Scheme for perfect score module 2012


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Scheme for perfect score module 2012

  2. 2. SECTION II - COMMON MISTAKES AND MISCONCEPTIONS8. Physical Quantity Physical quantity measured Physics Unit and symbol Stop watch time Second. s voltmeter Voltage, V Volt, V thermometer temperature Kelvin or oCelsius Bourdon gauge Gas pressure Pascal, Pa Ammeter Electric current Ampere, A9. Terms Common Mistake Correct Answer [The type of energy when the object is at P] Gravitational Potential Energy a Potential energy Force acting on surface area Force/area Normal force acting on a unit of b Pressure surface area A product of depth, density and gravitational acceleration Pascal’s principle In a close container, force is In a close container, pressure is c transmitted equally transmitted equally. Latent heat of Heat absorbed to change 1 kg d Heat absorbed to change vaporization of liquid to gas without any by 1oC changes in temperature. Amount of kinetic energy in an e Transfer from hot body to Temperature object cold body [Physics phenomena in a prism] Total internal reflection f Reflection
  3. 3. Terms Common Mistake Correct Answer Critical angle is when the Critical angle is the incident refracted angle is 90o angle in denser medium whichg Critical angle Critical angle is the incident produces when the refracted angle when the reflected angle in less dense medium is angle is 90o 90o The image that formed The image that cannot beh Virtual image behind the lens formed on the screen light of one frequency /i Monochromatic light A colour of one light wavelength / colour ………………………….. displacement of any Maximum point of the particle/oscillating system fromj Amplitude highest displacement its ……………………………………….. ……………………………………….. The time taken for any particlek Period One complete oscillation to make one complete oscillation 1000 W of energy is supplied 1000 W of energy is consumed Specification:l when the power supplied is in 1 s when connected to a 240 240 V, 1000 W 240 V. V power supply. When the current flow A conductor which can produce through magnetj electromagnet magnetic field when current Is a combination of electric passes through it. and magnetic fieldk Beta particles Negative charge Fast moving electron
  4. 4. B. Misconceptians Examples: Num Misconceptions Correction Oil is used in hydraulic jack because it has 1 .. because it is not easily evaporate. higher boiling point Snell’s law state that: The sine of incident 2 The sine of incident angle = constant angle Refractive The sine of = refracted angle The sine of refracted index angle Container A Container B water Pressure at X = Pressure at Y because X and Y are at the same depth, same 3 gravitational acceleration and in the same type of liquid that has same density. The force exerted at X > the force exerted at ( P = hg) Y because smaller surface area (P = F /A) To increase the efficiency of ac/dc GENERATOR: Generator – the current is induced - Use more number of turns to produce stronger magnetic field The ship can float in sea water because the total density of the ship is less than the density of water The buoyant force is equals to the total weight of the ship The ship can float in sea water because the buoyant force is bigger than the weight of the ship
  5. 5. C. Paper 3 1. Data Tabulation Title - no unit Content- not consistent Example: Common Mistake Correct Answer Electric Current Voltage Electric Current, I (A) Voltage, V (V) 0.1 0.5 0.10 0.5 0.12 1 0.12 1.0 0.14 1.5 0.14 1.5TOV 1 – SPM FORMAT SET 1 4531/2 SECTION AQuestion 5No Answer Scheme Marka The force that gravitation exerts upon a body 1b(i) The mass of slotted weigh in Diagram 5.1 > Diagram 5.2 1b(ii) The nett force in Diagram 5.2 > Diagram 5.1 1b(iii) The acceleration in Diagram 5.2 > Diagram 5.1 1c The greater the nett force , the greater the acceleration 1d(i) Net force in Diagram 5.1 > Diagram 5.3 1d(ii) The acceleration in Diagram 5.1 > Diagram 5.3 1d(iii) The weight of 20 N in Diagram 5.1 is perpendicular to the tension of the string 1Question 6No Answer Scheme Mark Diagram 6.1 : no relative motiona(i) 2 Diagram 6.2 : there is a relative motiona(ii) Number of turns in Diagram 6.3 > Diagram 6.2 1b(i) The greater the number of turn of coil, the greater the change in magnetic flux 1 The greater the number of turn of coil, the greater the magnitude of inducedb(ii) 1 currentc Faraday’s Law 1 When the magnet is pulled away from the coild Reason : the current will flow in such direction that oppose the change that 2 cause it
  6. 6. Question 7 No Answer Scheme Mark a Depth of water 1 P = hg5 b = 2.5 x 103 x 10 2 = 2.5 x 104 N m-2 c Less different of water pressure 1 Place the water tank P higher than water tank R // use water pump d(i) 2 It will increase the water pressure // sufficient water supply Bigger base area //thicker wall at the bottom d(ii) 2 Less pressure exerted on the ground // could withstand water pressure Low density material // fiber tank d(iii) 2 Light // can withstand stronger pressureQuestion 8 No Answer Scheme Mark1. (a) Atmospheric pressure is the weight of the atmosphere on an object 1 (b) 1. Vacuum pump is used to pump out the air from the suction cup 3 2. Partial vacuum is created in the suction cup 3. Higher atmospheric pressure push the glass sheet onto the suction cup 1 (c)(i) Low pressure 1 (ii) Larger difference in pressure 1 (iii) Big diameter cup 1 (iv) Greater force 1 (d) Triple cups 1 Greater force 1 R 1 Straw/syringe/siphon/vacuum cleaner 12Question 9 No Answer Scheme Mark a The force exerted by the gas molecules onto a unit of surface area 1 When temperature increases, the average kinetic energy increases Rate of collision also increase b 4 Rate of change of momentum increase Force exerted on a unit of surface area increase Temperature of gas : 9.3 > 9.2 c 5 Volume of gas : 9.3 = 9.2
