PERIODIC TABLE a. i.Label group 1 17 Transition metal 13 14 15 16 18 2
ii.Label period 1 to 5 Period 1 Period 2 Period 3 Period 4 Period 5 1 2 Transition metal 13 14 15 16 17 18
iii.Place proton number of  elements 1 to 20 in the periodic table above 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
iv.Place all the elements  given in the periodic table above with their symbols Transition metal H He F Ne Na Cu Cl Br Ar ...
b)Why are all noble gases chemically not reactive?  <ul><li>Because  they have stable electron arrangement with octet  or ...
c.State 3 physical properties of element sodium <ul><li>1.Soft metals (easily cut with a razor blade) </li></ul><ul><li>2....
Sodium undergoes the following reactions. Write chemical equation: i) With oxygen: ii) With water:  iii) With chlorine:  4...
The reaction of Potassium with water is  more  vigorous  than the reaction of sodium with water. Explain <ul><li>Because p...
State 3 physical properties of element  Chlorine: <ul><li>Yellow gas at room temperature </li></ul><ul><li>Turn moist blue...
g. Chlorine  undergoes reaction with heated iron wool.  Write chemical equation <ul><li>2Fe  + 3Cl 2    2FeCl 3 </li></ul...
The reaction of chlorine  with heated iron is more vigorous than the reaction of bromine with heated iron . Explain <ul><l...
State 3 special properties of transition elements  compared to other elements <ul><li>Form coloured ion and compound </li>...
When going across a period from left to right, the atoms get smaller in size. Explain <ul><li>as the proton number increas...
“ Sesiapa  yang  hendak  mengetahui kedudukannya  di sisi Allah  maka lihatlah kedudukan Allah di dalam hatinya. Sesungguh...
 
CHEMICAL BONDS REVISION
<ul><li>Sodium and oxygen </li></ul><ul><li>( given proton no. Na, 11: O, 8) </li></ul>Step 1) determine whether ionic or ...
Draw electron arrangement  for compounds formed between a) Sodium and oxygen ( given proton no. Na, 11: O, 8)
<ul><li>water  </li></ul><ul><li>( given proton no. H, 1: O, 8) </li></ul>Step 1) determine whether ionic or covalent? Ste...
b) For water molecule
<ul><li>Carbon and chlorine  </li></ul><ul><li>( given proton no. C, 6: Cl, 17) </li></ul>Step 1) determine whether ionic ...
c) Carbon and chlorine
State 3 physical properties of  sodium oxide <ul><li>Solid at room temperature </li></ul><ul><li>Soluble in water </li></u...
State 3 physical properties of water  <ul><li>Does not conduct electricity in in any state  </li></ul><ul><li>Low melting ...
 
1. MOLTEN LEAD(II)IODIDE WITH CARBON ELECTRODE
1)Electrolysis of molten PbI 2  using carbon as electrode <ul><li>a)Ions present : </li></ul>Pb 2+  , I - I - Pb 2+ I - Pb...
d) Half equation : ANODE :  CATHODE : <ul><li>e) Product : </li></ul><ul><li>ANODE : </li></ul><ul><li>CATHODE : </li></ul...
ANODE CATHODE OBSER A PURPLE GAS EVOLVED GREY AND SHINY SOLID DEPOSITED
2.  HYDROCHLORIC ACID 0.0001  moldm -3   WITH CARBON ELECTRODE ALL IONS PRESENT H +  , Cl -  & OH -
2)Electrolysis of HCl, 0.0001 moldm -3  using carbon as electrode <ul><li>a)Ion present : </li></ul>H +  , Cl -  , OH - Cl...
d) Half equation : ANODE :  CATHODE : <ul><li>e) Product : </li></ul><ul><li>ANODE : </li></ul><ul><li>CATHODE : </li></ul...
ANODE CATHODE OBS COLOURLESS GAS THAT REKINDLES GLOWING WOODEN SPLINTER COLOURLESS GAS THAT GIVES ‘POP’ SOUND -TESTED USIN...
2)Electrolysis of CuSO 4 , 1.0 moldm -3  using carbon as electrode <ul><li>a)Ions present : </li></ul>Cu 2+  , SO 4 2-  ,H...
d) Half equation : ANODE :  CATHODE : <ul><li>e) Product : </li></ul><ul><li>ANODE : </li></ul><ul><li>CATHODE : </li></ul...
2)Electrolysis of CuSO 4 , 1.0 moldm -3  using  copper  as electrode <ul><li>a)Ions present: </li></ul>Cu 2+  , SO 4 2-  ,...
d) Half equation : ANODE :  CATHODE : <ul><li>e) Product : </li></ul><ul><li>ANODE : </li></ul><ul><li>CATHODE : </li></ul...
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revision on chapter periodic table, chemical bonding and electrolysis with answers

