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# 12 x1 t04 04 travel graphs (2012)

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### 12 x1 t04 04 travel graphs (2012)

1. 1. Travel Graphs
2. 2. Travel Graphse.g. A ball is bounced and its distance from the ground is graphed. x 80 x  5t  8  t  60 40 20 2 4 6 8 t
3. 3. Travel Graphse.g. A ball is bounced and its distance from the ground is graphed. x 80 x  5t  8  t  60 40 20 2 4 6 8 t Distance = total amount travelled
4. 4. Travel Graphse.g. A ball is bounced and its distance from the ground is graphed. x 80 x  5t  8  t  60 40 20 2 4 6 8 t Distance = total amount travelled Displacement = how far from the starting point
5. 5. Travel Graphs e.g. A ball is bounced and its distance from the ground is graphed. x 80 x  5t  8  t  60 40 20 2 4 6 8 t Distance = total amount travelled Displacement = how far from the starting point(i) Find the height of the ball after 1 second
6. 6. Travel Graphs e.g. A ball is bounced and its distance from the ground is graphed. x 80 x  5t  8  t  60 40 20 2 4 6 8 t Distance = total amount travelled Displacement = how far from the starting point(i) Find the height of the ball after 1 second when t  1, x  5 1 8  1  35
7. 7. Travel Graphs e.g. A ball is bounced and its distance from the ground is graphed. x 80 x  5t  8  t  60 40 20 2 4 6 8 t Distance = total amount travelled Displacement = how far from the starting point(i) Find the height of the ball after 1 second when t  1, x  5 1 8  1  35 After 1 second the ball is 35 metres above the ground
8. 8. (ii) At what other time is the ball this same height above the ground?
9. 9. (ii) At what other time is the ball this same height above the ground? when x  35,
10. 10. (ii) At what other time is the ball this same height above the ground? when x  35, 5t  8  t   35 t 8  t   7 8t  t 2  7 t 2  8t  7  0  t  1 t  7   0 t  1 or t 7
11. 11. (ii) At what other time is the ball this same height above the ground? when x  35, 5t  8  t   35 t 8  t   7 8t  t 2  7 t 2  8t  7  0  t  1 t  7   0 t  1 or t  7  ball is 35 metres above ground again after 7 seconds
12. 12. (ii) At what other time is the ball this same height above the ground? when x  35, 5t  8  t   35 t 8  t   7 8t  t 2  7 t 2  8t  7  0  t  1 t  7   0 t  1 or t  7  ball is 35 metres above ground again after 7 seconds change in displacement Average velocity = change in time
13. 13. (ii) At what other time is the ball this same height above the ground? when x  35, 5t  8  t   35 t 8  t   7 8t  t 2  7 t 2  8t  7  0  t  1 t  7   0 t  1 or t  7  ball is 35 metres above ground again after 7 seconds change in displacement Average velocity = change in time x2  x1  t2  t1
14. 14. (iii) Find the average velocity during the 1st second
15. 15. (iii) Find the average velocity during the 1st second x2  x1 average velocity  t2  t1 35  0  1 0  35
16. 16. (iii) Find the average velocity during the 1st second x2  x1 average velocity  t2  t1 35  0  1 0  35  average velocity during the 1st second was 35m/s
17. 17. (iii) Find the average velocity during the 1st second x2  x1 average velocity  t2  t1 35  0  1 0  35  average velocity during the 1st second was 35m/s(iv) Find the average velocity during the fifth second
18. 18. (iii) Find the average velocity during the 1st second x2  x1 average velocity  t2  t1 35  0  1 0  35  average velocity during the 1st second was 35m/s(iv) Find the average velocity during the fifth second when t  4, x  5  4  8  4  =80
19. 19. (iii) Find the average velocity during the 1st second x2  x1 average velocity  t2  t1 35  0  1 0  35  average velocity during the 1st second was 35m/s(iv) Find the average velocity during the fifth second when t  4, x  5  4  8  4  =80 when t  5, x  5  5  8  5  =75
20. 20. (iii) Find the average velocity during the 1st second x2  x1 average velocity  t2  t1 35  0  1 0  35  average velocity during the 1st second was 35m/s(iv) Find the average velocity during the fifth second x2  x1 when t  4, x  5  4  8  4  average velocity  t2  t1 =80 75  80 when t  5, x  5  5  8  5   54 =75  5
21. 21. (iii) Find the average velocity during the 1st second x2  x1 average velocity  t2  t1 35  0  1 0  35  average velocity during the 1st second was 35m/s(iv) Find the average velocity during the fifth second x2  x1 when t  4, x  5  4  8  4  average velocity  t2  t1 =80 75  80 when t  5, x  5  5  8  5   54 =75  5  average velocity during the 5th second was  5m/s
22. 22. (iv) Find the average velocity during its 8 seconds in the air
23. 23. (iv) Find the average velocity during its 8 seconds in the air x2  x1 average velocity  t2  t1 00  80 0
24. 24. (iv) Find the average velocity during its 8 seconds in the air x2  x1 average velocity  t2  t1 00  80 0  average velocity during the 8 seconds was 0m/s
25. 25. (iv) Find the average velocity during its 8 seconds in the air x2  x1 average velocity  t2  t1 00  80 0  average velocity during the 8 seconds was 0m/s distance travelled Average speed = time taken
26. 26. (iv) Find the average velocity during its 8 seconds in the air x2  x1 average velocity  t2  t1 00  80 0  average velocity during the 8 seconds was 0m/s distance travelled Average speed = time taken(v) Find the average speed during its 8 seconds in the air
27. 27. (iv) Find the average velocity during its 8 seconds in the air x2  x1 average velocity  t2  t1 00  80 0  average velocity during the 8 seconds was 0m/s distance travelled Average speed = time taken(v) Find the average speed during its 8 seconds in the air distance travelled average speed  time taken
28. 28. (iv) Find the average velocity during its 8 seconds in the air x2  x1 average velocity  t2  t1 00  80 0  average velocity during the 8 seconds was 0m/s distance travelled Average speed = time taken(v) Find the average speed during its 8 seconds in the air distance travelled average speed  time taken 160  8  20
29. 29. (iv) Find the average velocity during its 8 seconds in the air x2  x1 average velocity  t2  t1 00  80 0  average velocity during the 8 seconds was 0m/s distance travelled Average speed = time taken(v) Find the average speed during its 8 seconds in the air distance travelled average speed  time taken 160  8  20 average speed during the 8 seconds was 20m/s
30. 30. Exercise 3A; 2, 4, 6, 7, 8, 10, 11, 13