  7. 7. No Answer Scheme Mark Reading of pressure gauge : 9.2 < 9.3 Temperature increase, reading of pressure gauge Pressure Law Characteristics Explaination Rate of rotation is less // Temperature does not Large radius increase easily Increase the surface area // less pressure Many tyres d Provide a gripping surface 10 Tyres with treads Prevent from deformation Strong tyre Can withstand high temperature High melting pointQuestion 10 No Answer Scheme Mark Electromagnetic induction 1 a b 4 Number of turns of coil : Diagram 10.3 > Diagram 10.4 Speed of magnet : same c Deflection of galvanometer : Diagram 10.3 > 10.4 5 When number of turns of coil increased, deflection also increased Faraday’s Law Characteristics Explaination Curve magnet Produce radial magnetic field Stronger magnet Produce stronger magnetic field d Replace component X 10 Current is induced in one direction with commutator Good conductor Copper wire coil Thick copper wire Less resistance
  8. 8. Question 11(a) Distance between optical centre and focal point(b)(i) M1 correct substitution into formula or correct answer M = v/u = 60/20 = 3(b)(ii) M1 correct substitution into formula: 1 1 1 1 1 = + = + 𝑓 𝑢 𝑣 20 60 M2 Answer with correct unit f = 15 cm = 0.15 m(b)(iii) M1: P = 100/f = 100/15 M2: Answer with correct unit: = 6.67 D(c) M1: Parallel light rays from the hot sun at infinity pass through a convex lens// labeled diagram M2: Light rays are focused after passing through the lens // labeled diagram M3: Light rays are converged onto a focal point of the lens M4: At the point, the intensity of lights is great (and the light energy) causes an increases in temperature. When the spot on the paper become hot enough, the paper start to burn // light energy change to heat energy. Aspect Reason Focal length is longer // eyepiece must be more longer focal Low power of eye piece length than objective lens Focal length is shorter / objective lens must be powerful lens High power objective lens than eyepiece lens// Objective lens must be shorter focal length than eyepiece lens. Distance between lenses : To produce bigger image from the eyepiece // to increase >fo + fe the magnification Position of the specimen : fo< To produce real, inverted and magnified image u < 2fo The most suitable is : Focal length of eyepiece is longer than objective lens, microscope M distance between lenses is greater than (fo + fe), and the position of the specimen is between fo and 2 fo
  9. 9. Question 12Answer:(a) frequency(b) 1 High pitch, high frequency / pitch directly propotional to frequency 2 frequency is inversly propotional to wave length // high frequency has shorter wave length 3 Short λ / high f / high pith at C, will diffract / spread out/ bend less 4 Sound easily diffracted / bending / spread out during low pitch/ low f/long λ / at A,B,C(c) Characteristic Reason Large diameter Receive more signal Same as focal length Signal are focused/converged to the receiver Microwave Has high frequency / high energy The signal is not blocked / easy to be High detected Choose K because Because it has large diameter, Same as focal length, use microwave and locate at high position.(d)(i) v = 2s/t = (2 x 90)/0.12 = 1 500 m/s (i) V = fλλ = 1 500/50 000 = 0.03 m = 3 cmTOV 2 – SPM FORMAT SET 2 4531/2 SECTION AQUESTION 5 No Answer Scheme Mark a The size of the coin in Diagram 6.1 < Diagram 6.2 1 b Refraction of light wave 2 Light travels from water to air // denser to less dense medium c Light is refracted away from normal line 3 The image is seen bigger and closer to the observer eye n = rd/ad = H/h d h = 16/(4/3) 2 = 12 cm e Use liquid with bigger refractive index 1
  10. 10. QUESTION 6No Answer Scheme Mark 1a(i) Kinetic energy to electric energy Rotating coil will cut the magnetic fluxa(ii) Emf is produced 3 The commutatorwii ensure the current flow in one directionb(i) The ratio Np : Ns is 6 : 1 1b(ii) diode 1 Capacitorb(iii) 2 Reason : it can store and discharge charges Copper wire // laminated iron corec 2 Reason : good conductor // reduce eddy currentQUESTION 7 No Answer Scheme Mark a Temperature increases 2 Pressure increases b When temperature increases, the average kinetic energy increases 3 Rate of collision also increase Rate of change of momentum increase Force exerted on a unit of surface area increase c) P1 = 200 kPa T1 = 273 + 30 = 303 K P2 = 225 kPa T2 = (T1P2)/ P1 = (303 x225) /200 3 = 340.875 K d(i) More 1 d(ii) Able to support greater mass // heavier load 1 d(iii) Grips efficiently 1
  11. 11. QUESTION 8 No Answer Scheme Mark (a) Concave mirror 1 (b) 1. Object between F and pole of mirror 4 2. Light parallel to principal axis reflected to F 3. Light through C reflect back original path 4. Extend the lines to back of mirror and draw a virtual image (c)(i) Concave 1 (ii) To focus light 1 Big size 1 (iii) To collect and reflect more light 1 (iv) At focal point of the mirror 1 Light/energy will focus after light reflected 1 Z 1 12QUESTION 9 No Answer Scheme Mark Real image is an image which can be formed / projected on a screen. 1 a(i) object distance in 9.1 is shorter than 9.2 Size of image formed in 9.1 is bigger than in 9.2 a(ii) Image distance in 9.1 is smaller /shorter 5 The shorter the object distance, the bigger the size of the image formed When the object distance is shorter, the magnification scale is bigger. P b 4 1. Object is placed between F and P 2. Parallel light ray from top of object to mirror and reflected to F 3. Light ray from top to mirror and reflected back to C 4. Extrapolation of both rays and its intersection behind the mirror and an upright image is drawn.
