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Organic Compounds

Organic Compounds

Redox Reactions

Redox Reactions

Relative atomic mass

Relative atomic mass

Carbon compound

Carbon compound

C11 redox reactions

C11 redox reactions

S & p block elements

S & p block elements

Carboxylic acids (O Levels Chemistry)

Carboxylic acids (O Levels Chemistry)

Conservation of Mass

Conservation of Mass

Chemical bonds.ppt

Chemical bonds.ppt

P – block elements 12 Classes

P – block elements 12 Classes

Chemistry of Alkaline Earth Metals MANIK

Chemistry of Alkaline Earth Metals MANIK

Chemica kinetic 2017

Chemica kinetic 2017

C16 alcohols and carboxylic acids

C16 alcohols and carboxylic acids

Chapter 8 redox reactions ppt for class 11 CBSE

Chapter 8 redox reactions ppt for class 11 CBSE

Oxidation

Oxidation

The mole concept

The mole concept

Stoichiometry

Stoichiometry

covalent bond

covalent bond

REDOX REACTION

REDOX REACTION

2.1 Chemical Formulas and Equations

2.1 Chemical Formulas and Equations

14 the mole!!!

14 the mole!!!

01 significant digits

01 significant digits

17 stoichiometry

17 stoichiometry

13 nuclear reactions

13 nuclear reactions

10 naming and formula writing 2012

10 naming and formula writing 2012

04 periodic trends v2

04 periodic trends v2

11 balancing chemical equations

11 balancing chemical equations

05 intramolecular bonds

05 intramolecular bonds

09 polarity 2016

09 polarity 2016

08 lewis dot diagrams to 3 d diagrams

08 lewis dot diagrams to 3 d diagrams

Tang 02 wave quantum mechanic model

Tang 02 wave quantum mechanic model

Tang 04 periodic trends

Tang 04 periodic trends

12 types of chemical reactions

12 types of chemical reactions

07 lewis dot diagrams

07 lewis dot diagrams

04 periodic trends and effective nuclear charge supplement

04 periodic trends and effective nuclear charge supplement

06 intermolecular forces

06 intermolecular forces

22 acids + bases

22 acids + bases

19 solutions and solubility

19 solutions and solubility

22 solution stoichiometry new

22 solution stoichiometry new

Synthesis of Aspirin lab chem 165

Synthesis of Aspirin lab chem 165

18 percentage yield

18 percentage yield

Chapter9 stoichiometry-100707061730-phpapp01

Chapter9 stoichiometry-100707061730-phpapp01

Limiting reagents

Limiting reagents

Chemistry - Chp 12 - Stoichiometry - PowerPoint

Chemistry - Chp 12 - Stoichiometry - PowerPoint

ASP Chemistry - Ch 4 Notes.pdf

ASP Chemistry - Ch 4 Notes.pdf

Y11 stoichiometry.pptx (3).pdf

Y11 stoichiometry.pptx (3).pdf

Chemical Reaction Stoichiometry

Chemical Reaction Stoichiometry

Module 6 - Calculations with Balanced Equation.pptx

Module 6 - Calculations with Balanced Equation.pptx

Chapter 3.powerpoint

Chapter 3.powerpoint

Physical Chemistry

Physical Chemistry

526128650-Limiting-Reactants-and-the-Product-Formed.pdf

526128650-Limiting-Reactants-and-the-Product-Formed.pdf

526128650-Limiting-Reactants-and-the-Product-Formed.pdf

526128650-Limiting-Reactants-and-the-Product-Formed.pdf

Limiting reactants

Limiting reactants

Ch3 stoichiometry

Ch3 stoichiometry

Chapter_3_Mass_Relationships.ppt

Chapter_3_Mass_Relationships.ppt

MDCAT Chemistry Notes | Nearpeer

MDCAT Chemistry Notes | Nearpeer

Chapter4

Chapter4

Chemistry - Chp 12 - Stoichiometry - PowerPoint

Chemistry - Chp 12 - Stoichiometry - PowerPoint

Chemistry.

Chemistry.

