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b) If r has multiplicity 2 as a zero of polynomial f(x) and multiplic-
ity 3 as a zero of polynomial g(x). Explain why it is also a zero
of h(x) = f2(x) + g2(x). Can we determine it's multiplicity? If
so what is the multiplicity? If not, why not?
the response should be related to Fundamental theorem of algebra 1 or 2, or remainder theorem
factore theorem or rational root theorem- gotta be related to something
Solution
It is realted to factor theorem
If r is a zero for f(x) with multiplicity m then (x-r)m is a factor of f(x)
Hence f(x) = k(x)*(x-r)2
g(x) = p(x)*(x-r)3
=>
f2(x) = k2(x)*(x-r)4
g2(x) = p2(x)*(x-r)6
=>h(x) = f2(x) + g2(x) = (x-r)4 ( k2(x)+ p2(x)*(x-r)2)
Hence r is also a zero of h(x) with multiplicity 4 as (x-r)4 is a factor of h(x)

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b) If r has multiplicity 2 as a zero of polynomial f(x) and multipli.pdf

  • 1. b) If r has multiplicity 2 as a zero of polynomial f(x) and multiplic- ity 3 as a zero of polynomial g(x). Explain why it is also a zero of h(x) = f2(x) + g2(x). Can we determine it's multiplicity? If so what is the multiplicity? If not, why not? the response should be related to Fundamental theorem of algebra 1 or 2, or remainder theorem factore theorem or rational root theorem- gotta be related to something Solution It is realted to factor theorem If r is a zero for f(x) with multiplicity m then (x-r)m is a factor of f(x) Hence f(x) = k(x)*(x-r)2 g(x) = p(x)*(x-r)3 => f2(x) = k2(x)*(x-r)4 g2(x) = p2(x)*(x-r)6 =>h(x) = f2(x) + g2(x) = (x-r)4 ( k2(x)+ p2(x)*(x-r)2) Hence r is also a zero of h(x) with multiplicity 4 as (x-r)4 is a factor of h(x)