  12. 12. No Answer Scheme Mark suggestion Explanation Higher intensity of light / more light Use higher power bulb produced. The filament of the bulb is at the focus point of The light ray focuses to one point. d 10 the concave mirror More curvature Increase the intensity. To produce real and enlarge / bigger lens between f and 2f images. Increase the distance / Larger image produced further away the screenQUESTION 10 No Answer Scheme Mark 10 (a) Monochromatic light: light of one frequency / wavelength / 1 colour (b)  In figure 10.1(a), distance between the double slit and 1 screen, D is smaller  In figure 10.1(b), distance between two successive bright 1 fringes, x is smaller  In figure 10.1(b), the number of fringes is bigger / more 1 fringes  In figure 10.1(b), the width of fringes is smaller / narrower 1  When the distance between the double slit and screen, D 1 increases, the distance between two successive fringes, x increases. 5 (c)  Microwaves are transmitted by the radar 1  the radar transmits the signal towards the aeroplane 1  it detects the reflected signal from the aeroplane t seconds 1 later.  calculate the distance of aeroplane from the radar,s by 1 using formula s = vt/2, where v is the speed of microwaves in air. 4
  13. 13. AnswerNo Answer Scheme Scheme Modification Explanation  Shape of the boat is  To reduce the water resistance / drag streamline  Material used is  Can withstands high water pressure strong  Uses ultrasonic  Have high energy / sounds can travel at further waves distance  Put fish in a  Ice has larger latent heat / ice can absorb a large polisterine box quantity of heat from fish as it melts / fish can be containing ice kept at a low temperature for an extended period of time  Made of fiber glass  The boat is lighter / less dense material 10 TOTAL 20QUESTION 11No Answer Scheme Mark11(a) Volume = area x height 1 1st : pressure of air is inversely proportional to the volume of air 2nd : the pressure inside the air bubbles is equal to the water pressure which is high at the bottom(b) 3rd : so the volume of air bubbles is small. 4 4th : as air bubble goes up to the surface, the pressure decreases., so the volume of air bubbles increases. 1st : safety valve is needed 2nd : to releases extra steam so that the pressure is the cooker does not reach a dangerous stage 3rd : Thickness of the pot is high(c) 4th : to withstand high pressure 10 5th : specific heat capacity of the pot is low 6th : heats up quickly and food will be cooked faster 7th : specific heat capacity of the handle is high
  14. 14. No Answer Scheme Mark 8th : heats up slowly and can be held with bare hands 9th : K is chosen 10th : Reasons: It has a safety valve, high thickness, low specific heat capacity of the pot, high specific heat capacity of the handle 1st : P1= 75 cm Hg, V1 = 10 cm 2nd : P2 = 75 + 3 = 78 cm Hg(d) 3rd : P1V1 = P2V2 5 4th : (75)(10) = (78) (V) 5th : V2 = 9.62 cm TOTAL 20
  15. 15. QUESTION 12
  16. 16. ExerciseNo Answer Scheme Marka The force that gravitation exerts upon a body 1 Stone is denser than water When the stone is immersed in the water , it experienced buoyant force, Fb 4 The tension which is the reading of spring balance, T = W-F Archimedes’ Principle i. ii. (44-36) = 8 Nc iii. F = Vg 5 V = F/(g) = 8/(103 x 10) = 8x10-4 m3 Characteristics Explaination Denser material So the hydrometer stand up right Large diameter of bulb Displaced more acid// stay floating Long hydrometer To measure wide range of density of acidd 10 Glass hydrometer Does not react with acid The best choice is U because it is denser material, large diameter of bulb, long hydrometer and glass hydrometerSECTION III– UNDERSTANDING (Paper 2 Section B and C)Question 1 [ Introduction to Physics ] 1. Consistency is the ability of the instrument to give the same readings close to each other when repeated measurement are done 2. each measurement with little deviation among readings/ draw diagram bulls eye target. 3. Accuracy is the ability of an instrument to give a measured reading to the actual reading. 4. The value determined is accurate if it is near to the actual value/ draw diagram bulls eye target.Question 2 [Forces and Motion]1. Fuel burns in the combustion chamber2. Hot gases expelled at high speed / high momentum3. A large downwards momentum is produced4. The rocket gains upwards momentum of equal magnitude.Question 3 [Forces and Motion(i) Elasticity is the property of matter to return back to its original size or shape when the force thatacting on it is removed(ii)1. There are two types of force; attraction and repulsive force between the particles of the solid. 2. When the solid is stretched, the molecules displaced away from each other 3. Attractive forces are acting to oppose the stretching 4. When the solid is compressed, the molecules displaced closer to each other 5. Repulsive forces are acting to oppose the compression
  17. 17. Question 4 [Forces and Motion] (ii) The force forward = friction The resultant force is zero The object move with constant velocityQuestion 5 [Forces and Pressure] 1. High altitude has low density of air 2. Air molecules has low temperature / low kinetic energy 3. Less collision of air molecules with surface 4. Rate of change of momentum decreases.Question 6 [Forces and Pressure] 1. When air is pumped out , pressure inside decrease. 2. Atmospheric pressure outside is higher 3. Difference in pressure produces a forceto lift the mirror 4. Force is greater than the weight of the mirror.Question 7 [Forces and Pressure] (a) (i) Archimedes’ Principle states that buoyant force equal to the weight of fluid displaced. (a) (ii) 1. Volume of air displaced equal to volume of aballoon 2. Density of air decreased as a altitude increase 3. Weight of displaced air becomes smaller 4. At certain height weight of displaced air equal to weight of the balloon.Question 8 [Forces and Pressure] 1. Hydrometer displaces water. 2. Weight of water displaced equal to weight of hydrometer. 3. The denser the liquid is, the less volume of water displaced. 4. Hydrometer will float higher.Question 9 [Heat] (i) Thermal equilibrium occurs when the net transfer of heat between two objects in thermal contact is zero. (ii) 1. Thermometer is placed in the boiling water. 2. Heat is transferred from boiling water to the thermometer3. Thermal equilibrium between the thermometer and boiling is reached when thenet rate of heat transfer is zero.4. The thermometer and the boiling water are at the same temperature.
  18. 18. Question 10 [Heat]1. Molecules moving freely in random motion2. When temperature increase, kinetic energy//velocity increase3. Molecules strike the walls of pressure cooker more frequently The rate of change of momentum increase4. Force exerted on the walls increase, pressure (P = F/A) increaseQuestion 11 [Heat] 1. The specific heat capacity of the land is less than sea water. 2. During daytime, the land warms up faster than the sea. 3. Air above the land becomes hot and less dense, so it will rise up. 4. The cooler air from sea moves to the land.Question 12 [Light] 1. The air close to the surface is much colder than the air above it 2. Light travels from denser to less dense medium 3. Light rays refracted away from normal line and bend downward toward the surface/total internal reflection occur. 4. The observer will see the image of the ship due to light travels in a straight line.Question 13 [Light]1. The parallel rays of the sun will pass through the a convex lens2. After entering the lens, the light rays is focused at the principal focus of the lens3. At the principal focus, the light ray is focused on one small area4. Heat energy causes an increase in temperature, the paper starts to burnQuestion 14 [Waves](i) Sonar is a reflected ultrasonic waves. (ultrasonic echoes)(ii) ultrasonic wave has a higher frequency waves , it has more energy so it can move further it do not produce noise(iii) 1. attach ultrasonic transmitter to a ship2. use a microphone receiver to detect ultrasonic pulses3. direct the ultrasonic pulses from the transmitter to the seabed4. use microphone receiver to pick up the reflected pulses from the seabed5. measure the time taken by the pulses to travel to the seabed and return v x t6. calculate the depth of the water using the formula d 2Question 15 [Waves]1. The airplane engine produces noise which cause the air to vibrate2. All particles in a material/matter/glass vibrate at its natural frequency3. Due to resonance, the glass vibrate at a higher/maximum amplitude4. Need strong glasses to withstand the effect of resonance/ the strong vibration/ high amplitude, so that it does not break easily.Question 16 [Electricity]1. A parallel circuit can run several devices using the full voltage of the supply.2. If one device fails, the others will continue running normally3. If the device shorts, the other devices will receive no voltage, preventing overload damage.4. A failure of one component does not lead to the failure of the other components.5. More components may be added in parallel without the need for more voltage.