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basic concept in chemistry on several chapters

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revision on chapter periodic table, chemical bonding and electrolysis with answers

  1. 1. PERIODIC TABLE a. i.Label group 1 17 Transition metal 13 14 15 16 18 2
  2. 2. ii.Label period 1 to 5 Period 1 Period 2 Period 3 Period 4 Period 5 1 2 Transition metal 13 14 15 16 17 18
  3. 3. iii.Place proton number of elements 1 to 20 in the periodic table above 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
  4. 4. iv.Place all the elements given in the periodic table above with their symbols Transition metal H He F Ne Na Cu Cl Br Ar K Mn Li
  5. 5. b)Why are all noble gases chemically not reactive? <ul><li>Because they have stable electron arrangement with octet or duplet structure. </li></ul><ul><li>So they do not release, Gain or share electron </li></ul>
  6. 6. c.State 3 physical properties of element sodium <ul><li>1.Soft metals (easily cut with a razor blade) </li></ul><ul><li>2.Low melting and boiling point compare to other metals </li></ul><ul><li>3.Low density </li></ul><ul><li>4.Good conductor of heat and electricity </li></ul>
  7. 7. Sodium undergoes the following reactions. Write chemical equation: i) With oxygen: ii) With water: iii) With chlorine: 4Na + O 2  2Na 2 O 2Na + 2H 2 O  2NaOH + H 2 2Na + Cl 2  2NaCl
  8. 8. The reaction of Potassium with water is more vigorous than the reaction of sodium with water. Explain <ul><li>Because potassium atom is bigger than sodium atom , </li></ul><ul><li>So the distance between nucleus and valence electron in potassium atom is further than sodium atom </li></ul><ul><li>nuclei attraction in potassium is weaker, therefore easier to release electron </li></ul><ul><li>Potassium is more reactive than sodium </li></ul>
  9. 9. State 3 physical properties of element Chlorine: <ul><li>Yellow gas at room temperature </li></ul><ul><li>Turn moist blue litmus paper to red and decolourised </li></ul><ul><li>Very soluble in water </li></ul>
  10. 10. g. Chlorine undergoes reaction with heated iron wool. Write chemical equation <ul><li>2Fe + 3Cl 2  2FeCl 3 </li></ul><ul><li>or </li></ul><ul><li>Fe + Cl 2  FeCl 2 </li></ul>
  11. 11. The reaction of chlorine with heated iron is more vigorous than the reaction of bromine with heated iron . Explain <ul><li>Chlorine atom is smaller than bromine atom </li></ul><ul><li>The distance between nucleus and valence electron in Chlorine atom is shorter than bromine atom </li></ul><ul><li>Causing the nuclei attraction to be stronger in chlorine atom </li></ul><ul><li>Thus, chlorine atom is easier to attract electron causing it to be more reactive </li></ul>
  12. 12. State 3 special properties of transition elements compared to other elements <ul><li>Form coloured ion and compound </li></ul><ul><li>Have many oxidation number </li></ul><ul><li>Act as catalyst </li></ul><ul><li>Form complex ion </li></ul>
  13. 13. When going across a period from left to right, the atoms get smaller in size. Explain <ul><li>as the proton number increase, the positively charged also increase </li></ul><ul><li>Thus, the nuclei attraction also increase </li></ul><ul><li>The electron are pulled closer to the nucleus causing the size to be smaller </li></ul>
  14. 14. “ Sesiapa yang hendak mengetahui kedudukannya di sisi Allah maka lihatlah kedudukan Allah di dalam hatinya. Sesungguhnya Allah SWT meletakkan kedudukan hambanya di sisiNya sebagaimana hamba meletakkanNya di dalam dirinya.” <ul><li>THE END TOPIC 4 </li></ul>
  15. 16. CHEMICAL BONDS REVISION
