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an electron is projected in an electric field of 500N - Ci with a spee.docx
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an electron is projected in an electric field of 500N - Ci with a spee.docx

  1. an electron is projected in an electric field of 500N / Ci with a speed of 50km / s i. determine the distance traveled to stop an electron is projected in an electric field of 500N / Ci with a speed of 50km / s i. determine the distance traveled to stop Solution Force on an electron = qE= 1.6×10^-19× 500= 8 ×10^-17N a = 8× 10^-17/9.1×10^-31= 87.9×10^12m/s^2 V^2- u^2 = 2as 0-( 50×1000)^2=- 2 × 87.9 × 10^12× s s = 25× 10^8/2×87.9 ×10^12= 0.14×10^-4m
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