I am not sure if I\'m adding these phasors correctly, can someone clarify it for me. Odd these sinusoids using phazers v(+)=27cos(wt - 12degree) + 33sin(wt + 14degree) - 17cos(wt + 6degree) =27 12degree + 33 76degree - 17 6degree 27cos-12degree + 27jsin-12degree+33cos-76degree+33sin-76degree-17cos6degree 26.41 - 5.61j + 7.98-32.02j - 16.91 - 1.78j =17.48 - 39.41j Vs=43.11 66degree Solution yes its correct only 27 /_ -12 + 33 /_ (-90+14) - 17 /_6 splitting into complex form we get = 27 cos -12 + j 27 sin -12 + 33 cos -76 + j 33 sin -76 - 17 cos 6 -j 17 sin 6 = 17.4865 - j 39.4104 now convert it polar form we get Resultant = sqrt { 17.4865 ^2 + (-39.4104)^2 } * /_ arctan (-39.4104/17.4865) = 43.1156 /_ -66.073 so in time domain it is V = 43.12 cos (wt - 66.073) .