  19. 19. Question 17 [Electricity]1. The two dry cells are connected in parallel2. The effective e.m.f. remains the same3. The effective internal resistance of the two cells is smaller4. A larger current will flow through the bulb to make it brighterQuestion 18 [Electromagnetism]1. When the switch is on, the soft iron core becomes electromagnet. End A becomes north pole.2. End B becomes south pole3. Magnet P repels from end A4. Magnet Q attracts to end BQuestion 19 [Electromagnetism]1. The (magnadur) magnets produce a magnetic field / diagram2. The current in the wire produces a magnetic field / diagram3. The two magnetic fields interact/combine to form a resultant / catapult field / diagram4. Same direction of magnetic field produces stronger resultant magnetic field. Opposite direction cancel each other and produce weaker magnetic field. S NQuestion 20 [Electromagnetism]1. When too high current flow, magnetic field strength become very strong / wire expand2. electromagnet pull the soft iron armature / pulled to the right by spring P.3. release the catch, contact separate and current does not flow4. When reset button is pressed, spring Q pulls the soft iron armature back to its original positionQuestion 21 [Electromagnetism] (i) Ideal transformer is when the efficiency is 100% / power output equal to power input (ii) 1. When a.c. voltage is supplied to primary coil, (alternating current will flow) and the softiron core is magnetized.2. The magnet produced varies in magnitude and direction.3. This causes a changing magnetic flux pass through the secondary coil.4. An induced e.m.f. across the secondary coil is producedQuestion 22 [Electromagnetism] 1. Electric supply is continuous 2. Electric supply idepends on region, the region like city needs more electric supply than interior region. 3. Peak hour need more electric supply. 4. If one region black out, the source of electric supply can be taken from another region. 5. Reduce the cost. 6. Easy to manage and to repair * Choose any FOUR from the list.
  20. 20. Question 23 [Electronic] 1. Connect the dry cell terminal to the Y-input of CRO. 2. The Y-gain setting is recorded 3. The vertical displacement is measured = h. 4. Potential difference = ( Y-gain scale) x (Vertical displacement of direct current wave)Question 24 [Radioactivity]1. Put the radioactive source opposite the detector2. Detector is connected to the thickness indicator3. Detector detect the reading of the changes in counts4. Thickness is measured with the thickness indicator. If the reading of the detector is less than thespecified value, the thickness of the paper is too tick/ vice versaQuestion 25 [Radioactivity](a) Unstable isotopes which decay and emit radioactive particles / ray(b)1. Radioisotope is injected into the pipe2. G-M tube as detector is used to find the leakage3. Reading on detector increases when near a leakageQuestion 26 [Radioactivity]1. Neutron bombarded a uranium nucleus and produced three neutral2 The new neutron bombarded a new uranium nucleus3. For every reaction, the neutrons produced will generate a chain reaction4. Diagram of chain reaction
  21. 21. SECTION IV – DECISION MAKING (Paper 2 Section A – Question 8; Section C )Question 1Characteristics ExplanationStreamlined shape To reduce water resistanceHigh strength of metal To withstand high water pressureWide base cross section area So that ship can float / prevent from overturn // ship more stable // ship not sink deeperHigh volume of air space in the ship Increase buoyant forceStructure U Because it has streamlined ship, high strength of metal, wide base cross section area, high volume of air space in the ship.Question 2 [Force and Pressure]Specification ReasonStraight cut shape bottle Move faster/increase the speedThe body is streamline shape Reduce air frictionThe angle of launching is 450 The rocket can achieve maximum distanceThe volume of water 1/3 of the bottle To produce optimum momentum/speedThe rocket has functional fins Increase stabilityThe best water rocket is T,because it has straight cut shape, body is streamline, angle of launching is 450 the volume of water is1/3 of the bottle and the rocket has functional fins.Question3 [Force and Pressure] Specification ReasonWith ABS To reduce jerking when it stopped immediately / can be controlled if direction changes / does not move side waysWide tyres Better support / more stable / safer when turnLow mass Lighter, can move faster / low inertiaLow seat height Lower centre of gravity / more stableC because it has ABS, wider tyres, low mass, low seat height.Question 4 Specification ReasonHigh specific heat capacity The rate of temperature increased caused by friction is lowHigh melting point Does not easily change in shape when the temperature is highDifficult to compress Pressure will be transmitted uniformly in all directions.Use ceramic Can withstand high temperature // less dust producedS because it has high specific heat capacity, high melting point, difficult to compress and use ceramic.Question 5Specification ReasonSize of the tyre is large Prevent backhoe from sinking into soft ground Not easy compress compared to the gases // highFluids used in hydraulic system is liquid powerLarge mass Avoid backhoe from movingLarge base area Ensure that the backhoe will not collideSULIT 21
  22. 22. Centre of gravity is low More stableThe most suitable backhoe is M.Large tyre, fluids use in hydraulic system is liquid, large mass, large base area and the centre of gravityis low.Question 6 [Force and Pressure]Specification ReasonA shape of cross section which is upper side is To produce the speed of airflow above the wingshigher Than the bottom//aerofoil to be higher than the speed of air belowLarge area of the wing The larger the lift forceLow density of the wing material Less weight// produce more upward forceThe higher the difference in speed of air The higher the difference in pressureP was chosen because shape of aerofoil,large area of the wing,Low density of the wing and the higher the difference in speed of airQuestion 7[Force and Pressure]Specification Reason Produced bigger buoyant force / displaced moreVolume of the balloon is bigger volume of airMaterial used for balloon is nylon Stronger / does not break easily Lighter / low mass / increase the time impact /Material used for basket is rattan reduce impulsive force Reduce the density of air / reduce the mass of airTemperature of air inside the balloon is higher in the balloon / increase upward resultant force / can carry more loadThe best chosen is K because volume of the balloon is bigger, material used for balloon is nylon,material used for basket is rattan and temperature of air inside the balloon is higherQuestion 8[Heat]Specification Reason It will not easily change into gas when absorb heatHigh boiling point from the engine It will not freeze during cold weather // can flow atLow viscously low temperature It can absorb a big quality of heat with small rise inHigh specific heat capacity temperature The metal parts of the engine will not corrodeA low ability to react with metals easilyK because of its high boiling point, low viscosity, high specific heat capacity and low ability to reactwith metals.Question 9 [light]Specification ReasonType of objective lens is convex lens To converge the light and produce real imageFocal length of the objective lens is big To get higher magnification powerD < f0 + fe To get virtual and magnified image More light can be captured, the image formed isDiameter of the objective lens is large brighterLens S because lens used is convex lens, focal length of the objective lens is big, D D < f 0 + fe anddiameter of the objective lens is large.SULIT 22
