Upcoming SlideShare
×

# Geometry Section 10-2 1112

866 views

Published on

Measuring

Published in: Education, Technology
0 Likes
Statistics
Notes
• Full Name
Comment goes here.

Are you sure you want to Yes No
• Be the first to comment

• Be the first to like this

Views
Total views
866
On SlideShare
0
From Embeds
0
Number of Embeds
201
Actions
Shares
0
11
0
Likes
0
Embeds 0
No embeds

No notes for slide

### Geometry Section 10-2 1112

1. 1. Section 10-2 Measuring Angles and ArcsMonday, May 14, 2012
2. 2. Essential Questions • How do you identify central angles, major arcs, minor arcs, and semicircles, and ﬁnd their measures? • How do you ﬁnd arc length?Monday, May 14, 2012
3. 3. Vocabulary 1. Central Angle: 2. Arc: 3. Minor Arc: 4. Major Arc:Monday, May 14, 2012
4. 4. Vocabulary 1. Central Angle: An angle inside a circle with the vertex at the center and each side is a radius 2. Arc: 3. Minor Arc: 4. Major Arc:Monday, May 14, 2012
5. 5. Vocabulary 1. Central Angle: An angle inside a circle with the vertex at the center and each side is a radius 2. Arc: A part of a exterior of the circle 3. Minor Arc: 4. Major Arc:Monday, May 14, 2012
6. 6. Vocabulary 1. Central Angle: An angle inside a circle with the vertex at the center and each side is a radius 2. Arc: A part of a exterior of the circle 3. Minor Arc: An arc that is less than half of a circle; Has same measure as the central angle that contains it 4. Major Arc:Monday, May 14, 2012
7. 7. Vocabulary 1. Central Angle: An angle inside a circle with the vertex at the center and each side is a radius 2. Arc: A part of a exterior of the circle 3. Minor Arc: An arc that is less than half of a circle; Has same measure as the central angle that contains it 4. Major Arc: An arc that is more than half of a circle; Find the measure by subtracting the measure of the minor arc with same length from 360°Monday, May 14, 2012
8. 8. Vocabulary 5. Semicircle: 6. Congruent Arcs: 7. Adjacent Arcs:Monday, May 14, 2012
9. 9. Vocabulary 5. Semicircle: An arc that is half of a circle; the measure of a semicircle is 360° 6. Congruent Arcs: 7. Adjacent Arcs:Monday, May 14, 2012
10. 10. Vocabulary 5. Semicircle: An arc that is half of a circle; the measure of a semicircle is 360° 6. Congruent Arcs: Arcs that have the same measure 7. Adjacent Arcs:Monday, May 14, 2012
11. 11. Vocabulary 5. Semicircle: An arc that is half of a circle; the measure of a semicircle is 360° 6. Congruent Arcs: Arcs that have the same measure 7. Adjacent Arcs: Two arcs in a circle that have exactly one point in commonMonday, May 14, 2012
12. 12. Theorems and Postulates Theorem 10.1 - Congruent Arcs: Postulate 10.1 - Arc Addition Postulate: Arc Length:Monday, May 14, 2012
13. 13. Theorems and Postulates Theorem 10.1 - Congruent Arcs: In the same or congruent circles, two minor arcs are congruent IFF their central angles are congruent Postulate 10.1 - Arc Addition Postulate: Arc Length:Monday, May 14, 2012
14. 14. Theorems and Postulates Theorem 10.1 - Congruent Arcs: In the same or congruent circles, two minor arcs are congruent IFF their central angles are congruent Postulate 10.1 - Arc Addition Postulate: The measure of an arc formed by two adjacent arcs is the sum of the measures of the two arcs Arc Length:Monday, May 14, 2012
15. 15. Theorems and Postulates Theorem 10.1 - Congruent Arcs: In the same or congruent circles, two minor arcs are congruent IFF their central angles are congruent Postulate 10.1 - Arc Addition Postulate: The measure of an arc formed by two adjacent arcs is the sum of the measures of the two arcs D Arc Length: l = i2π r 360Monday, May 14, 2012
