Comprehensive 4th Grade Mathematics: Estimation, Addition, and Subtraction of Large Numbers
Covers comparing, estimating sums and differences, addition and subtraction up to 1,000,000 with and without regrouping, including word problems and assessments for 4th grade students.
A. Directions: Writethe symbols >, <, or
= on the space between the numbers to
compare their value.
R E V I E W
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P R E - L E S S O N
3.
1. 210 000_____ 230 000
2. 14 156 _____ 15 156
3. 175 333 _____ 175 333
4. 90 546 _____ 90 654
5. 293 102 _____ 293 120
R E V I E W
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P R E - L E S S O N
4.
B. Can yousolve the following?
1. 35, 231 + 24, 567 =
2. 46, 700 + 45, 234 =
3. 190, 222 + 78, 021 =
4. 89, 765 – 76, 001 =
5. 187, 123 – 87, 123 =
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P R E - L E S S O N
1. Identify thenumbers: Let's say we
have 58,736 and 32,489.
ESTIMATING THE SUM
7.
2. Round eachnumber to the nearest
large place value: For large numbers,
this usually means rounding to the
nearest ten thousand or hundred
thousand.
ESTIMATING THE SUM
8.
58,736 roundsto 60,000 (nearest ten
thousand).
32,489 rounds to 30,000 (nearest ten
thousand).
ESTIMATING THE SUM
9.
3. Add therounded numbers:
60,000 + 30,000 = 90,000.
ESTIMATING THE SUM
10.
Example 1:
• Originalnumbers: 58,736 and 32,489.
• Rounded numbers: 60,000 and 30,000.
• Estimated sum: 60,000
+ 30,000
90,000.
ESTIMATING THE SUM
11.
Example 2:
• Originalnumbers: 142,356 and 87,243.
• Rounded numbers: 140,000 and 90,000
(rounded to the nearest ten thousand).
• Estimated sum:
140,000 + 90,000 = 230,000.
ESTIMATING THE SUM
12.
1. Identify thenumbers: Let's use 58,736 and
32,489 again.
2. Round each number to the nearest large
place value:
o 58,736 rounds to 60,000.
o 32,489 rounds to 30,000.
ESTIMATING THE DIFFERENCE
Example 1:
• Originalnumbers: 58,736 and 32,489.
• Rounded numbers: 60,000 and 30,000.
• Estimated difference: 60,000 - 30,000 = 30,000.
ESTIMATING THE DIFFERENCE
15.
Example 2:
• Originalnumbers: 142,356 and 87,243.
• Rounded numbers: 140,000 and 90,000 (rounded
to the nearest ten thousand).
• Estimated difference:
140,000 - 90,000 = 50,000.
ESTIMATING THE DIFFERENCE
16.
Directions: Estimate thesum of the
following.
1. 45, 532 2. 78, 345
+ 26, 453 + 56, 453
A C T I V I T Y 1
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A S S E S S M E N T
17.
3. 135, 1234. 821, 776
+ 87, 214 + 243, 234
5. 895, 322
+ 345, 789
A C T I V I T Y 1
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A S S E S S M E N T
18.
Directions: Estimate thesum of the
following.
1. 45, 532 2. 78, 345
- 26, 453 - 56, 453
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E X T E N D E D
19.
3. 135, 1234. 821, 776
- 87, 214 - 243, 234
5. 895, 322
- 345, 789
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E X T E N D E D
1. Identify thenumbers: Let's say we
have 58,736 and 32,489.
ESTIMATING THE SUM
29.
2. Round eachnumber to the nearest
large place value: For large numbers,
this usually means rounding to the
nearest ten thousand or hundred
thousand.
ESTIMATING THE SUM
30.
58,736 roundsto 60,000 (nearest ten
thousand).
32,489 rounds to 30,000 (nearest ten
thousand).
ESTIMATING THE SUM
31.
3. Add therounded numbers:
60,000 + 30,000 = 90,000.
ESTIMATING THE SUM
32.
Example 1:
• Originalnumbers: 58,736 and 32,489.
• Rounded numbers: 60,000 and 30,000.
• Estimated sum: 60,000
+ 30,000
90,000.
ESTIMATING THE SUM
33.
Example 2:
• Originalnumbers: 142,356 and 87,243.
• Rounded numbers: 140,000 and 90,000
(rounded to the nearest ten thousand).
• Estimated sum:
140,000 + 90,000 = 230,000.
ESTIMATING THE SUM
34.
1. Identify thenumbers: Let's use 58,736 and
32,489 again.
2. Round each number to the nearest large
place value:
o 58,736 rounds to 60,000.
o 32,489 rounds to 30,000.
ESTIMATING THE DIFFERENCE
Example 1:
• Originalnumbers: 58,736 and 32,489.
• Rounded numbers: 60,000 and 30,000.
• Estimated difference: 60,000 - 30,000 = 30,000.
ESTIMATING THE DIFFERENCE
37.
Example 2:
• Originalnumbers: 142,356 and 87,243.
• Rounded numbers: 140,000 and 90,000 (rounded
to the nearest ten thousand).
• Estimated difference:
140,000 - 90,000 = 50,000.
ESTIMATING THE DIFFERENCE
38.