  23. 23. Question10 [Electricity]Specification ReasonThin diameter High resistanceCoil wire Increase length / resistanceParallel arrangement If one panel not function, others still functionHigh melting point Withstand high temperatureG, because thin diameter, coil wire, parallel arrangement and high melting point.Question 11Characteristics ExplanationCurved shape Produce radial magnetic fieldSoft iron Easily to magnetized and demagnetized Can detect small current // more sensitive // canSoft spring measured small current Uniform deflection // force produced directlyLinear scale proportional to current.T is chosen because curved shape, soft iron, soft spring and linear scale.Question 12Specification ReasonLow resistivity to reduce heat loss in the cablesLow density The cables will be lighterLow rate of oxidation Not easily rust / corrodeLow rate of thermal expansion The cables will not expand under hot weatherCable Q because it has low resistivity, low density, low rate of oxidation, low rate of thermal expansion.Question 13Specification ReasonLow density of the coil Lighter // less mass The rate of change of magnetic field, moreHigh frequency of rotation current inducedUse 4 diodes Full wave rectification to get a d.cHeat capacitor in the circuit To smooth the direct current obtainedCircuit I because it has low density coil, high frequency of rotation, consist 4 diodes and has capacitorin the circuitSULIT 23
  24. 24. Question 14Specification Reason When it is doped, the conductivity of theThe valency of the intrinsic semiconductor is 4 semiconductor increases Valency of 3 is used to produce hole as majority charge carrier (P type) and valency of 5 is used toThe valency of the doping substance are 3 or 5 produce electron as majority charge carrier (N type) Can maintain the crystallize structure of theSize of the atom of the doping substance is almost substance / give good effect in the dopingsame as the size of the substance processSubstance T because the valency of the intrinsic semiconductor is 4, the valency of the dopingsubstance are 3 or 5 and the size of the doping substance is almost the same as the size of thesubstance.The type of pure semiconductor is silicon because it has greater power handling (not easy overheated.Question 15 [radioactive]Specification ReasonGamma Has high penetrating powerLong half life Long lastingSolid Easy to handle Does not ionize healthy cells / does not cause cellLow ionizing power mutationK is chosen because it radiated gamma ray, the half life is long, the state of matter is solid and has lowionizing power.uestion 16 [Radioactive]Specification ReasonType of ray is Alpha Stronger ionizing powerLong half life Long lastingState of matter is solid Easy to handle / does not spill or evaporateLogic gate: NOT To inverse inputL is chosen because type or ray is alpha, long half life, solid and use logic gate NOTSULIT 24
  25. 25. SECTION V– CONCEPTUALIZATION (Paper 2 Section A – Question 5/6; Section B )Question 1 [Force and Pressure] 1. Density of sphere A is less than B 2. Weight A is less than B 3. The weight of water displaced by A is less than B 4. The larger the weight of sphere, the bigger the weight of water displaced 5. Weight of water displaced = upthrust // When the weight of water displaced increase, upthrust increaseQuestion 2 [Force and Pressure] (a) Density is mass per unit volume (b) i Level of the boat is higher in the sea than in the river. ii Water displaced in the sea is less than in the river. iii Density of sea water is higher than river water. (c) i The lower the density of water, the greater the volume of water displaced. ii Weight of the boat = Weight of the water displaced (d) Archimedes’ principleQuestion 3 [Heat] (a)(i) The temperature of air increase The volume of air increase (ii) The mass of air constant(b)(i) When the temperature increase the volume of air increase (ii) Charles’ Law(iii) Temperature increases, kinetic energy increases The rate of collision between molecules and wall increases/ pressure increases To keep the pressure constant, volume increases/expandQuestion 4 [Waves](a) Length between the two crest / trough / consecutive wave front(b) (i) Wavelength in Diagram 4.2 is greater than 4.1 (ii) Wavelength remains constant after passing through the gap(c) Curvature of the wave pattern in Diagram 4.2 is greater(d) The greater the wavelength, the more circular the wave pattern(e) DiffractionSULIT 25
  26. 26. Question 5 [Electromagnetism](a) Diagram 5.1 has less number of turns compare to Diagram 5.2 Deflection of pointer in Diagram 5.1 is smaller than Diagram 5.2(b) P = North Q = South(c) The larger the number of turns, the higher the induced current produced(d) Faraday’s Law(e) Increase the speed of the relative motion between the coil and the magnet // Use a stronger magnet(f) Direct Current Generator (D.C. Dynamo) //Alternating Current Generator (A.C. Dynamo) // Moving coil microphone // TransformerQuestion 6 [Force and Motion](a) The energy an object has because of its position.(b) Load in Diagram 6.1 is higher than in Diagram 6.2. Gravitational potential energy in Diagram 6.1 is higher Work done in Diagram 6.1 is greater The higher the position of the load, the greater the work done The greater the work done, the greater the gravitational potential energy // Work done = gravitational potential energyQuestion 7 [Force and Motion]1. Mass of the coin is greater than the leaf2. Both objects reach the ground at the same time3. The falling position of both objects is the same4. Gravitational acceleration is the same5. Gravitational acceleration does not depend on massQuestion 8 [Force and Pressure]1. Reading of spring balance in the oil/Diagram 8(c) is greater than in the water/Diagram 8(b)2. Weight lost in the water/Diagram 8(b)is greater than in oil/Diagram 8(c) // vise versa3. Density of water is greater than density of oil4. The greater the density of liquid, the greater the weight lost5. The greater the density of liquid, the greater the buoyant forceSULIT 26