16. 16. Example 1 Find the value of x when m∠QTV = (20x)°, m∠QTR = 20°, m∠RTS = (8x − 4)°, m∠STU = (13x − 3)°, and m∠VTU = (5x + 5)°.Monday, May 14, 2012
17. 17. Example 1 Find the value of x when m∠QTV = (20x)°, m∠QTR = 20°, m∠RTS = (8x − 4)°, m∠STU = (13x − 3)°, and m∠VTU = (5x + 5)°. 20x + 40 + 8x − 4 + 13x − 3 + 5x + 5 = 360Monday, May 14, 2012
18. 18. Example 1 Find the value of x when m∠QTV = (20x)°, m∠QTR = 20°, m∠RTS = (8x − 4)°, m∠STU = (13x − 3)°, and m∠VTU = (5x + 5)°. 20x + 40 + 8x − 4 + 13x − 3 + 5x + 5 = 360 46x + 38 = 360Monday, May 14, 2012
19. 19. Example 1 Find the value of x when m∠QTV = (20x)°, m∠QTR = 20°, m∠RTS = (8x − 4)°, m∠STU = (13x − 3)°, and m∠VTU = (5x + 5)°. 20x + 40 + 8x − 4 + 13x − 3 + 5x + 5 = 360 46x + 38 = 360 46x = 322Monday, May 14, 2012
20. 20. Example 1 Find the value of x when m∠QTV = (20x)°, m∠QTR = 20°, m∠RTS = (8x − 4)°, m∠STU = (13x − 3)°, and m∠VTU = (5x + 5)°. 20x + 40 + 8x − 4 + 13x − 3 + 5x + 5 = 360 46x + 38 = 360 46x = 322 x=7Monday, May 14, 2012
21. 21. Example 2 WC is the radius of ⊙C. Identify each as a major arc, minor arc, or semicircle. Then ﬁnd each measure.  a. XZY  b. WZX  c. XWMonday, May 14, 2012
22. 22. Example 2 WC is the radius of ⊙C. Identify each as a major arc, minor arc, or semicircle. Then ﬁnd each measure.  a. XZY Semicircle, 180°  b. WZX  c. XWMonday, May 14, 2012
23. 23. Example 2 WC is the radius of ⊙C. Identify each as a major arc, minor arc, or semicircle. Then ﬁnd each measure.  a. XZY Semicircle, 180°  b. WZX Major arc, 270°  c. XWMonday, May 14, 2012
24. 24. Example 2 WC is the radius of ⊙C. Identify each as a major arc, minor arc, or semicircle. Then ﬁnd each measure.  a. XZY Semicircle, 180°  b. WZX Major arc, 270°  c. XW Minor arc, 90°Monday, May 14, 2012
25. 25. Example 3 Refer to the table showing the percent of bicycles bought by type at a bike shop. Type Mountain Youth Comfort Hybrid Other Percent 37% 26% 21% 9% 7% a. Find the measure of the arc of Comfort the section that represents the 21% Youth Hybrid comfort bicycles. 26% 9% Other 7% Mountain 37%Monday, May 14, 2012
26. 26. Example 3 Refer to the table showing the percent of bicycles bought by type at a bike shop. Type Mountain Youth Comfort Hybrid Other Percent 37% 26% 21% 9% 7% a. Find the measure of the arc of Comfort the section that represents the 21% Youth Hybrid comfort bicycles. 26% 9% Other 7% 360(.21) Mountain 37%Monday, May 14, 2012
27. 27. Example 3 Refer to the table showing the percent of bicycles bought by type at a bike shop. Type Mountain Youth Comfort Hybrid Other Percent 37% 26% 21% 9% 7% a. Find the measure of the arc of Comfort the section that represents the 21% Youth Hybrid comfort bicycles. 26% 9% Other 7% 360(.21 = 75.6° ) Mountain 37%Monday, May 14, 2012
28. 28. Example 3 Refer to the table showing the percent of bicycles bought by type at a bike shop. Type Mountain Youth Comfort Hybrid Other Percent 37% 26% 21% 9% 7% b. Find the measure of the arc Comfort representing the combination of 21% Youth Hybrid the mountain, youth, and comfort 26% 9% bicycles. Other 7% Mountain 37%Monday, May 14, 2012
29. 29. Example 3 Refer to the table showing the percent of bicycles bought by type at a bike shop. Type Mountain Youth Comfort Hybrid Other Percent 37% 26% 21% 9% 7% b. Find the measure of the arc Comfort representing the combination of 21% Youth Hybrid the mountain, youth, and comfort 26% 9% bicycles. Other 7% 360(.37 + .26 + .21) Mountain 37%Monday, May 14, 2012
