives, impeller types for different uses, and hydraulic concepts like duty point and head.

Cu07821 5 drainage

1) Darcy's law describes groundwater flow through porous media according to hydraulic conductivity and hydraulic gradient.
2) Factors that influence groundwater levels include precipitation, soil type, and land use. Heavy rainfall or irrigation can cause groundwater levels to rise.
3) The drainage of an agricultural parcel is calculated based on the hydraulic conductivity, horizontal distance from a stream, and vertical distances between the groundwater level and impenetrable layer and stream level.

Cu07821 4 soil

This document discusses the hydrological cycle and soil moisture in the unsaturated zone. It describes:
1) The process of rainfall infiltration and groundwater recharge. Water is stored in the pores of the unsaturated zone below the ground surface.
2) Forces that act on soil moisture in the unsaturated zone, including adsorption, osmotic, and capillary forces. Capillary action causes smaller pores to fill with water before larger pores.
3) The soil moisture curve and Staring series, which relate soil type to water pressure and volume of water stored. Finer textured soils like clay can store more water than coarser soils like sand.

Cu07821 3 precipitation and evapotranspiration

1. The hydrological cycle diagram shows the annual water balance for an area, with 800 mm of precipitation, 350 mm of evapotranspiration, 425 mm of surface runoff, and 475 mm of groundwater recharge.
2. Effective precipitation is defined as the volume of precipitation available for groundwater recharge, and is calculated as total precipitation minus actual evapotranspiration, which depends on crop type.
3. Extreme precipitation events like the 1998 "Westlandbui" storm that dropped 100 mm of rain in 24 hours can cause hundreds of millions of euros in flood damage.

Cu07821 2 help

This document discusses water management strategies in the Netherlands, specifically focusing on optimal water level agreements. It describes how water levels are managed through water level agreement areas, where the surface water level is fixed and uniform. The typical Dutch strategy involves examining the existing water situation and specifying adjustments to achieve an optimal groundwater and surface water regime. It also discusses how to relate crop selection and production to soil type and groundwater classification using HELP tables. Maintaining appropriate water levels is important for preventing flooding, drying out, and salination while supporting agriculture and nature.

Cu07821 1 intro_1415

This document provides information about several rural water management courses, including their course codes and names. It then discusses the organization of one course called "Rural Water Management" including that it has both theory and assignment classes each week. The document outlines the course assignment which is to prepare a water level agreement for a polder in Noord Beveland. It also lists the criteria for marks in the course. The rest of the document covers hydrological cycle concepts and diagrams, reasons for managing water systems, how water systems can be adjusted, key topics covered in the course, and an exercise on simple water level areas.

Research portfolio delta_academy_s2_2014_2015

Every semester the 4 research groups of the Delta Academy offer research possibilities for internships, final thesis and Minor. The document (also in English) shows the assignments for the second semester of study year 2014/2015.

Research portfolio da arc 2014-2015 s1

This document provides a summary of research projects conducted by the Delta Academy Applied Research Centre between September 2014 and January 2015. The research was divided among four main research groups: Aquaculture in Delta Areas, Building with Nature, Water Technology, and Water Safety & Area Development. The projects covered a wide range of topics including algae cultivation, shellfish feeding, bioremediation, coastal ecosystem restoration, wastewater reuse, community resilience, and water management in the Dutch delta region.

Research portfolios1 2013_2014 jan july 2014

Mindert de Vries (mindert.devries@hz.nl)
FEEDING TRIALS OYSTERS
The quality of algal biomass as feed for shellfish is dependent on the cultivation parameters. In order to
determine the effect of algal quality on shellfish growth and condition, feeding trials with oysters using
algae cultivated under different parameters are needed. In cooperation with the algae research a set of
feeding trials will be designed and executed. Growth and condition parameters of the oysters will be
determined. This will give insight in the effect of algal quality on shellfish production parameters.
Research type: experiments (HZ, Vlissingen)
Research level: minor

Presentatie AET voor scholieren 15-11-2013

Presentatie AET voor scholieren 15-11-2013

Vision group1(5)

This document outlines a vision and action plan for sustainable development along the Guadalete river basin in Spain. It discusses objectives in areas like water quality, water quantity, ecosystem management, and economic development. It proposes various measures like improving wastewater treatment, promoting renewable energy, education initiatives, green infrastructure projects, sustainable tourism, and balancing economic and natural resource goals. Stakeholders are grouped according to their priorities and the plan identifies both short and long term actions needed to achieve an integrated approach to river management.