17 stoichiometry

17 stoichiometry

17 stoichiometry

17 stoichiometry

23 gases

23 gases

23 gases

23 gases

22 acids + bases

22 acids + bases

21 water treatment

21 water treatment

20 concentration of solutions

20 concentration of solutions

22 acids + bases

22 acids + bases

13 isotopes

13 isotopes

04 periodic trends v2

04 periodic trends v2

09 lens applications

09 lens applications

08 lens equations

08 lens equations

GBSN - Microbiology Lab 2 (Compound Microscope)

GBSN - Microbiology Lab 2 (Compound Microscope)

Gliese 12 b, a temperate Earth-sized planet at 12 parsecs discovered with TES...

Gliese 12 b, a temperate Earth-sized planet at 12 parsecs discovered with TES...

The Scientific names of some important families of Industrial plants .pdf

The Scientific names of some important families of Industrial plants .pdf

Erythropoiesis- Dr.E. Muralinath-C Kalyan

Erythropoiesis- Dr.E. Muralinath-C Kalyan

Ostiguy & Panizza & Moffitt (eds.) - Populism in Global Perspective. A Perfor...

Ostiguy & Panizza & Moffitt (eds.) - Populism in Global Perspective. A Perfor...

MODERN PHYSICS_REPORTING_QUANTA_.....pdf

MODERN PHYSICS_REPORTING_QUANTA_.....pdf

Exomoons & Exorings with the Habitable Worlds Observatory I: On the Detection...

Exomoons & Exorings with the Habitable Worlds Observatory I: On the Detection...

Climate extremes likely to drive land mammal extinction during next supercont...

Climate extremes likely to drive land mammal extinction during next supercont...

B lymphocytes, Receptors, Maturation and Activation

B lymphocytes, Receptors, Maturation and Activation

Constraints on Neutrino Natal Kicks from Black-Hole Binary VFTS 243

Constraints on Neutrino Natal Kicks from Black-Hole Binary VFTS 243

Emergent ribozyme behaviors in oxychlorine brines indicate a unique niche for...

Emergent ribozyme behaviors in oxychlorine brines indicate a unique niche for...

Gliese 12 b: A Temperate Earth-sized Planet at 12 pc Ideal for Atmospheric Tr...

Gliese 12 b: A Temperate Earth-sized Planet at 12 pc Ideal for Atmospheric Tr...

Continuum emission from within the plunging region of black hole discs

Continuum emission from within the plunging region of black hole discs

WASP-69b’s Escaping Envelope Is Confined to a Tail Extending at Least 7 Rp

WASP-69b’s Escaping Envelope Is Confined to a Tail Extending at Least 7 Rp

Pests of Green Manures_Bionomics_IPM_Dr.UPR.pdf

Pests of Green Manures_Bionomics_IPM_Dr.UPR.pdf

Tuberculosis (TB)-Notes.pdf microbiology notes

Tuberculosis (TB)-Notes.pdf microbiology notes

Plasmapheresis - Dr. E. Muralinath - Kalyan . C.pptx

Plasmapheresis - Dr. E. Muralinath - Kalyan . C.pptx

INSIGHT Partner Profile: Tampere University

INSIGHT Partner Profile: Tampere University

Mining Activity and Investment Opportunity in Myanmar.pptx

Mining Activity and Investment Opportunity in Myanmar.pptx

GBSN - Microbiology Lab 1 (Microbiology Lab Safety Procedures)

GBSN - Microbiology Lab 1 (Microbiology Lab Safety Procedures)

