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# an equation of the line that contains the origin and the point (1-2) i.docx ×

# an equation of the line that contains the origin and the point (1-2) i.docx

an equation of the line that contains the origin and the point (1,2) is a. y=2x b. 2y=x c. y=x-1 d. y=2x+1 e. y/2=x-1
Solution
Well so we have 2 points: (0,0) and (1,2). So we can use the slope formula to find the slope of the line. Slope formula: m=(y2-y1)/(x2-x1) m=(2-0)/(1-0) m=2/1 m=2 so the slope is 2. Now we use the standard slope-intercept form equation: y=mx+b In this equation, m is the slope and b is the y-intercept (when x=0). So lets plug in the slope: y=2x+b Now we find the b by plugging in one of the 2 points from above. So I will use (1,2): 2=2*1+b 2=2+b b=0 Therefore, y=2x is the equation through (0,0) and (1,2). Therefore the letter choice is A. y=2x Please Rate Answer!! :)
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an equation of the line that contains the origin and the point (1,2) is a. y=2x b. 2y=x c. y=x-1 d. y=2x+1 e. y/2=x-1
Solution
Well so we have 2 points: (0,0) and (1,2). So we can use the slope formula to find the slope of the line. Slope formula: m=(y2-y1)/(x2-x1) m=(2-0)/(1-0) m=2/1 m=2 so the slope is 2. Now we use the standard slope-intercept form equation: y=mx+b In this equation, m is the slope and b is the y-intercept (when x=0). So lets plug in the slope: y=2x+b Now we find the b by plugging in one of the 2 points from above. So I will use (1,2): 2=2*1+b 2=2+b b=0 Therefore, y=2x is the equation through (0,0) and (1,2). Therefore the letter choice is A. y=2x Please Rate Answer!! :)
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