Final presentation spain quattro

This document discusses plans for sustainable management of the Guadelete River basin in southern Spain. It envisions transitioning the region away from traditional agriculture and overdevelopment towards more sustainable practices like aquaculture, eco-tourism, and sustainable agriculture/aquaculture. Specific measures proposed include improving wastewater treatment, promoting sustainable farming techniques, developing rural hotels and tourism activities centered around the river, and restoring abandoned salt marshes to create jobs and biodiversity. Stakeholders like universities, NGOs, and different levels of government would need to cooperate to achieve this sustainable vision for the river basin.

Final presentation group 3

The document outlines a plan to improve the Guadalete river basin in Spain by 2030. The vision is for the river basin to have good water quality, sustainable industries, increased environmental awareness, good management, and a high quality of living. Several objectives are identified, including sustainable development, increasing public awareness, and improving water quality and management. Specific measures and timelines are proposed to achieve these objectives, such as improving wastewater treatment plants, sewage systems, and increasing taxes from industries and tourism to fund improvements. Educational programs for local schools are also described to increase environmental awareness among residents.

Cu07821 ppt9 recapitulation

Cu07821 ppt9 recapitulation

Gastcollege mli

Gastcollege mli

Cu07821 10management and maintenance2015

Cu07821 10management and maintenance2015

Cu07821 9 zoning plan2015

Cu07821 9 zoning plan2015

Cu07821 8 weirs

Cu07821 8 weirs

Cu07821 7 culverts new

Cu07821 7 culverts new

Cu07821 6 pumping stations_update

Cu07821 6 pumping stations_update

Cu07821 5 drainage

Cu07821 5 drainage

Cu07821 4 soil

Cu07821 4 soil

Cu07821 3 precipitation and evapotranspiration

Cu07821 3 precipitation and evapotranspiration

Cu07821 2 help

Cu07821 2 help

Cu07821 1 intro_1415

Cu07821 1 intro_1415

Research portfolio delta_academy_s2_2014_2015

Research portfolio delta_academy_s2_2014_2015

Research portfolio da arc 2014-2015 s1

Research portfolio da arc 2014-2015 s1

Jacobapolder

Jacobapolder

Research portfolios1 2013_2014 jan july 2014

Research portfolios1 2013_2014 jan july 2014

Presentatie AET voor scholieren 15-11-2013

Presentatie AET voor scholieren 15-11-2013

Vision group1(5)

Vision group1(5)

Final presentation spain quattro

Final presentation spain quattro

Final presentation group 3

Final presentation group 3

Pengantar Penggunaan Flutter - Dart programming language1.pptx

Pengantar Penggunaan Flutter - Dart programming language1.pptx

Jemison, MacLaughlin, and Majumder "Broadening Pathways for Editors and Authors"

Jemison, MacLaughlin, and Majumder "Broadening Pathways for Editors and Authors"National Information Standards Organization (NISO)

This presentation was provided by Racquel Jemison, Ph.D., Christina MacLaughlin, Ph.D., and Paulomi Majumder. Ph.D., all of the American Chemical Society, for the second session of NISO's 2024 Training Series "DEIA in the Scholarly Landscape." Session Two: 'Expanding Pathways to Publishing Careers,' was held June 13, 2024.BBR 2024 Summer Sessions Interview Training

Qualitative research interview training by Professor Katrina Pritchard and Dr Helen Williams

C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx

C1 Rubenstein

Beyond Degrees - Empowering the Workforce in the Context of Skills-First.pptx

Iván Bornacelly, Policy Analyst at the OECD Centre for Skills, OECD, presents at the webinar 'Tackling job market gaps with a skills-first approach' on 12 June 2024

Electric Fetus - Record Store Scavenger Hunt

Electric Fetus is a record store in Minneapolis, MN

How to Setup Warehouse & Location in Odoo 17 Inventory

In this slide, we'll explore how to set up warehouses and locations in Odoo 17 Inventory. This will help us manage our stock effectively, track inventory levels, and streamline warehouse operations.

