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# An aqueous solution contains 0-332 M ammonia (NH3)- How many mL of 0-.docx

An aqueous solution contains 0.332 M ammonia ( NH 3 ).

How many mL of 0.386 M nitric acid would have to be added to 250 mL of this solution in order to prepare a buffer with a pH of 9.180 ?
Solution
pH of basic buffer= 14 - ( pkb + log(NH4NO3/NH3)
pKb of NH3 = 4.75
no of mol of NH3 present finally = 0.332*0.25 = 0.083-x mol
no of mol of NH4NO3 = HNO3 = x M

9.18 = 14-(4.75+log(x/(0.083-x))
x = 0.0448
no of mol of HNO3 must add = 0.0448 mol
volume of HNO3 must add =0.0448/0.386 = 0.116 L
= 116 ml
.

An aqueous solution contains 0.332 M ammonia ( NH 3 ).

How many mL of 0.386 M nitric acid would have to be added to 250 mL of this solution in order to prepare a buffer with a pH of 9.180 ?
Solution
pH of basic buffer= 14 - ( pkb + log(NH4NO3/NH3)
pKb of NH3 = 4.75
no of mol of NH3 present finally = 0.332*0.25 = 0.083-x mol
no of mol of NH4NO3 = HNO3 = x M

9.18 = 14-(4.75+log(x/(0.083-x))
x = 0.0448
no of mol of HNO3 must add = 0.0448 mol
volume of HNO3 must add =0.0448/0.386 = 0.116 L
= 116 ml
.