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A student rolled a standard six-sided die 60 times, recording the number of dots that appeared on each roll. The results showed an uneven distribution of rolls across the six sides of the die. A statistical test is required to determine if the die is fair or not using a 10% significance level.

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A student went on a fishing trip over the weekend and these were len.pdf

A student went on a fishing trip over the weekend and these were len.pdf

A study is conducted to estimate survival in patients following kidn.pdf

A study is conducted to estimate survival in patients following kidn.pdf

A study is conducted in patients with HIV. The primary outcome is CD.pdf

A study is conducted in patients with HIV. The primary outcome is CD.pdf

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A student went on a fishing trip over the weekend and these were len.pdf

A student went on a fishing trip over the weekend and these were lengths of the 13 fish he
caught.
12, 13, 5, 8, 9, 20, 16, 14, 14, 6, 9, 12, 12
A) Make 2 general statements (statistical) about this trip.
Solution
this a probability distribution mode of distribution = 12.

A study is conducted to estimate survival in patients following kidn.pdf

A study is conducted to estimate survival in patients following kidney transplant. Key factors
that adversely affect success of the transplant include advanced age and diabetes. This study
involves 25 participants who are 65 years of age and older and all have diabetes. Following
transplant, each participant is following for up to 10 years. the following are times to death, in
years, or the time to last contact (at which time the participants was known to be alive).
Deaths: 1.2, 2.5, 4.3, 5.6. 6.7, 7.3 and 8.1 years
Alive: 3.4, 4.1, 4.2, 5.7, 5.9, 6.3, 6.4, 6.5, 7.3, 8.2, 8.6, 8.9, 9.4, 9.5, 10, 10, 10 and 10 years
Interval in Years
Number At Risk During Interval,
Nt
Average Number At Risk During Interval,
Nt*=Nt-Ct/2
Number of Deaths During Interval,
Dt
Lost to Follow-Up, Ct
Proportion Dying
qt = Dt/Nt*
Proportion Surviving pt = 1-qt
Survival Probability
St = pt*St-1
0-2
2-4
4-6
6-8
8-10
Use the Kaplan-Meier approach to estimate the survival function.
Referring to the graph below:
What is the probability of surviving 6.5 years?
A. None
B. 0.85
C. 0.60
D. 0.90
Patients have an 85% chance of surviving how many years?
A. 6.0
B. 4.25
C. 3.2
D. 5.5
Time,
Complete the table below
Years
Number at Risk
Nt
Number of Deaths
Dt
Numbers Censored
Ct
Survival Probability
St+1= St*((Nt-Dt)/Nt)
0
25
1.2
2.5
3.4
4.1
4.2
4.3
5.6
5.7
5.9
6.3
6.4
6.5
6.7
7.3
8.1
8.2
8.6
8.9
9.4
9.5
10.0
Interval in Years
Number At Risk During Interval,
Nt
Average Number At Risk During Interval,
Nt*=Nt-Ct/2
Number of Deaths During Interval,
Dt
Lost to Follow-Up, Ct
Proportion Dying
qt = Dt/Nt*
Proportion Surviving pt = 1-qt
Survival Probability
St = pt*St-1
0-2
2-4
4-6
6-8
8-10
Solution
Probability of surviving 6.5 years: A. None of the above
85% chance of surviving: B. 4.25 years.

A study is conducted in patients with HIV. The primary outcome is CD.pdf

A study is conducted in patients with HIV. The primary outcome is CD4 cell count which is a
measure of the stage of the disease. Lower CD4 counts are associated with more advanced
disease. The investigators are interested in the association between vitamin and mineral
supplements and CD4 count. A multiple regression analysis is performed relating CD4 count to
use of supplements (coded as 1=yes, 0=no) and to duration of HIV, in years (i.e., the number of
years between the diagnosis of HIV and the study date). For the analysis, Y=CD4 count.
= 501.41 + 12.67 Supplements %u2013 30.23 Duration of HIV
A. What is the expected CD4 count for a patient taking supplements who has had HIV for 2.5
years?
= ________
B. What is the expected CD4 count for a patient not taking supplements who was diagnosed with
HIV at study enrollment?
= ________
C. What is the expected CD4 count for a patient not taking supplements who has had HIV for 2.5
years.
= ________
Solution
(a) 501.41 + 12.67*1+30.23*2.5 =589.655
(b) 501.41 + 12.67*0+30.23*1 =531.64
(c) 501.41 + 12.67*0+30.23*2.5 =576.985.

