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Help story Bookmarks Window saplinglearning.com Hofstra U Sapling Learning-201802.C. Home-hofstra.edu Center Candidate Q > Hw 12 ·CHEM 3A-Spring18-ALBANESE > Activities and Due Dates 5/9/2018 11:59 PM ?Print 6.5/13 5/5/2018 08:00 PM ? Calculator -d Periodic Table uestion 7 of 13 Sapling Learning The rate constant for this second-order reaction is 0.750 M-1 s-1 at 300-C. A ? products How long (in seconds) would it take for the concentration of A to decrease from 0.880 M to 0.210 M? Number O Previous ?Give Up & View Solution Check Answer e Next
Solution
Second order integrated rate constant equation,
1 / [A] = kt + 1 / [A] 0
1 / 0.210 = 0.750 * t + 1 / 0.880
t = time required = 4.83 s
.

Help story Bookmarks Window saplinglearning.com Hofstra U Sapling Learning-201802.C. Home-hofstra.edu Center Candidate Q > Hw 12 ·CHEM 3A-Spring18-ALBANESE > Activities and Due Dates 5/9/2018 11:59 PM ?Print 6.5/13 5/5/2018 08:00 PM ? Calculator -d Periodic Table uestion 7 of 13 Sapling Learning The rate constant for this second-order reaction is 0.750 M-1 s-1 at 300-C. A ? products How long (in seconds) would it take for the concentration of A to decrease from 0.880 M to 0.210 M? Number O Previous ?Give Up & View Solution Check Answer e Next
Solution
Second order integrated rate constant equation,
1 / [A] = kt + 1 / [A] 0
1 / 0.210 = 0.750 * t + 1 / 0.880
t = time required = 4.83 s
.

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Help story Bookmarks Window saplinglearning-com Hofstra U Sapling Lear.docx

  1. 1. Help story Bookmarks Window saplinglearning.com Hofstra U Sapling Learning-201802.C. Home-hofstra.edu Center Candidate Q > Hw 12 ·CHEM 3A-Spring18-ALBANESE > Activities and Due Dates 5/9/2018 11:59 PM ?Print 6.5/13 5/5/2018 08:00 PM ? Calculator -d Periodic Table uestion 7 of 13 Sapling Learning The rate constant for this second-order reaction is 0.750 M-1 s-1 at 300-C. A ? products How long (in seconds) would it take for the concentration of A to decrease from 0.880 M to 0.210 M? Number O Previous ?Give Up & View Solution Check Answer e Next Solution Second order integrated rate constant equation, 1 / [A] = kt + 1 / [A] 0 1 / 0.210 = 0.750 * t + 1 / 0.880 t = time required = 4.83 s

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