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- 1. Equation of a linear function Parallel and Perpendicular Lines
- 2. Find the equation of a Linear Function y in STANDARD FORM and SLOPE- INTERCEPT FORM whose graph satisfies the given conditions: 1.Passes through (2,-3) and parallel to the line 3x+4y =2.
- 3. Solution: 1. The line 3x+4y=2 in slope-intercept form is 3x+4y=2 4y=-3x+2 y=-3/4x+2/4 y=-3/4x+1/2
- 4. Its slope is -3/4. Any parallel to it has the slope -3/4. The equation of the line with slope -3/4 and passes through (2,-3) is y-(-3)=-3/4(x-2) y+3=-3/4(x-2) 4y+12=-3(x-2) 4y+12=-3x+6 4y=-3x-6 y=-3/4x-3/2 or 3x+4y=-6
- 5. 2. Passes through (-3,2) and perpendicular to the line 4x-3y=2
- 6. Solution: 1. The line 4x-3y=2 in slope-intercept form is 4x-3y=2 -3y=-4x+2 y=4/3x-2/3
- 7. Its slope is 4/3. Any line perpendicular to it has the slope 4/3. Hence, the required slope -3/4. the equation of the line with the slope -3/4 and passes through (-3,2) is y-2=-3/4[(x-(-3)] y-2=-3/4(x+3) 4y-8=-3(x+3) 4y-8=-3x-9 4y=-3x-1 y=-3/4x-1/4 or 3x+4y=-1
- 8. Find the equation of the Linear Function y in slope-Intercept form and in Standard form satisfying the given conditions 1. Parallel to the line x+y=2, passing through (-1,2) 2. Parallel to the line 3x+4y=12, passing through (0,-2) 3. Perpendicular to the line x+y=3, passing through (- 4,3) 4. Perpendicular to the line 2x-3y=6, passing through (3,-4)
- 9. No Assignment

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