  16. 17. <ul><li>Sodium and oxygen </li></ul><ul><li>( given proton no. Na, 11: O, 8) </li></ul>Step 1) determine whether ionic or covalent? Step 3) Arrange the atoms Step 4) Draw electron arrangement Step 2) write formula- so you know how many atoms involve ionic Na 2 O Na O Na See next slide
  17. 18. Draw electron arrangement for compounds formed between a) Sodium and oxygen ( given proton no. Na, 11: O, 8)
  18. 19. <ul><li>water </li></ul><ul><li>( given proton no. H, 1: O, 8) </li></ul>Step 1) determine whether ionic or covalent? Step 3) Arrange the atoms Step 4) Draw electron arrangement Step 2) write formula- so you know how many atoms involve covalent H 2 O H O H See next slide
  19. 20. b) For water molecule
  20. 21. <ul><li>Carbon and chlorine </li></ul><ul><li>( given proton no. C, 6: Cl, 17) </li></ul>Step 1) determine whether ionic or covalent? Step 3) Arrange the atoms Step 4) Draw electron arrangement Step 2) write formula- so you know how many atoms involve covalent CCl 4 See next slide
  21. 22. c) Carbon and chlorine
  22. 23. State 3 physical properties of sodium oxide <ul><li>Solid at room temperature </li></ul><ul><li>Soluble in water </li></ul><ul><li>Insoluble in organic solvent </li></ul><ul><li>Conduct electricity in molten and aqueous state </li></ul><ul><li>High melting point and boiling point </li></ul>
  23. 24. State 3 physical properties of water <ul><li>Does not conduct electricity in in any state </li></ul><ul><li>Low melting point and boiling point </li></ul><ul><li>Colourless liquid at room temperature </li></ul>
  24. 26. 1. MOLTEN LEAD(II)IODIDE WITH CARBON ELECTRODE
  25. 27. 1)Electrolysis of molten PbI 2 using carbon as electrode <ul><li>a)Ions present : </li></ul>Pb 2+ , I - I - Pb 2+ I - Pb 2+ Anode(+) Cathode(-) b)Ion attracted c) Ion discharged
  26. 28. d) Half equation : ANODE : CATHODE : <ul><li>e) Product : </li></ul><ul><li>ANODE : </li></ul><ul><li>CATHODE : </li></ul>2I - I 2 +2e Pb 2+ +2e Pb Iodine gas Lead metal
  27. 29. ANODE CATHODE OBSER A PURPLE GAS EVOLVED GREY AND SHINY SOLID DEPOSITED
  28. 30. 2. HYDROCHLORIC ACID 0.0001 moldm -3 WITH CARBON ELECTRODE ALL IONS PRESENT H + , Cl - & OH -
  29. 31. 2)Electrolysis of HCl, 0.0001 moldm -3 using carbon as electrode <ul><li>a)Ion present : </li></ul>H + , Cl - , OH - Cl - , OH - H + OH - H + Anode Cathode b)Ion attracted c) Ion discharged
  30. 32. d) Half equation : ANODE : CATHODE : <ul><li>e) Product : </li></ul><ul><li>ANODE : </li></ul><ul><li>CATHODE : </li></ul>4OH - O 2 + 2H 2 O +4e 2H + +2e H 2 Oxygen and water Hydrogen gas
  31. 33. ANODE CATHODE OBS COLOURLESS GAS THAT REKINDLES GLOWING WOODEN SPLINTER COLOURLESS GAS THAT GIVES ‘POP’ SOUND -TESTED USING BURNING WOODEN SPLINTER
  32. 34. 2)Electrolysis of CuSO 4 , 1.0 moldm -3 using carbon as electrode <ul><li>a)Ions present : </li></ul>Cu 2+ , SO 4 2- ,H + , OH - SO 4 2- , OH - Cu 2+ , H + OH - Cu 2+ Anode Cathode b)Ion attracted c) Ion discharged
  33. 35. d) Half equation : ANODE : CATHODE : <ul><li>e) Product : </li></ul><ul><li>ANODE : </li></ul><ul><li>CATHODE : </li></ul>4OH - O 2 + 2H 2 O +4e Cu 2+ +2e Cu Oxygen and water Copper metal
  34. 36. 2)Electrolysis of CuSO 4 , 1.0 moldm -3 using copper as electrode <ul><li>a)Ions present: </li></ul>Cu 2+ , SO 4 2- ,H + , OH - SO 4 2- , OH - Cu 2+ , H + Cu 2+ No ions are discharged Anode Cathode b)Ion attracted c) Ion discharged
  35. 37. d) Half equation : ANODE : CATHODE : <ul><li>e) Product : </li></ul><ul><li>ANODE : </li></ul><ul><li>CATHODE : </li></ul>Cu Cu 2+ +2e Cu 2+ +2e Cu Copper(II) ions Copper metal

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