  27. 27. Question 9 [Force and Pressure]1. Density of air in Diagram 9(a) is higher than in Diagram 9(b)// vice versa2. The number of load in Diagram 9(a) is greater than in Diagram 9(b)// vice versa3. The height of the balloons in both Diagram 9(a) and Diagram 9(b) are equal4. When the density of the air increase, the buoyant force increase5. As the density of the air increase, the weight of the load carried increased// . As the density of the air decrease, the weight of the load carried also decreasedQuestion 10 [Force and Pressure]1. The mass of the fish is the same2. The volume of the fishing net immersed in the water is the least in Diagram 10.3 and the largest in Diagram 10.13. When the weight of water displaced is smaller, the force needed is greater4. Buoyant force is equal to weight of water displaced5. The greater the weight of water displaced, the greater the buoyant forceQuestion 11 [Light]1. Density of glass block in Diagram 11(a) is smaller than density of glass block in Diagram 11(b)2. Refractive index of glass block in Diagram 11(a) is smaller3. Angle of refraction in Diagram 11(a) is greater than angle of refraction in Diagram 11(b)4. The higher the density, the smaller the angle of refraction5. The higher the refractive index, the smaller the angle of refraction.Question 12 [Light]1. Lens K is thicker than lens J2. Light ray refracted more in lens K than lens J.3. Focal length of lens K is shorter than lens J.4. The thicker the lens, the greater the light refracted5. The thicker the lens, the shorter the focal lengthSULIT 27
  28. 28. Question 13 [Light]1. Distance between the double-slit and screen, D, i n Diagram 13.1(a) is smaller2. Distance between two successive bright fringes, x, in Diagram 13.1(b), is smaller3. The number of fringes in Diagram 13.1(b) is bigger4. The width of fringes in Diagram 13.1(b) is smaller5. When the distance between the double-slit and screen, D, increases, the distance between two successive fringes, x, increasesQuestion 14 [Waves]1 . Number of oscillations in Diagram 14(a) is greater than in Diagram 14(b)2. The amplitude of the wave in Diagram 14(a) is the same as in Diagram 14(b)3 . The diameter of guitar string in Diagram 14(a) is smaller than diameter of the string in Diagram 14(b)4. When the diameter of the string increases , the frequency of the wave decreases5. The higher the frequency , the higher is the pitch// As the frequency of the sound decreases, the pitch of the sound also decreasesQuestion 15 [Electricity]1. Diagram 15.1 connected in series and Diagram 15.2 connected in parallel2. The reading of ammeter in Diagram 15.2 is greater than in Diagram 15.13. The reading of voltmeter is the same4. The effective resistance in Diagram 15.2 is smaller than in Diagram 15.15. When the effective resistance increases, the current flow decreases.6. When the circuit is in parallel connection, the effective resistance is smallerQuestion 16 [Electromagnetism]1. The N-pole in Diagram 16(a) moved into the solenoid, the N-pole of the magnet in Diagram 16 (b) moved away from the solenoid.2. The galvanometer pointer in Diagram 16(a) deflects to the right, the galvanometer pointer in Diagram 16(b) deflects to the left.3. When N-pole is moved into the coil, the top of the coil is a N-pole, and tends to repel the magnet4. When the N-pole is moved away from the coil, the top of the coil is a S-pole, and thus attracting the receding N-pole.5. Lenz’s Law which states that the direction of the induced electromotive force acts in such a way as to oppose the action which produces itSULIT 28
  29. 29. Question 17 [Electronic]1 The bulb in Diagram 17.2 does not light up while the bulb in Diagram 17.1 lights up2. In diagram 17.2 the negative terminal of the cell is connected to the anode.3. When the anode of the diode is connected to the positive terminal of a cell, the bulb lights up4. When the diode is in forward bias connection, the current flow5. Diode allows current to flow in one direction onlyQuestion 18 [Radioactivity](ii). Difference: Nuclear fission involves the fission of heavy nucleus. Nuclear fusion involves the combination of light nuclei Similarities: Decrease/loss of mass after the process occurs. Neutrons are produced. E = mc2 // loss of mass/ mass defect directly proportional to the energy released .Question 19 [Radioactivity]1. Exponential graph2. The time taken for the activity to become half of its initial value is constant3. The time taken for the activity of P to be half of its initial value is constant //5 hrs4. The time taken for the activity of Q to be half of its initial value is constant //100 s5. Half-lifeVI – PROBLEM SOLVING [QUALITATIVE] (Paper 2 Section A: Question 7; Section BQuestion 9/10 )QUESTION 1 Suggestion Reason Thermometer is made from transparent It is not easily broken glass that is strong The capillary tube is made narrow and It is more sensitive thin The shape of the thermometer is It has a magnifying effect round/streamline It can measure very low temperature/ not freeze at low The liquid has low freezing point temperature Thin glass bulb’s wall Absorb / transfer heat fasterSULIT 29
  30. 30. QUESTION 2 Suggestion Reason Aerodynamic shape / stream line/ Reduce air resistance torpedo Low density material // Lighter // Strong material// high boiling point Does not break easily// does not melt easily Boosting combustion // supply oxygen for combustion Has liquid oxygen Retro rocket /Has several stages that To decrease mass can slip/strip off Increase the size of combustion More space for the fuel to be burnt chamberQUESTION 3Suggestion ReasonStrong material Do not break easilyLow density Small mass / lighter //o increase the accelerationStreamline javelin To reduce air resistanceThe athlete runs with high speed /has to To increase kinetic energy/energy/force/ momentumincrease his speed/accelerationThrow at an angle of 45o / Throw with To get maximum horizontal distance of throwinga great forceQUESTION 4 Suggestion ExplanationShape of the shuttle – conical shape /oval Allow for better / fast air flow//produce more lift force ///diagram / aerodynamic reduce air resistanceMaterial used for shuttle – feather / small Light// high velocity/ acceleration //further distancemass/ low density travelled//reduce inertia // smaller massMaterial used for base of the shuttle – Light// high velocity/ acceleration //further distancecork/ small mass/ low density travelled//reduce inertia // smaller massMaterial used for the string of the racquet – Not easily broken //withstand high forcestrong/ low elasticityHigh tension Short time impact// high impulsive forceSULIT 30