Mule event processing models | MuleSoft Mysore Meetup #47

Mule event processing models | MuleSoft Mysore Meetup #47
Event Link:- https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-mule-event-processing-models/
Agenda
● What is event processing in MuleSoft?
● Types of event processing models in Mule 4
● Distinction between the reactive, parallel, blocking & non-blocking processing
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shivani Yasaswi - https://www.linkedin.com/in/shivaniyasaswi/
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw

Bonku-Babus-Friend by Sathyajith Ray (9)

Bonku-Babus-Friend by Sathyajith Ray for class 9 ksb

Temple of Asclepius in Thrace. Excavation results

The temple and the sanctuary around were dedicated to Asklepios Zmidrenus. This name has been known since 1875 when an inscription dedicated to him was discovered in Rome. The inscription is dated in 227 AD and was left by soldiers originating from the city of Philippopolis (modern Plovdiv).

Chapter wise All Notes of First year Basic Civil Engineering.pptx

Chapter wise All Notes of First year Basic Civil Engineering
Syllabus
Chapter-1
Introduction to objective, scope and outcome the subject
Chapter 2
Introduction: Scope and Specialization of Civil Engineering, Role of civil Engineer in Society, Impact of infrastructural development on economy of country.
Chapter 3
Surveying: Object Principles & Types of Surveying; Site Plans, Plans & Maps; Scales & Unit of different Measurements.
Linear Measurements: Instruments used. Linear Measurement by Tape, Ranging out Survey Lines and overcoming Obstructions; Measurements on sloping ground; Tape corrections, conventional symbols. Angular Measurements: Instruments used; Introduction to Compass Surveying, Bearings and Longitude & Latitude of a Line, Introduction to total station.
Levelling: Instrument used Object of levelling, Methods of levelling in brief, and Contour maps.
Chapter 4
Buildings: Selection of site for Buildings, Layout of Building Plan, Types of buildings, Plinth area, carpet area, floor space index, Introduction to building byelaws, concept of sun light & ventilation. Components of Buildings & their functions, Basic concept of R.C.C., Introduction to types of foundation
Chapter 5
Transportation: Introduction to Transportation Engineering; Traffic and Road Safety: Types and Characteristics of Various Modes of Transportation; Various Road Traffic Signs, Causes of Accidents and Road Safety Measures.
Chapter 6
Environmental Engineering: Environmental Pollution, Environmental Acts and Regulations, Functional Concepts of Ecology, Basics of Species, Biodiversity, Ecosystem, Hydrological Cycle; Chemical Cycles: Carbon, Nitrogen & Phosphorus; Energy Flow in Ecosystems.
Water Pollution: Water Quality standards, Introduction to Treatment & Disposal of Waste Water. Reuse and Saving of Water, Rain Water Harvesting. Solid Waste Management: Classification of Solid Waste, Collection, Transportation and Disposal of Solid. Recycling of Solid Waste: Energy Recovery, Sanitary Landfill, On-Site Sanitation. Air & Noise Pollution: Primary and Secondary air pollutants, Harmful effects of Air Pollution, Control of Air Pollution. . Noise Pollution Harmful Effects of noise pollution, control of noise pollution, Global warming & Climate Change, Ozone depletion, Greenhouse effect
Text Books:
1. Palancharmy, Basic Civil Engineering, McGraw Hill publishers.
2. Satheesh Gopi, Basic Civil Engineering, Pearson Publishers.
3. Ketki Rangwala Dalal, Essentials of Civil Engineering, Charotar Publishing House.
4. BCP, Surveying volume 1

Nutrition Inc FY 2024, 4 - Hour Training

Slides for Lessons: Homes and Centers

math operations ued in python and all used

used to math operaions

مصحف القراءات العشر أعد أحرف الخلاف سمير بسيوني.pdf

مصحف أحرف الخلاف للقراء العشرةأعد أحرف الخلاف بالتلوين وصلا سمير بسيوني غفر الله له

ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...

Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
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Stack Memory Organization of 8086 Microprocessor

The stack memory organization of 8086 microprocessor.

Gender and Mental Health - Counselling and Family Therapy Applications and In...

A proprietary approach developed by bringing together the best of learning theories from Psychology, design principles from the world of visualization, and pedagogical methods from over a decade of training experience, that enables you to: Learn better, faster!

What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...

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BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...

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https://app.box.com/s/tacvl9ekroe9hqupdnjruiypvm9rdanePengantar Penggunaan Flutter - Dart programming language1.pptx

Pengantar Penggunaan Flutter - Dart programming language1.pptx

Jemison, MacLaughlin, and Majumder "Broadening Pathways for Editors and Authors"

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BBR 2024 Summer Sessions Interview Training

BBR 2024 Summer Sessions Interview Training

C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx

C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx

Beyond Degrees - Empowering the Workforce in the Context of Skills-First.pptx

Beyond Degrees - Empowering the Workforce in the Context of Skills-First.pptx

Electric Fetus - Record Store Scavenger Hunt

Electric Fetus - Record Store Scavenger Hunt

How to Setup Warehouse & Location in Odoo 17 Inventory

How to Setup Warehouse & Location in Odoo 17 Inventory

Mule event processing models | MuleSoft Mysore Meetup #47

Mule event processing models | MuleSoft Mysore Meetup #47

Bonku-Babus-Friend by Sathyajith Ray (9)

Bonku-Babus-Friend by Sathyajith Ray (9)

Temple of Asclepius in Thrace. Excavation results

Temple of Asclepius in Thrace. Excavation results

Chapter wise All Notes of First year Basic Civil Engineering.pptx

Chapter wise All Notes of First year Basic Civil Engineering.pptx

Nutrition Inc FY 2024, 4 - Hour Training

Nutrition Inc FY 2024, 4 - Hour Training

math operations ued in python and all used

math operations ued in python and all used

مصحف القراءات العشر أعد أحرف الخلاف سمير بسيوني.pdf

مصحف القراءات العشر أعد أحرف الخلاف سمير بسيوني.pdf

ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...

ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...

Stack Memory Organization of 8086 Microprocessor

Stack Memory Organization of 8086 Microprocessor

Gender and Mental Health - Counselling and Family Therapy Applications and In...

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What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...

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SWOT analysis in the project Keeping the Memory @live.pptx

