Titration experiment report

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Titration experiment report

  1. 1. Titration Experiment Report<br />Rolla Tyas Amalia- Grade 10<br />Aim:<br /><ul><li>To find how many NaOH needed for titrating 10 ml of vinegar
  2. 2. To find concentration of the vinegar</li></ul> <br />Materials:<br /><ul><li>Vinegar6. 2 beakers
  3. 3. Conical flask7. Phenophtalyn
  4. 4. Measuring pipette8. Dropper
  5. 5. 2 grm of NaOH (0,1 M)9. 50 ml burette
  6. 6. Retord stand 10. 2 volumetric flasks (500 ml)</li></ul>Procedure:<br /><ul><li>Fill a beaker with 2 grm of NaOH granule
  7. 7. Add water to the beaker
  8. 8. Stir the water until the NaOH granule dissolved
  9. 9. Put the dissolved NaOH to a 500 ml volumetric flask (1st volumetric flask)
  10. 10. Set the retord stand, conical flask, and burette like the picture below
  11. 11. Fill another 500 ml volumetric flask (2nd volumetric flask) by water and 10 ml of vinegar, then mix them (to make concentration of the vinegar lesser)
  12. 12. Pour the conical flask by 10 ml of vinegar from the 2nd volumetric flask, by measuring pipette
  13. 13. Add 3 small drop of phenophtalyn to the conical flask
  14. 14. Fill the 50 ml burette with 50 ml of NaOH from the 1st volumetric flask
  15. 15. Titrate the NaOH in the burette to 10 ml of vinegar in the conical flask
  16. 16. Observe until the solution in the conical flask change color into light purple (not dark purple)
  17. 17. Measure how many ml of NaOH take to make the solution change into purple color
  18. 18. Repeat step 7 until 12 for second and third times</li></ul>Data/Experiment result:<br />Titrant: NaOH<br />Concentration: 0,1 M<br />Volume:<br />1st Experiment result: 49, 1 ml<br />2nd Experiment result: 49,3 ml<br />3rd Experiment result: 49, 5 ml<br />Average volume: 49,1 ml + 49,3 ml +49,5 ml<br /> _______________________________ = 49,3 ml<br />3<br />Analyte: Vinegar<br />Volume: 10 ml<br />Concentration: V1 x M1 = V2 x M2<br />49,3 ml x 0,1 M = 10 ml x M2<br /> 4,93 : 10 = M2<br />0,493 =M2<br />0,5 M = M2<br />Analysis: <br />It takes 49,3 ml of NaOH in average, for titrating 10 ml of vinegar, and the concentration of the vinegar is 0,5 M. <br />

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