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# Session 2 & 3 rectifiers

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### Session 2 & 3 rectifiers

1. 1. DC POWER SUPPLIES
2. 2. Block diagram DC power supplyTransformer Rectifier Filter Regulator D C Revision 01 2
3. 3. RectificationRectification is the process by whichan alternating voltage or current ischanged to a unidirectional (one way)voltage or current.
4. 4. The AC SinewavePeak voltage = √2 x V rms = 1.414 x V rms
5. 5. An AC voltage is defined as a voltage that periodically reversespolarity and will cause current to flow in the reverse direction. A DC voltage is a voltage that does not reverse direction, and causes current to flow in one direction only.When an AC voltage is measured with a voltmeter, the indicated value will be the RMS value (V rms = 0.707 x V peak) or (V rms = V peak) of the waveform) √2 When a DC voltage is measured, the meter will indicate the average of the DC voltage waveform.
6. 6. Single phase half wave AC Supply Load+ +- TIME - TIME Revision 01 6
7. 7. Half Wave Single Phase RectificationV load = V average = 0.318 x V peak or 0 .45 x V rms fr = fs PIV = √ 2 x V rms V ripple = √ 2 x V rms
8. 8. Center tapped full wave Load AC Supply+- TIME + - TIME Revision 01 8
9. 9. Full Wave Single Phase RectificationV load = V average = 0.638 x V peak or 0 .9 x V rms fr = 2 x fs PIV = √ 2 x V rms (bridge rectifier) PIV = √ 2 x (2 x V rms) (centre tapped rectifier) V ripple = √ 2 x V rms
10. 10. Single phase bridge rectifier + AC Supply - D D2 TIME+ 1- D3 D4 TIME Load Revision 01 10
11. 11. Printed circuit boardCables Tracks - DC SupplyAC Supply DC terminals AC terminal s Revision 01 11
12. 12. RememberV Line = √3 x V phase
13. 13. V Line V Phase Revision 01 13
14. 14. Three phase half wave D 1 3 Phase Supply Load D2 D3+ +- - TIM E TIME Revision 01 14
15. 15. Half Wave Three Phase RectificationV load = V average = 0.827 x V peak or 1.17 x V rms fr = 3 x fs PIV =2.45 x V phase rms (√ 2 x√ 3 x V rms) V ripple = 0.707 x V rms
16. 16. Three phase full wave Suppl y D D3 D2 1 + - TIM E D4 D5 D 6+- TIME Revision 01 16
17. 17. Full Wave Three Phase RectificationV load = V average = 0.955 x V peak or1.34 x V line rms or 2.34 x V phase rms fr = 6 x fs PIV =√ 2 x V line rms V ripple = 0.16 x V rms