A student takes a quiz consisting of 10 multiple choice questions. E.pdf

A student takes a quiz consisting of 10 multiple choice questions. Each question has 5 possible
answers. If a student is guessing the answers at random, and the answers to different questions
are independent, find the probability of giving at least five correct answers.
Solution
1 - binomcdf(10,.2,4) = 1 - .9672 = .0328.

a study determined that 2 of children under 18yrs lived with their .pdf

a study determined that 2% of children under 18yrs lived with their father only. find the
probability that exactly 2 children selected at random from 16 children under 18yrs lived with
their father only.
the probability that exactly 2 of the 16 children under 18yrs lived with their father only is?
Solution
(1/(2^(n-1))* (2/100).

A student scored 43 percent on a test, and was in the 35th percentil.pdf

A student scored 43 percent on a test, and was in the 35th percentile. Explain these two numbers.
Solution
43 PERCENT MEANS HE ANSWERED 43% CORRECT ANSWERS, AND 35
PERCENTILE MEANS HE SCORED BETTER THAN 35 PERCENT OF THE PEOPLE WHO
TOOK THE TEST.

A student survey was done to study the relationship between class st.pdf

A student survey was done to study the relationship between class standing (freshman,
sophomore, junior, or senior) and major subject (English, Biology, French, Political Science,
Undeclared, or Other). What degrees of freedom would be used in conducting the hypothesis
test?
Solution
24.

A student scored 50 percent on a test, and was in the 43rd percentil.pdf

A student scored 50 percent on a test, and was in the 43rd percentile. Explain these two numbers.
Solution
I.
The 50 percent means that the student correctly answered half of all of the questions asked on the
test.
Percent score is a way to compare objects against a set rubric.
II.
Scoring in the 43rd percentile means the student performed better than 43% of all test takers.
Percentile is a way to compare objects against one another..

A student went on a fishing trip over the weekend and these were len.pdf

A student went on a fishing trip over the weekend and these were len.pdf

A study is conducted to estimate survival in patients following kidn.pdf

A study is conducted to estimate survival in patients following kidn.pdf

A study is conducted in patients with HIV. The primary outcome is CD.pdf

A study is conducted in patients with HIV. The primary outcome is CD.pdf

A student takes a quiz consisting of 10 multiple choice questions. E.pdf

A student takes a quiz consisting of 10 multiple choice questions. E.pdf

a study determined that 2 of children under 18yrs lived with their .pdf

a study determined that 2 of children under 18yrs lived with their .pdf

A student scored 43 percent on a test, and was in the 35th percentil.pdf

A student scored 43 percent on a test, and was in the 35th percentil.pdf

A student survey was done to study the relationship between class st.pdf

A student survey was done to study the relationship between class st.pdf

A student scored 50 percent on a test, and was in the 43rd percentil.pdf

A student scored 50 percent on a test, and was in the 43rd percentil.pdf

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Title: Relational Database Management System Concepts(RDBMS)
Description:
Welcome to the comprehensive guide on Relational Database Management System (RDBMS) concepts, tailored for final year B.Sc. Computer Science students affiliated with Alagappa University. This document covers fundamental principles and advanced topics in RDBMS, offering a structured approach to understanding databases in the context of modern computing. PDF content is prepared from the text book Learn Oracle 8I by JOSE A RAMALHO.
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Disclaimer:
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Feedback and Contact Information:
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- 1. A student rolled a standard six-sided die 60 times, resulting in the distribution of dots shown in the chart: Number of Dots: 1 2 3 4 5 6 Frequency: 7 14 9 13 7 10 Total = 60 Is the die fair? Use a 10% significance level. Assume all statistical requirements are met. Solution http://www.isds.duke.edu/~michael/book.pdf