SWOT analysis in the project Keeping the Memory @live.pptx

- 1. Exercise lecture 7 culverts Downstream Upstream Cross-section Dropwaterlevel Length culvert Length culvert is 50 m, cross-section 2 x 2 m, λ=0,022 and μ =0,6 Question 1 Calculate the discharge if the drop in water level is 1 m and the velocity downstream and upstream is 0 m/s. Make a sketch of the H and h line, with numbers
- 2. Because the velocity upstream and downstream is 0 m/s, velocity head is 0, total head is equal to pressure line, difference in water level is the same as difference in energy level. Δy = ΔH. ΔH = 1 m. 2g u ξΔΗ 2 c tottot ⋅= m O A R 50,0 2222 22 = +++ ⋅ == 44,01 1 2 = −= µ ξi 55,0 5,04 50 022,0 = ⋅ ⋅=⋅= D l w λξ 1=uξ 994,1155,044,0)ξξξ( uwi =++=++=totξ smu /17,3= s mQ 3 67,12=
- 3. Head losses at culvert: m22,0 20 17,3 44,0 2g u ξΔΗ 22 culvert i =⋅=⋅= m28,0 20 17,3 55,0 2g u ξΔΗ 22 culvert ffriction =⋅=⋅= m50,0 20 17,3 1 2g u ξΔΗ 22 culvert oo =⋅=⋅= When I add al losses it should be 1 m, which is the total head loss ΔH Velocity head culvert m50,0 20 17,3 2 22 culvert == g u Due to contraction the Aera at the inlet of the culvert will be 0,6 x 4 =2,4 m2 So velocity will be 12,67/2,4=5,28 m/s. This makes the velocity head at the contraction m39,1 20 28,5 2 = Velocity head upstream culvert m0 20 0 2 22 upstream == g u Velocity head downstream culvert m0 20 0 2 22 downstream == g u
- 5. Question 2 Calculate the discharge en velocity culvert if the velocity upstream is 1 m/s and downstream is 2 m/s. Drop in waterlevel is 1 m. Make a sketch of the H and h line, with numbers The difference with question 1 is that the velocity upstream and downstream are not 0, so velocity head upstream and downstream are not 0, so total head upstream is not equal to pressure line upstream, so total head downstream is not equal to pressure line downstream. Velocity head upstream m05,0 2 12 = g , downstream is m2,0 2 22 = g So ΔH=1 + 0,05 –0,2 =0,85 m. The other numbers are the same as with question 1. s mHgAq tot tot v 3 2 68,1185,0204 994,1 1 2 1 =⋅⋅⋅=∆⋅⋅⋅= ξ sm A Q u /92,2 4 68,11 === Of course you also can use the formulas: 2g v ξΔΗ 2 c tottot ⋅= And For the sketch, you can use the same strategy as with question 1, only the velocity now is different, 2,92 m/s. And the velocity head upstream(0,05m) and downstream (0,2 m)are not zero Head losses at culvert: m19,0 20 92,2 44,0 2g u ξΔΗ 22 culvert i =⋅=⋅= m23,0 20 92,2 55,0 2g u ξΔΗ 22 culvert ffriction =⋅=⋅= m43,0 20 92,2 1 2g u ξΔΗ 22 culvert oo =⋅=⋅= When I add al losses it should be 0,85 m, which is the total head loss ΔH Velocity head culvert m43,0 20 92,2 2 22 culvert == g u Due to contraction the Aera at the inlet of the culvert will be 0,6 x 4 =2,4 m2 So velocity will be 11,68/2,4=4,87 m/s. This makes the velocity head at the contraction m18,1 20 87,4 2 = 1 m 0,05 m 0,2 m ΔH duiker
- 6. Question 3 Suppose the water level downstream is 3 m above the bottom of the culvert, velocity downstream and upstream is 0,5 m/s and the flow-rate is 10 m3 /s. Calculate the water level upstream. Make a sketch of the H and h line, with numbers De duiker staat geheel gevuld met water. tot tot v HgAq ∆⋅⋅⋅= 2 1 2 ξ Er is 1 onbekende, ΔH. In this case ΔH al other numbers are given. totH∆⋅⋅⋅= 204 994,1 1 10 oplossen geeft ΔH=0,62 m. Dit is het energieverschil!!!! Niet het drukverschil (=waterstandsverschil) Er moet nog rekening gehouden worden met de snelheidshoogte m0125,0 2 5,0 2 = g . Bovenstrooms en benedenstrooms is de snelheidshoogte gelijk. To transfer this to difference in water level the velocity head upstream and downstream have to be taken into account!!!!! Het waterstandsverschil wordt (water level difference will be) Δy=0,0125 + 0,62 - 0,0125=0,62 m De waterstand bovenstrooms is (water upstream) 3 + 0,62 =3,62 m tov de bodem. Note: Because velocity downstream and upstream are equal, both velocity heads are equal so difference in water level(Δy) is equal to difference in head (ΔH) For the sketch you may use the same strategy as with question 2. Velocity culvert is different, velocity upstream / downstream is different. 0,0125 m m 0,0125 m m ΔH=0,62 m Culvert Δh=??