  31. 31. QUESTION 5 Suggestion Reason To create sufficient buoyant force due to greater Balloon should be large size1 weight of surrounding air displaced. Balloon material is made of light weight The total weight of the balloon is less than the2 material like nylon buoyant force//reduce weight Balloon material should also have a high3 It will not disintegrate when exposed to hot air melting point. The part of the balloon (the skirt) near the4 burner must be fire resistant /coated with fire So that it doesn’t catch fire easily resistant material5 The burner burns (liquefied) propane/gas Warms up the air in the balloon6 A large fan is needed initially To blow enough air into the balloon The basket must be made off light and Prolong the collision time between basket and7 flexible/safe material (e.g. rattan or cane ground// reduce impulsive force when basket hits woven) the ground Best times to launch the balloon are early9 morning and late afternoon when the air is Cool air is denser, providing more buoyant forc coolerQUESTION 6 Suggestion ReasonSpecific heat capacity of the wok is low Heat up faster / temperature increase fasterThermal conductivity of the wok is high Can conduct heat fasterMelting point of wok is high Can withstand high temperatureSpecific heat capacity of the oil is low Heat up faster Will not change to vapour easily // cooking at higherBoiling point of oil is high temperatureSULIT 31
  32. 32. QUESTION 7Suggestion ReasonPut ice in the cointainer Ice absorbs heat out from the packet drinks.Add a little water to the ice Heat transfer is faster through the heat conduction.Container has high specific heat capacity Heat up slower.White container Does not absorb heatInsulator // low density Avoid absorb heat from outside into the container // lighterQUESTION 8Modification Reason Sunlight ray will converge / focus to the tank // absorb moreConcave mirror heat Reflect more light /focus light at shorter distance// reduceRadius of curvature is smaller energy lostBlack Absorb more heatLow specific heat capacity The temperature rise up fasterBigger size Receive/collect more lightQUESTION 9Suggestion ReasonConvex mirror The image formed is virtual, upright an diminishedLarge diameter Wider field viewstrong Withstand change in weather / does not break easilyLess thickness Avoid multiple image formed / clearer imageAt the sharp corner Can reflect the light from opposite directionSULIT 32
  33. 33. QUESTION 10Suggestion Reason Longer wavelength/ diffraction easierFrequency of signal is low no blocking / capture more signalThe location of transmitter higherthe number of transmitter is more / increase the strength of signal/ increase energy of signal /many reduce energy lost during transmission have more energy / can move furtherThe strength of signal is higherThe distance between two transmitter increase the strength of signal/ increase energy of signalis closerQUESTION 11 Suggestion ReasonAttach switch for each lamp To allows each lamp to be switched on and off independentlyConnect the metal fitting lamp to the To flows electron (extra) to earth to avoid lethal shockearth wire/cable Voltage across both bulbs is 240 V / if one bulb blows anotherParallel bulb can still function.Using only 240 V light bulb To ensure the bulbs light up with normal brightnessStep down transformer / adapter Reduce the voltage from 240 V to 12 V.QUESTION 12Suggestion ReasonSoft spring Give a greater sensitivity/ can detect small changesSmall density Small mass / light Radial magnetic field, create uniform strength of magneticCurve in shape of the magnet field around the coilcopper coil To reduce energy loss / Low resistance material of the coilPlace the seismometer in direct to convert very small motions of the earth into electrical signalscontact with the earthSULIT 33
  34. 34. QUESTION 13 Suggestion ReasonOR gate The gates output is ON if either one sensor is ONThermistor Resistance decrease when temperature increase Base voltage increase, when the temperature increase.At R1 and R2 Base current flows, collector current flows. Alarm will triggered. It converts the electrical signal into sound energy/ AlarmReplace the lamp or at the collector circuit triggered when collector current flow.Relay switch To switch on the alarm which is use a greater voltageQUESTION 14Component FunctionFilament To heat up the cathodeCathode Emits electrons Controls the number of electrons//Control Grid control the brightness of the image on the screenFocusing anode Focuses the electrons into a beamAccelerating anode To accelerate electrons to towards the screenY-plates To deflect the electron beam vertically To deflect the electron beamX-plates HorizontallyQUESTION 15 Suggestion ReasonUse forcep/robot The distance between the source and the body is farWear a mask/goggle The radiation does not penetrate our eyesUse a lead box/container with thick To prevent radiation leakage to surroundingsconcreteKeep the exposure time as short as The body is not exposed to the radiation for a long timepossibleWear a film bandage To detect the amount of radiation exposedPut radiation symbol on the storage box To inform the users of dangerous contents of the boxWear coat lined with lead To protect the body from the radiationSULIT 34
  35. 35. SECTION VII– PROBLEM SOLVING [QUANTITATIVE] (Paper 2 Section C Question 11/12 )1. (i) impulse = mv – mu = 1.5 ( -35-40) = 112.5 kg ms-1 (ii) Impulsive force = mv-mu t = 140.625 N2. (i) 900 N (ii) F – 900 N = 1000 (2) F = 2 900 N3. (i) v = 18 x1000 = 5 ms-1 60 x 60 a =v – u t =5 –0 10 = 0.5 ms-2 (ii) F = ma = ( 202) (0.5) = 101 N4. (i)Spring constant P , k =F = 6N x 12 cm = 0.5 Ncm-1 Spring constant Q, k = F = 3N x 12 cm = 0.75 N cm-15. (i) Buoyant force = weight of the boat ρV g = 250 (10) V = 0.25 m-3 (ii) Weight of the boat + weight of the load = buoyant force 2500 + WL = 1000 (4) (10)SULIT 35
  36. 36. WL= 40 000 – 2500 = 3 7500 N Mass of load = 3 750 kg6. (i) F = 500 x 40 = 20 000 N (ii) Resultant force = 20 000 – 800 (10) = 12000 N (iii) F = ma a = 12 000 800 =15 ms-27. (i) F1 = F2 A1 A2 F2 = 6N ( 1.2) 0.2 = 36 N (ii) V1 = V2 A1h1 = A2h2 h2 = 1.2 (0.2) 1.2 = 0.2 cm8. (i) F = ρVg = 1020 (2)(10) = 20 400 N (ii) Buoyant Force = weight of the boat + weight of the box 20 400 N = 15 000 + W W = 5 400N9. (i) Mass,m =ρV = 800 x 0.004 = 3.2 kg (ii) Pt = mc 2 500 (t) = 3.2 (2 000) (130) t = 332.8 sSULIT 36
  37. 37. 10. (i) 1/f = 1/u+1/v 1/-15 = 1/20 + 1/v v = - 8.6 cm (ii) Magnification = v/u = 8.6 / 20 = 0.43 (iii) virtual, upright and diminished11. (i) 1/f = 1/v + 1/u 1/5 = ½ +1/v 2 v = -3.33 cm 2 (ii) m = v/u =3.33/2 = 1.67 times sin 𝑖 1 (i) 𝑛=12. sin 𝑟 1 sin 𝜃 1 1.5 = sin 30 𝑜 1 sin  = 0.75 1  = 48.6o 1 (ii) 𝑛= sin 𝑐 1 1.5 = sin   = 41.8 oC sin 𝑏 (iii)1.5 = sin 40 𝑜 sin b = 0.9642 b = 74.6o β = 15.4o 213. (i) 4 cm 1 (ii) 5 Hz 2 (iii) 20 cm s-114. (i) Np= VpSULIT 37
  38. 38. Ns Vs = 240 12 = 20 Ratio = 20 : 1 (ii) P = IV I = 60 /12 =5A (iii) 80 = Po x 100 Pi 80 = 60x 100 Ip (240) Ip = 0.3125A 15. eV = ½ me v2 1.6 x 10-19 (3 x 103) = ½ (9.0 x 10-31) v2 v = 3.27 x 107 m s-1(i) 16. (i) 1 ½ ¼ 1/8(ii)(iii) 3T½ = 3 X 8 days = 24 days (ii) 32 days = 32/8 = 4 T½ 20 mg 10 mg 5 mg 2.5 mg 1.25 mg or (½)4 X 20 = 5/4 = 1.25 mg SECTION VIII A – Paper 3 Section A Question 1 a (i) Angle of incidence / i (ii) Angle of refraction / r // sin r (iii) Refractive index of the glass block (b) & (c) i sin i r sin r 15o 0.2588 11o 0.1908 SULIT 38
