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- 1. ADDITIONAL MATHEMATICS FORM 4 COORDINATE GEOMETRY 6.4 EQUATION OF STRAIGHT LINE
- 2. 6.4 EQUATION OF STRAIGHT LINE 6.4.3 Finding the gradient of straight line using X-intercept and y-intercept 6.42 Finding the gradient of a straight line 6.4.2 6.4.1 Determining x -intercept and y- intercept
- 3. The x-intercept of a straight line is the x-coordinate where the Straight Line crosses the x-axis. X-INTERCEPT Y-INTERCEPT The y-intercept of a straight line is the y-coordinate where line crosses the y-axis. 6.4.1 Determining the x-intercept and y-intercept Definition
- 4. The x-intercept of a straight line is the x-coordinate where the Straight Line crosses the x-axis The y-intercept of a straight line is the y-coordinate where line crosses the y-axis.
- 5. WORKSHEET 1
- 7. Gradient is a quantity which measure how step a straight line is sloping with reference to the horizontal The gradient of a straight line is the ratio of vertical distance to horizontal distance Gradient: Gradient = Vertical line Horizontal line @ m = y 2 -y 1 x 2 -x 1 6.4.2 Find the gradient of a straight line 1 3 2
- 8. A (x 1 ,y 1 ) Horizontal distance B (x 2 ,y 2 ) vertical distance y x Gradient = Vertical line Horizontal line m = y 2 -y 1 x 2 -x 1 gradient of a straight line is the ratio of vertical distance to horizontal distance
- 9. WORKSHEET 2
- 11. WORKSHEET 3
- 12. m = y 2 -y 1 x 2 -x 1 Gradient = Vertical line Horizontal line RECALL PREVIOUS SUBTOPIC
- 13. m = - y intercept x-intercept 6.4.3 Finding the gradient of a straight line by using x-intercept and y-intercept Gradient
- 14. summary Determining x -intercept and y- intercept Finding the gradient of a straight line Finding the gradient of straight line using X-intercept and y-intercept Gradient = Vertical line Horizontal line m = y 2 -y 1 x 2 -x 1 m = - y intercept x-intercept
- 15. Have a nice day.. Thank You !

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1)a point on the line

2)the gradient of the line

for example:

find the equation of the line which passes through points (2,8) and (4,12).

step one: take any point - (2,8)

step two: find gradient- gradient (symbol m)=2

step three: use the data

use the point you chose : (2,8) and this: (x,y).

make as if you are finding the gradient: (y-8)/(x-2)

you know that the gradient of the line is 2. thus,

(y-8)/(x-2)=2

solve it and make y subject of formula.you will get the equation of the line