- 7. Question 4 We use same data as question 3. Suppose the calculated water level upstream is to high. What possibilities do you have to lower the upstream water level, without changing the dimensions of cross-section of the culvert. Het energieverschil, en dus waterstandsverschil kan met een van de volgende formules bepaald worden: tot tot v HgAq ∆⋅⋅⋅= 2 1 2 ξ of 2g u ξΔΗ 2 duiker ⋅= tot If you look at the formula above, q, A and u do not change. The only number you can change is totaalξ totaalξ exists off 44,0=iξ Door de vorm aan te passen ( afronding met grote straal) is het mogelijk de waarde te verlagen tot 0. If you use a smooth shape, you can reduce the value to 0 55,0=⋅= D l w λξ Hier valt niks aan te passen. Can’t change this,, we assume that we don’t use another material 1=uξ Door de vorm aan te passen is het mogelijk de waarde te verlagen tot 0,3 By changing the shape (is somewhere in the PTT) you can reduce the value to 0,3 totaalξ wordt nu 0 + 0,55 + 0,3 = 0,85 ipv 1,992 totH∆⋅⋅⋅= 204 85,0 1 10 oplossen geeft ΔH=0,27 m. Aangezien de snelheidshoogte beneden en bovenstrooms gelijk is (zie uitwerking opgave 3) is ook het waterstandverschil 0, 27 m. Because velocity head downstream and upstream are the same, difference in waterlevel is 0,27 m. In dit geval is het dus mogelijk om het waterstandverschil meer dan te halveren, door het aanpassen, optimaliseren van de instroom en uitstroomopening. So by optimizing the shape you can reduce the head loss with about 50%.
- 9. Question 5 Suppose the discharge is3 m3 /s. Velocity upstream is 1 m/s, velocity downstream is 0,5 m/s. Reference line is the bottom of the culvert, water level downstream is 3 m above reference, water level upstream is 3.5 m above reference. Calculate the dimensions of the cross-section of the culvert. Make a sketch of the H (total head) and h (pressure) line, with numbers De duiker ligt geheel onder water. Snelheidshoogte bovenstrooms is m05,0 2 12 = g , benedenstrooms is m0125,0 2 5,0 2 = g ΔH=0,5 + 0,05 – 0,0125 =0,54 m. We gaan uit van de volgende formule 2g u ξΔΗ 2 duiker ⋅= tot en A Q u = samen 2g Q ξΔΗ 2 2 duiker ⋅ ⋅= A tot waarbij : 44,0=iξ Zie opgave 1 deze blijft hetzelfde 1=uξ Zie opgave 1 deze blijft hetzelfde RRD l w 275,0 4 50 022,0 =⋅=⋅= λξ R tot 275,0 44,1 +=ξ en O A R = Onbekenden zijn dus A (afmetingen van de duiker) en R. De oplossing kan je vinden door te proberen. Daarbij is het zo dat er een soort standaard afmetingen zijn bij duikers. Kijk bv op www.waco.nl bij afmetingen duikers The numbers which are missing are A and R. This is difficult to solve mathematically , I would suggest to use the try and error method. Eerste poging, doorsnede duiker is 2 x 2 m. (first attempt) m O A R 50,0 2222 22 = +++ ⋅ == 99,1 5,0 275,0 44,1 =+=totξ m A tot 05,1 204 13 99,1 2g Q ξΔΗ 2 2 2 2 duiker = ⋅ ⋅= ⋅ ⋅= >0,54 m voldoet niet Tweede poging, doorsnede duiker is 3 x 2,5 m. m O A R 68,0 5,25,233 5,23 = +++ ⋅ == 84,1 68,0 275,0 44,1 =+=totξ m A tot 28,0 205,7 13 84,1 2g Q ξΔΗ 2 2 2 2 duiker = ⋅ ⋅= ⋅ ⋅= <0,54 m is wel erg ruim 0,5 m 0,05 m 0,0125m ΔH duiker
- 10. Derde poging, doorsnede duiker is 3 x 2 m. m O A R 6,0 2233 23 = +++ ⋅ == 90,1 6,0 275,0 44,1 =+=totξ m A tot 45,0 206 13 90,1 2g Q ξΔΗ 2 2 2 2 duiker = ⋅ ⋅= ⋅ ⋅= <0,54 m voldoet De waterstandsverhoging tgv van de duiker 3 x 2 m wordt : 0,45 + 0,0125 – 0,05 = 0, 41 m, terwijl er een maximale stijging van 0,50 m was toegestaan. Dit soort berekening kunnen heel goed in een spreadsheet uitgevoerd worden.