  39. 39. 30o 0.5000 20o 0.3420 45o 0.7071 29o 0.4848 60o 0.8660 36o 0.5878 75o 0.9659 41o 0.6561(d) Draw graph sinr against sin i corecltly(e) sin i is directly proportional to sin rQuestion 2 QUESTION ANSWER MARK a) (i) d increases as t increase 1 1  Draw a dotted line at t = 0.4 s (show on the graph) a) (ii)  d = 0.46 m 1 (answer + unit)  Draw a tangent line at t = 0.5s  Draw a big triangle (shown on the graph) 15 PQ 1.64 - 0 1 b) (i) Gradient, m = = QR 0.7 – 0.31 1 (shows the working) -1 = 4.2051 ms 1 2m (2)( 4.2051) 1 (substitution) b) (ii) a = = T 0.5 (correct answer + unit; 2 to 4 1 d.p.) c) (i) Velocity 1 (answer + unit) -2 = 16.8204 ms c) (ii) Velocity increases as time increase 1SULIT 39
  40. 40. QUESTION ANSWER MARK Avoid parallax error by making sure the eye is perpendicular to the scale of d) 1 metre rule when measuring displacement TOTAL 12SULIT 40
  41. 41. SECTION VIII B– EXPERIMENT (Paper 3 Section B)Question1 [Force and Motion] No Answer Inference The force affects the acceleration (a) (b) Hypothesis The greater the force, the greater the acceleration (c) i. Aim To investigate the relationship between the force and the acceleration ii. Variables Manipulated variable : Force. F (weight of the load) Responding variable : acceleration, a Fixed variable : Mass of the trolley, m iii. List of apparatus and materials A trolley, runway, ticker- timer, ticker-tape, power supply,metre rule and wooden block States the workable arrangement of the apparatus a.c power supply Set up Set up the apparatus as shown in the diagram. States the method of controlling the manipulated variable Use load of F = 0.5 N to pull the trolley down the runway. States the method of measuring the responding variable Switch on the power supply and release the trolley. Cut the ticker tape into 5-tick strips and a tape chart for the motion of the trolley is made. v u Calculate the acceleration of the using a  and record the data. tSULIT 41
  42. 42. No Answer Repeat the experiment at least 4 times Repeat the experiment by using F = 1.0 N, 1.5 N, 2.0 N, 2.5, N and 3.0 N. Tabulating of data Force, F/ N acceleration , a /cms-2 0.5 1.0 1.5 2.0 2.5 3.0 State how data will be analysed Plot graph of acceleration against Force a/cms-2 F/NSULIT 42
  43. 43. QUESTION 2 (FORCE AND MOTION) No Answer (a) Inference The mass affects the acceleration (b) hypothesis The greater the mass, the smaller the acceleration (c) i. Aim To investigate the relationship between the mass and the acceleration ii. Variables Manipulated variable : mass. m Responding variable : acceleration, a Fixed variable : Mass of the trolley, m A trolley, runway, ticker- timer, ticker-tape, power supply,metre rule and wooden block iii. List of apparatus and materials States the workable arrangement of the apparatus a.c power supply Set up the apparatus as shown in the diagram. Use load of F = 0.5 N to pull the trolley down the runway. States the method of controlling the manipulated variable Use trolley with the mass, m = 500 g States the method of measuring the responding variable Switch on the power supply and release the trolley. Cut the ticker tape into 5-tick strips and a tape chart for the motion of the trolley is made. v u Calculate the acceleration of the using a  and record the data. t Repeat the experiment at least 4 timesSULIT 43
  44. 44. No Answer Repeat the experiment by using m = 1000 g, 1500 g, 2000 g and 2500 g Tabulating of data Mass, m/ g acceleration , a /cms-2 500 1000 1500 2000 2500 3000 State how data will be analysed Plot graph of acceleration against Mass a/cms-2 m/gQuestion3 [Force and Motion] No Answer (a) Inference The speed affects the position of the driver when the car stops suddenly (b) Hypothesis The greater the speed, the longer the distance to stop (c) i. Aim To investigate the relationship between the speed and the distance ii. Variables Manipulated variable : the height , h (the more the height, the greater the speed) Responding variable : the distance, s Constant variable : the mass, m iii. List of apparatus runway, load, trolley, ticker timer and ticker tape, power supply, metre rule. and materialsSULIT 44
  45. 45. No Answer Labeled diagram: Inclined plane s h Measure the height, h =10.0 cm of the inclined plane from the surface. Let the trolley moves down the inclined plane. h Calculate the speed of the trolley, v from the ticker tape obtained. s Measure the forward distance of the load, s Repeat the experiment with h = 15.0 cm, 20.0 cm, 25.0 cm, 30.0 cm and 35.0 cm. height, h / Forward distance, s speed, v (cms-1) cm (cm) 10.0 15.0 20.0 25.0 30.0 35.0 The graph(axis) of s against v or h is drawn TOTALQuestion 4 [Force and Motion] No Answer (a) Inference The compression of the spring affects the vertical distance of the projectile (b) hypothesis The greater the compression of the spring, the greater the vertical distance of the projectile (c) i. Aim To investigate the relationship between the compression of the spring and the ii. Variables vertical distance of the projectile Manipulated variable : compression of the spring. x Responding variable : vertical distance of the projectile, a Fixed variable : Mass of the ping pong ball, m iii. List of apparatus and materials A spring, ping pong ball,metre ruleSULIT 45
  46. 46. No Answer States the workable arrangement of the apparatus Set up the apparatus as shown in the diagram. States the method of controlling the manipulated variable Compress the spring, x = 1.0 cm with the ping pong ball States the method of measuring the responding variable Release the ping pong ball Measure the maximum distance of the ping pong ball, h using metre rule. Repeat the experiment at least 4 times Repeat the experiment by using x = 1.5 cm, 2.0 cm, 2.5, cm and 3.0 cm. Tabulating of data Compression of vertical distance of the projectile , the spring, x/ cm h /cm 1.0 1.5 2.0 2.5 3.0 State how data will be analysedSULIT 46
  47. 47. No Answer Plot graph of h against x h/cm x/cmQuestion 5 [Force and Pressure] No Answer(a) Inference State a suitable inference The pressure exerted on the surface depends on the area of contact. Hypothesis State a relevant hypothesis(b) When the area decrease, the pressure increases (i) Aim State the aim of experiment To investigate the relationship between the area of contact and pressure (depth of hole). (ii) Variables State the suitable manipulated variables and responding variable (Quantity that can be measured) (c) ( Manipulated variable : Area of contact object. i Responding variable : pressure exerted (depth of hole) ) State the constant variable Force applied (using 1 kg load) (iii) List of State the complete list of apparatus and materials Apparatus and Materials Vernier caliper, soft plasticine, ruler, Load 1 kg, the object with different surface area but same weight. Draw the functional arrangement of the apparatusSULIT 47