Successfully reported this slideshow.
We use your LinkedIn profile and activity data to personalize ads and to show you more relevant ads. You can change your ad preferences anytime.
Example continued Field due to q 1 E = 10 10  N.m 2 /C 2  10 X10 -9  C/(3m) 2  = 11 N/C in the y direction. Recall E =kq/r...
Example continued E y = 11 + 3.6 = 14.6 N/C E x = -4.8 N/C E Magnitude of electric field      tan -1  E y /E x = at...
Motion of point charges in electric fields <ul><li>When a point charge such as an electron is placed in an electric field ...
Upcoming SlideShare
Loading in …5
×

Electric field solving

1,589 views

Published on

  • Be the first to comment

  • Be the first to like this

Electric field solving

  1. 1. Example continued Field due to q 1 E = 10 10 N.m 2 /C 2 10 X10 -9 C/(3m) 2 = 11 N/C in the y direction. Recall E =kq/r 2 and k=8.99 x 10 9 N.m 2 /C 2 E y = 11 N/C E x = 0 Field due to q 2 5 E = 10 10 N.m 2 /C 2 15 X10 -9 C/(5m) 2 = 6 N/C at some angle  Resolve into x and y components  E E y =E sin  C E x =E cos  C  Now add all components E y = 11 + 3.6 = 14.6 N/C E x = -4.8 N/C Magnitude x y q 1 =10 nc q 2 =15 nc 4 3
  2. 2. Example continued E y = 11 + 3.6 = 14.6 N/C E x = -4.8 N/C E Magnitude of electric field      tan -1 E y /E x = atan (14.6/-4.8)= -72.8 deg x q 1 =10 nc q 2 =15 nc 4 3
  3. 3. Motion of point charges in electric fields <ul><li>When a point charge such as an electron is placed in an electric field E, it is accelerated according to Newton’s Law: </li></ul><ul><li>a = F/m = qE/m for uniform electric fields </li></ul><ul><li>a = F/m = mg/m = g for uniform gravitational fields </li></ul><ul><li>If the field is uniform, we now have a projectile motion problem- constant acceleration in one direction. So we have parabolic motion just as in hitting a baseball, etc except the magnitudes of velocities and accelerations are different. </li></ul><ul><li>Replace g by qE/m in all equations; </li></ul><ul><li>For example, In y =1/2at 2 we get y =1/2(qE/m)t 2 </li></ul>

×