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# Perimeter area circumference

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### Perimeter area circumference

1. 1. Perimeter, Circumferenceand Areahttp://player.discoveryeducation.com/?blnPreviewOnly=1&guidAssetId=
2. 2. Perimeter and Circumference Perimeter : The distance around a geometricfigure. Circumference: The distance around a circle.
3. 3. Perimeter To find perimeter add the lengths of all thesides.– Example: Find the perimeter of the polygon8 in6 in8 in6 inP = 8 + 8 + 6 + 6P = 28The perimeter is 28 in
4. 4. Perimeter– Example : Find the perimeter of the triangle12 in12 in16 inP = 12 + 12 + 16P = 40The perimeter is 40 in
5. 5. Your Turn…. Find the perimeter pg. 426 #1-3 ( 3 minutes) Make sure that there are no naked numbers.1. P = 6 + 4 + 8P = 18m2. P = 7 + 5 + 5 + 7P = 24in3. P = 8 + 8 + 8 + 8P = 32 ft
6. 6. Circumference To find the circumference multiply timesdiameter, where is 3.14C = dDiameterπππ
7. 7. Definitions Diameter (d): a line that passes through thecenter of a circle Radius (r): half the diameter d = 20, then r = 10 r = 15, then d = 30
8. 8. Circumference Example: Find thecircumferenceDiameter = 8 inCircumference = dC = 3.14(8)C = 25.12The circumference is 25.12 inπ
9. 9. CircumferenceExample: Find the circumferenceradius = 10 cmCircumference = dDiameter = 2r = 2 (10) = 20C = 3.14(20)C = 62.8The circumference is 62.8 cmπ
10. 10. Your Turn…. Find the circumference pg. 426 # 7-9 No naked numbers.7. C = d 8. C = dC = 3.14(12) C = 3.14(3)C = 37.7m C = 9.4 ft9. C = dC = 3.14 (16)C = 50. 2 inπ ππ
11. 11. Area of Rectangles The area of a rectangle is the product of its lengthand width.A = ωω
12. 12. Area of Rectangles Find the area of the rectangle10 ft7.5 inA = ωA = 10(7.5)A = 75 ft²The area is 75 ft²
13. 13. Area of Triangles The area of a triangle is half the product of itsbase b and its height h.A = bhheightbase21
14. 14. Area of Triangles Example: Find the area of the triangle216 in5 inA = bhA = 5(6)A = 15 in²21
15. 15. Area of Circles The area of a circle is the product of and thesquare of the circle’s radius r.A = r²radiusππ
16. 16. Area of Circles Example: Find the areaof the circler = 3 mA = r²A = 3.14(3)²A = 3.14(9)A = 28.26 m²The area of the circle is28.26m²π
17. 17. Area of Circlesd = 8 inA = r²Radius = 4 inA = 3.14(4)²A = 3.14(16)A = 50.24 in²The area of thecircle is 50.24in²π
18. 18. Lets Review Perimeter = Sum of all sides Circumference = d Area of a Rectangle = ω Area of a Triangle = bh Area of a Circle = r²π21π