Directions: Estimate thetotal.
1) 45,783 + 67,234
2) 89,456 + 12,345
3) 123,456 + 78,910
4) 256,789 + 143,210
5) 97,854 + 32,765
A C T I V I T Y 2
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A S S E S S M E N T
39.
Directions: Estimate thedifference.
1) 89,543 - 56,789
2) 123,456 - 78,912
3) 234,567 - 123,456
4) 97,865 - 65,432
5) 345,678 - 234,567
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E X T E N D E D
Directions: Read theproblem.
Mrs. Javier went to a grocery store. She
bought the items below. Estimate how
much change Mrs. Javier will receive if
she pays 100 000 bill for each.
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P R E - L E S S O N
1. Addition (Sumsup to 1,000,000)
• Without Regrouping: This happens
when the sum of the digits in a specific
column is 9 or less. You simply write the
sum below the line.
R E V I E W
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D I S C U S S I O N
45.
• With Regrouping(Carrying): When
the sum of a column is 10 or more, you
write the ones digit of that sum in the
answer space and "carry" the tens digit to
the next column on the left.
R E V I E W
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D I S C U S S I O N
46.
2. Subtraction (Numbersless than
1,000,000)
• Without Regrouping: This happens
when the top digit (minuend) is larger than
or equal to the bottom digit (subtrahend) in
every column.
R E V I E W
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D I S C U S S I O N
47.
With Regrouping (Borrowing):When
the top digit is smaller than the bottom
digit, you must "borrow" 1 from the
column to the left. This increases the
value of your current digit by 10.
R E V I E W
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D I S C U S S I O N
48.
A. Directions: Findthe sum for each item.
Some problems will require regrouping
(carrying), while others will not.
A C T I V I T Y 4
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A S S E S S M E N T
49.
1. 523,140 +264,728
2. 675,392 + 128,409
3. 412,005 + 387,994
4. 256,880 + 443,119
5. 834,567 + 165,432
A C T I V I T Y 4
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A S S E S S M E N T
50.
B. Directions: Subtractthe numbers below.
Watch out for problems that require
"borrowing" across multiple columns.
A C T I V I T Y 4
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A S S E S S M E N T
51.
1. 895,672 -453,210
2. 712,400 - 356,185
3. 999,999 - 123,456
4. 600,000 - 247,315
5. 543,210 - 231,000
A C T I V I T Y 4
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A S S E S S M E N T
52.
Directions: Carefully solveeach equation
by performing the indicated operation.
1. 642,850 + 235,149 =
2. 958,600 - 426,300 =
3. 517,392 + 382,608 =
4. 800,000 - 345,670 =
5. 456,712 + 123,288 =
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E X T E N D E D
Directions: Carefully solveeach equation
by performing the indicated operation.
1. 875,400 - 324,100 =
2. 249,550 + 610,450 =
3. 900,000 - 567,825 =
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P R E - L E S S O N
55.
4. 156,234 +743,766 =
5. A farm harvested 680,500 kilos of
rice. They sold 425,300 kilos to a
local trader. How many kilos of rice
are left in the barn?
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P R E - L E S S O N
1. Addition (Sumsup to 1,000,000)
• Without Regrouping: This happens
when the sum of the digits in a specific
column is 9 or less. You simply write the
sum below the line.
R E V I E W
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D I S C U S S I O N
58.
• With Regrouping(Carrying): When
the sum of a column is 10 or more, you
write the ones digit of that sum in the
answer space and "carry" the tens digit to
the next column on the left.
R E V I E W
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D I S C U S S I O N
59.
2. Subtraction (Numbersless than
1,000,000)
• Without Regrouping: This happens
when the top digit (minuend) is larger than
or equal to the bottom digit (subtrahend) in
every column.
R E V I E W
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D I S C U S S I O N
60.
With Regrouping (Borrowing):When
the top digit is smaller than the bottom
digit, you must "borrow" 1 from the
column to the left. This increases the
value of your current digit by 10.
R E V I E W
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D I S C U S S I O N
61.
Directions: Solve eachproblem and
determine if the provided answer is True
or False. If it is false, provide the correct
sum or difference.
A C T I V I T Y 4
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A S S E S S M E N T
62.
1. 450,000 +150,000 = 600,000 (______)
2. 800,000 - 250,000 = 650,000 (______)
3. 312,450 + 212,450 = 524,900 (______)
4. 920,000 - 120,000 = 800,000(______)
5. 560,700 + 439,300 = 1,000,000 (______)
A C T I V I T Y 4
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A S S E S S M E N T
63.
Directions: Read eachitem closely.
Solve the addition and subtraction
problems. For items involving word
problems, write the mathematical
sentence first before solving.
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E X T E N D E D
64.
1. Find thesum: 724,150 + 185,950
2. Find the difference:
672,405 - 281,560
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E X T E N D E D
65.
3. A donationdrive collected 412,300
pesos in the morning and 387,700
pesos in the afternoon. How much
was the total collection?
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E X T E N D E D
66.
4. A bookstorehas 950,000 pages
of bond paper. If they used 562,400
pages for printing modules, how many
pages are left?
5. Challenge: 1,000,000 - 450,500
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E X T E N D E D