- 2. Percentage Yield N2 + 3H2 2NH3 Based on this equation and your knowledge, if you reacted 1 mol N2 with 3 mol H2, you will get 2 mol NH3 BUT if you carried out this experiment, you may find out that you only make 1.9 mol. Where did the 0.1 mol go?!
- 3. Percentage Yield N2 + 3H2 2NH3 Where did the 0.1 mol go?! -Experimental design Competing reactions (products reacting with reactants) Experimenter techniques Impure reactants . . .
- 4. Percentage Yield N2 + 3H2 2NH3 Formula to find percentage yield: Percentage yield = Actual yield x 100% Theoretical Yield This formula is similar to: Test score = Marks earned x 100% Maximum possible marks
- 5. Percentage Yield N2 + 3H2 2NH3 PROBLEM: When 7.5g of nitrogen reacts with sufficient hydrogen, the actual yield of ammonia is 1.72g. What is the percentage yield of the reaction? Given: Limiting reactant = N2 mN2 = 7.5g
- 6. Percentage Yield N2 + 3H2 2NH3 Given: Limiting reactant = N2 mN2 = 7.5g n = m M = 7.5g 28.02g/mol = 0.2677mol When 7.5g of nitrogen reacts with sufficient hydrogen, the actual yield of ammonia is 1.72g. What is the percentage yield of the reaction?
- 7. Percentage Yield N2 + 3H2 2NH3 When 7.5g of nitrogen reacts with sufficient hydrogen, the actual yield of ammonia is 1.72g. What is the percentage yield of the reaction? Given: Limiting reactant = N2 nN2 = 0.2677mol STEP 1: SOLVE for the theoretical yield 2 mol NH3 = x 1 mol N2 0.2677mol N2 x = 0.5353 mol NH3 CONVERT BACK TO GRAMS mNH3 = n x M = (0.5353 mol) x (17.04 g/mol) = 9.121512g
- 8. Percentage Yield N2 + 3H2 2NH3PROBLEM: When 7.5g of nitrogen reacts with sufficient hydrogen, the theoretical yield of ammonia is 9.12g. If 1.72g of ammonia is obtained by experiment, what is the percentage yield of the reaction? Given: Actual yield = 1.72g Theoretical yield = 9.12g STEP 2: SOLVE for the percentage yield Percentage yield = Actual yield x 100% Theoretical yield = 1.72g x 100% 9.12g = 18.9% Therefore the percentage yield is 19% The actual yield is ALWAYS smaller than the theoretical yield
- 10. Percentage Purity Percentage purity: How much of a sample, by mass, is actually of a specific compound or element Sample = pure compound or element + impurities Percentage purity = theoretical mass (g) x 100% sample size (g)
- 11. Percentage Purity PROBLEM: You have a 13.9g sample of impure iron pyrite, The sample is heated in air to produce iron (III) oxide, Fe2O3, and sulfur dioxide SO2 4FeS2 + 11O2 2Fe2O3 + 8SO2 If you obtain 8.02g of iron (III) oxide, what was the percentage purity of iron pyrite in the original sample? Given: Actual yield of Fe2O3= 8.02g Sample mass = 13.9g Theoretical mass = ?
- 12. Percentage PurityPROBLEM: You have a 13.9g sample of impure iron pyrite and you obtain 8.02g of iron (III) oxide 4FeS2 + 11O2 2Fe2O3 + 8SO2 What was the percentage purity of iron pyrite? Given: Actual yield of Fe2O3= 8.02g Sample mass = 13.9g Theoretical mass = ? STEP 1: USE YOUR STOICHIOMETRY SKILLS to find the mass of Fe2S expected to have produced 8.02g Fe2O3!!!
- 13. Percentage PurityPROBLEM: You have a 13.9g sample of impure iron pyrite and you obtain 8.02g of iron (III) oxide 4FeS2 + 11O2 2Fe2O3 + 8SO2 Given: Actual yield of Fe2O3= 8.02g Sample mass = 13.9g Theoretical mass = ? STEP 1: Stoichiometry x = 4 mol FeS2 0.0502 mol Fe2O3 2 mol Fe2O3 x = 0.100 mol FeS2 CONVERT BACK TO GRAMS mFeS2 = n x M = (0.100 mol) x (120 g/mol) = 12.0g FeS2
- 14. Percentage PurityPROBLEM: You have a 13.9g sample of impure iron pyrite and you obtain 8.02g of iron (III) oxide 4FeS2 + 11O2 2Fe2O3 + 8SO2 Given: Actual yield of Fe2O3= 8.02g Sample mass = 13.9g Theoretical mass = ? STEP 2: Solve for the percentage purity Percentage purity = theoretical mass (g) x 100% sample size (g) Percentage purity = 12.0g x 100% 13.9g = 86.3% Therefore the percent purity of the iron pyrite sample is 86.3%

- FeS2 is called iron pyrite. Alan, it’s because this question is ASKINg you how pure iron pyrite is. So Why would you solve for something else?