General Uses <ul><li>These are used to describe the relationships between the following kinematic quantities: </li></ul><u...
The Four Basic Kinematic Equations are: <ul><li>V = V 0  + a  Δ t </li></ul><ul><li>V 2  = V 0 2  + 2a Δ s </li></ul><ul><...
V = V 0  + a  Δ t <ul><li>E.g. A car starts at rest and accelerates uniformly at  2 m/s 2  for 5 seconds and stops acceler...
V 2  = V 0 2  + 2a Δ s <ul><li>E.g. A train accelerates from 10 m/s to 40 m/s at an acceleration of 1m/s  2 . what distanc...
S = V 0 Δ t + 0.5 a  Δ t 2 <ul><li>E.g. A body starts from rest at a uniform  acceleration of 3 m/s 2 . how long does it t...
S = (V 0  + V)/2  ×  t <ul><li>A car decelerates from 20 m/s to 10 m/s over a period of 10 seconds. How far does it travel...
Note: <ul><li>All units must be converted such that they are uniform for different variable throughout the calculations. <...
Standard units for the various quantities are as follows: <ul><li>Speed – metres/second </li></ul><ul><li>Acceleration – m...
 
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Physics homework help, physics tutor, physics tutoring by onlinetutorsite

  1. 2. General Uses <ul><li>These are used to describe the relationships between the following kinematic quantities: </li></ul><ul><ul><ul><li>Distance/displacement </li></ul></ul></ul><ul><ul><ul><li>Speed/velocity </li></ul></ul></ul><ul><ul><ul><li>Time </li></ul></ul></ul><ul><ul><ul><li>Acceleration </li></ul></ul></ul><ul><li>When there is an unknown, it can be solved for when the values of the other quantities are given </li></ul>
  2. 3. The Four Basic Kinematic Equations are: <ul><li>V = V 0 + a Δ t </li></ul><ul><li>V 2 = V 0 2 + 2a Δ s </li></ul><ul><li>S = V 0 Δ t + 0.5 a Δ t 2 </li></ul><ul><li>S = (V 0 + V)/2 × t </li></ul>
  3. 4. V = V 0 + a Δ t <ul><li>E.g. A car starts at rest and accelerates uniformly at 2 m/s 2 for 5 seconds and stops accelerating from here on. Calculate its velocity after t = 5 seconds. </li></ul><ul><li>Using V = V 0 + a Δ t, we sub in values 0 for V 0 , 2 for a and 5 for t. Solving for V, we get: </li></ul><ul><li>V = 10 m/s </li></ul>
  4. 5. V 2 = V 0 2 + 2a Δ s <ul><li>E.g. A train accelerates from 10 m/s to 40 m/s at an acceleration of 1m/s 2 . what distance does it cover during this time. </li></ul><ul><li>Using V 2 = V 0 2 + 2a Δ s, we sub in values 40 for V, 10 for V 0 and 1 for a. Re-arranging to solve for s, we get: </li></ul><ul><li>S = 750 m </li></ul>
  5. 6. S = V 0 Δ t + 0.5 a Δ t 2 <ul><li>E.g. A body starts from rest at a uniform acceleration of 3 m/s 2 . how long does it take to cover a distance of 100m. </li></ul><ul><li>Using S = V 0 Δ t + 0.5 a Δ t 2 , we sub in values 3 for a, 0 for V 0 and 100 for s. Re-arranging the equation and solving for t (using the quadratic formula), we get: </li></ul><ul><li>t = 8.51 or -8.51 seconds. As time cannot be negative, t = 8.51 seconds. </li></ul>
  6. 7. S = (V 0 + V)/2 × t <ul><li>A car decelerates from 20 m/s to 10 m/s over a period of 10 seconds. How far does it travel during this time period. </li></ul><ul><li>Using S = (V 0 + V)/2 × t, we sub in values 20 for V 0 , 10 for V and 10 for t. Solving for s, we get: </li></ul><ul><li>S = 150m </li></ul>
  7. 8. Note: <ul><li>All units must be converted such that they are uniform for different variable throughout the calculations. </li></ul><ul><li>Kinematic quantities that are scalar CANNOT be negative, hence any such alternate solutions obtained must be disregarded. </li></ul>
  8. 9. Standard units for the various quantities are as follows: <ul><li>Speed – metres/second </li></ul><ul><li>Acceleration – metres/second squared </li></ul><ul><li>Distance – metres </li></ul><ul><li>Time - seconds </li></ul>

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