Advertisement

Upcoming SlideShare

An example of a job that usually involves a revenue-sharing plan would.docx

Loading in ... 3

Jan. 28, 2023•0 likes## 0 likes

•32 views## views

Be the first to like this

Show More

Total views

0

On Slideshare

0

From embeds

0

Number of embeds

0

Download to read offline

Report

Education

An ideal gas in a sealed container has an initial volume of 2.70 L. At constant pressure, it is cooled to 22.00 Â°C where its final volume is 1.75 L. What was the initial temperature? Solution for an ideal gas PV/T = constant at constant pressure V/T = constant so Vi / Vf = Ti / Tf now Ti = Tf ( Vi / Vf) given Tf = 22 C = 22 + 273 K = 295 K Vi = 2.7 L Vf = 1.75 L plug in the values Ti = 295 K x ( 2.7 L / 1.75 L) Ti = 455.14 K Ti = 455.14 - 273 C Ti = 182.14 C so the initial temperature is 182.14 C .

rtodd988Follow

Advertisement

Advertisement

Advertisement

An example of a job that usually involves a revenue-sharing plan would.docxrtodd988

an equation of the line that contains the origin and the point (1-2) i.docxrtodd988

An equation that defines y as a function of x is given- Solve for y in.docxrtodd988

An equation in three variables has an ordered triple as a solution- Co.docxrtodd988

An experiment is being carried out by two students- Anne tests the fil.docxrtodd988

An engineer claims to have perfected the gasoline combustion engine- A.docxrtodd988

- An ideal gas in a sealed container has an initial volume of 2.70 L. At constant pressure, it is cooled to 22.00 Â°C where its final volume is 1.75 L. What was the initial temperature? Solution for an ideal gas PV/T = constant at constant pressure V/T = constant so Vi / Vf = Ti / Tf now Ti = Tf ( Vi / Vf) given Tf = 22 C = 22 + 273 K = 295 K Vi = 2.7 L Vf = 1.75 L plug in the values Ti = 295 K x ( 2.7 L / 1.75 L) Ti = 455.14 K Ti = 455.14 - 273 C
- Ti = 182.14 C so the initial temperature is 182.14 C

Advertisement