30. 30. Example 3 Refer to the table showing the percent of bicycles bought by type at a bike shop. Type Mountain Youth Comfort Hybrid Other Percent 37% 26% 21% 9% 7% b. Find the measure of the arc Comfort representing the combination of 21% Youth Hybrid the mountain, youth, and comfort 26% 9% bicycles. Other 7% 360(.37 + .26 + .21 = 360(.84) ) Mountain 37%Monday, May 14, 2012
31. 31. Example 3 Refer to the table showing the percent of bicycles bought by type at a bike shop. Type Mountain Youth Comfort Hybrid Other Percent 37% 26% 21% 9% 7% b. Find the measure of the arc Comfort representing the combination of 21% Youth Hybrid the mountain, youth, and comfort 26% 9% bicycles. Other 7% 360(.37 + .26 + .21 = 360(.84) ) Mountain 37% = 302.4°Monday, May 14, 2012
32. 32. Example 4 Find the measure of each arc.  a. mKHL  b. mHJ  c. mLH  d. mKJMonday, May 14, 2012
33. 33. Example 4 Find the measure of each arc.  a. mKHL = 360 − 32  b. mHJ  c. mLH  d. mKJMonday, May 14, 2012
34. 34. Example 4 Find the measure of each arc.  a. mKHL = 360 − 32 = 328°  b. mHJ  c. mLH  d. mKJMonday, May 14, 2012
35. 35. Example 4 Find the measure of each arc.  a. mKHL = 360 − 32 = 328°  b. mHJ = 180 − 32  c. mLH  d. mKJMonday, May 14, 2012
36. 36. Example 4 Find the measure of each arc.  a. mKHL = 360 − 32 = 328°  b. mHJ = 180 − 32 = 148°  c. mLH  d. mKJMonday, May 14, 2012
37. 37. Example 4 Find the measure of each arc.  a. mKHL = 360 − 32 = 328°  b. mHJ = 180 − 32 = 148°  c. mLH = 32°  d. mKJMonday, May 14, 2012
38. 38. Example 4 Find the measure of each arc.  a. mKHL = 360 − 32 = 328°  b. mHJ = 180 − 32 = 148°  c. mLH = 32°  d. mKJ = 90 + 32Monday, May 14, 2012
39. 39. Example 4 Find the measure of each arc.  a. mKHL = 360 − 32 = 328°  b. mHJ = 180 − 32 = 148°  c. mLH = 32°  d. mKJ = 90 + 32 = 122°Monday, May 14, 2012
40. 40. Example 5  Find the length of DA , rounding to the nearest hundredth. a.Monday, May 14, 2012
41. 41. Example 5  Find the length of DA , rounding to the nearest hundredth. a. D l= i2π r 360Monday, May 14, 2012
42. 42. Example 5  Find the length of DA , rounding to the nearest hundredth. a. D l= i2π r 360 40 = i2π (4.5) 360Monday, May 14, 2012
43. 43. Example 5  Find the length of DA , rounding to the nearest hundredth. a. D l= i2π r 360 40 = i2π (4.5) 360 ≈ 3.14 cmMonday, May 14, 2012
44. 44. Example 5  Find the length of DA , rounding to the nearest hundredth. b.Monday, May 14, 2012
45. 45. Example 5  Find the length of DA , rounding to the nearest hundredth. b. D l= i2π r 360Monday, May 14, 2012
46. 46. Example 5  Find the length of DA , rounding to the nearest hundredth. b. D l= i2π r 360 152 = i2π (6) 360Monday, May 14, 2012
47. 47. Example 5  Find the length of DA , rounding to the nearest hundredth. b. D l= i2π r 360 152 = i2π (6) 360 ≈ 15.92 cmMonday, May 14, 2012
48. 48. Example 5  Find the length of DA , rounding to the nearest hundredth. c.Monday, May 14, 2012
49. 49. Example 5  Find the length of DA , rounding to the nearest hundredth. c. D l= i2π r 360Monday, May 14, 2012
50. 50. Example 5  Find the length of DA , rounding to the nearest hundredth. c. D l= i2π r 360 140 = i2π (6) 360Monday, May 14, 2012
51. 51. Example 5  Find the length of DA , rounding to the nearest hundredth. c. D l= i2π r 360 140 = i2π (6) 360 ≈ 14.66 cmMonday, May 14, 2012
52. 52. Check Your Understanding p. 696 #1-11Monday, May 14, 2012
53. 53. Problem SetMonday, May 14, 2012
54. 54. Problem Set p. 696 #13-41 odd, 55, 73 "Our lives improve only when we take chances - and the ﬁrst and most difﬁcult risk we can take is to be honest with ourselves." - Walter AndersonMonday, May 14, 2012