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Latihan menghitung ip subneting

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Latihan menghitung ip subneting

  1. 1. Carilah: 1. Jumlah Subnet 2. Jumlah Host 3. Blok Subnet Dari IP berikut: a. 172.140.56.9 /29 b. 210.124.111.11 /27 c. 30.68.100.72 /26 d. 128.96.200.10/23 e. 10.0.213.7 /21 172.140.56.9 /29 11111111.11111111.11111111.11111000 10101100.10001100.00111000.00001001 10101100.10001100.00111000.00001000 AND Network ID dari 172.140.56.9 adalah = 172.140.56.8 1. jumlah subnet 2x, x = 5 maka 25 = 32 2. jumlah host 2y-2, y =3 maka 23-2 = 8 - 2 = 6 3. blok subnet 256-248 = 8 1) 0 2) 0+8=8 3) 8+8=16 4) .. 32) 240+8=248 Subnet/net 172.140.56.0 172.140.56.8 Host pertama 172.140.56.1 172.140.56.9 Host terakhir 172.140.56.6 172.140.56.14 Broadcast 172.140.56.7 172.140.56.15 172.140.56.16 172.140.56.17 172.140.56.22 172.140.56.23 … … … … 210.124.111.11 /27 11111111.11111111.11111111.11100000 11010010.11111000.11011110.00001011 11010010.11111000.11011110.00000000 Network ID dari 210.124.111.11 adalah = 210.124.111.0 1. jumlah subnet 2x, x = 3 maka 23 = 8 AND 172.140.56.248 172.140.56.249 172.140.56.254 172.140.56.255
  2. 2. 2. jumlah host 2y-2, y =5 maka 25-2 = 32 - 2 = 30 3. blok subnet 256-224 = 32 1) 0 2) 0+32=32 3) 32+32=64 4) … 8) 192+32=224 Subnet/net 210.124.111.0 210.124.111.32 Host pertama 210.124.111.1 210.124.111.33 Host terakhir 210.124.111.30 210.124.111.62 Broadcast 210.124.111.31 210.124.111.63 210.124.111.64 210.124.111.65 210.124.111.94 210.124.111.95 … … … … 210.124.111.224 210.124.111.225 210.124.111.254 210.124.111.255 30.68.100.72 /26 11111111.11111111.11111111.11000000 00011110.01000100.01100100.01001000 00011110.01000100.01100100.01000000 AND Network ID dari 30.68.100.72 adalah = 30.68.100.64 1. jumlah subnet 2x, x = 2 maka 22 = 4 2. jumlah host 2y-2, y =6 maka 26-2 = 64 - 2 = 62 3. blok subnet 256-192=64 1) 0 2) 0+64=64 3) 64+64=128 4) 128+64=192 Subnet/net 30.68.100.0 30.68.100.64 Host pertama 30.68.100.1 30.68.100.65 Host terakhir 30.68.100.62 30.68.100.126 Broadcast 30.68.100.63 30.68.100.127 30.68.100.128 30.68.100.129 30.68.100.190 30.68.100.191 30.68.100.192 30.68.100.193 30.68.100.254 30.68.100.255 128.96.200.10/23 11111111.11111111.11111110.00000000 10000000.01100000.11001000.00001010 10000000.01100000.11001000.00000000 Network ID dari 128.96.200.10 adalah = 128.96.200.0 AND
  3. 3. 1. jumlah subnet 2x, x = 7 maka 27 = 128 2. jumlah host 2y-2, y =9 maka 29-2 = 512 - 2 = 510 3. blok subnet 256-254=2 1) 0 2) 0+2=2 3) 2+2=4 4) … 128)252+2=254 Subnet/net 128.96.0.0 128.96.2.0 Host pertama 128.96.0.1 128.96.2.1 Host terakhir 128.96.1.254 128.96.3.254 Broadcast 128.96.1.255 128.96.3.255 128.96.4.0 128.96.4.1 128.96.5.254 128.96.5.255 … … … … 128.96.254.0 128.96.254.1 128.96.255.254 128.96.255.255 10.0.213.7 /21 11111111.11111111.11111000.00000000 00001010.01100000.11001000.00001010 10000000.01100000.11001000.00000000 AND Network ID dari 128.96.200.10 adalah = 128.96.200.0 1. jumlah subnet 2x, x = 5 maka 25 = 32 2. jumlah host 2y-2, y =11 maka 211-2 = 2048 - 2 = 2046 3. blok subnet 256-248=8 1) 0 2) 0+8=8 3) 8+8=16 4) … 32) 240+8=248 Subnet/net 10.0.0.0 10.0.8.0 10.0.16.0 Host pertama 10.0.0.1 10.0.8.1 10.0.16.1 Host terakhir 10.0.7.254 10.0.15.254 10.0.23.254 Broadcast 10.0.7.255 10.0.15.255 10.0.23.255 … … … … 10.0.248.0 10.0.248.1 10.0.255.254 10.0.255255

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