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Mar. 25, 2023•0 likes•2 views

Mar. 25, 2023•0 likes•2 views

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Based on a pilot study, the population standard deviation of scores for U.S. highschool graduates taking a new version of an aptitude test has been estimated as 3.7 points. If a larger study is to be undertaken, how large simple random sample will be necessary to have a 99% confidence that the sample mean will not differ from the actual popultion mean by more than 1.0 point? Solution Given a=0.01, |Z(0.005)|=2.58 (check standard normal table) E=1, s=3.7 So n=(Z*s/E)^2 =(2.58*3.7/1)^2 =91.12612 Take n=92.

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- 1. Based on a pilot study, the population standard deviation of scores for U.S. highschool graduates taking a new version of an aptitude test has been estimated as 3.7 points. If a larger study is to be undertaken, how large simple random sample will be necessary to have a 99% confidence that the sample mean will not differ from the actual popultion mean by more than 1.0 point? Solution Given a=0.01, |Z(0.005)|=2.58 (check standard normal table) E=1, s=3.7 So n=(Z*s/E)^2 =(2.58*3.7/1)^2 =91.12612 Take n=92