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Geometry Section 10-1 1112

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Circles and Circumference

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Geometry Section 10-1 1112

1. 1. CHAPTER 10 CIRCLESFriday, May 11, 2012
2. 2. SECTION 10-1 Circles and CircumferenceFriday, May 11, 2012
3. 3. ESSENTIAL QUESTIONS How do you identify and use parts of circles? How do you solve problems involving the circumference of a circle?Friday, May 11, 2012
4. 4. VOCABULARY 1. Circle: 2. Center: 3. Radius: 4. Chord:Friday, May 11, 2012
5. 5. VOCABULARY 1. Circle: The set of points that are all the same distance from a given point 2. Center: 3. Radius: 4. Chord:Friday, May 11, 2012
6. 6. VOCABULARY 1. Circle: The set of points that are all the same distance from a given point 2. Center: The point that all of the points of a circle are equidistant from 3. Radius: 4. Chord:Friday, May 11, 2012
7. 7. VOCABULARY 1. Circle: The set of points that are all the same distance from a given point 2. Center: The point that all of the points of a circle are equidistant from 3. Radius: A segment with one endpoint at the center and the other on the edge of the circle; also the distance from the center to the edge of the circle 4. Chord:Friday, May 11, 2012
8. 8. VOCABULARY 1. Circle: The set of points that are all the same distance from a given point 2. Center: The point that all of the points of a circle are equidistant from 3. Radius: A segment with one endpoint at the center and the other on the edge of the circle; also the distance from the center to the edge of the circle 4. Chord: A segment with both endpoints on the edge of the circleFriday, May 11, 2012
9. 9. VOCABULARY 5. Diameter: 6. Congruent Circles: 7. Concentric Circles: 8. Circumference: 9. Pi (π):Friday, May 11, 2012
10. 10. VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: 7. Concentric Circles: 8. Circumference: 9. Pi (π):Friday, May 11, 2012
11. 11. VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: Two or more circles with congruent radii 7. Concentric Circles: 8. Circumference: 9. Pi (π):Friday, May 11, 2012
12. 12. VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: Two or more circles with congruent radii 7. Concentric Circles: Coplanar circles with the same center 8. Circumference: 9. Pi (π):Friday, May 11, 2012
13. 13. VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: Two or more circles with congruent radii 7. Concentric Circles: Coplanar circles with the same center 8. Circumference: The distance around a circle 9. Pi (π):Friday, May 11, 2012
14. 14. VOCABULARY 5. Diameter: A special chord that passes through the center of a circle; twice the length of the radius 6. Congruent Circles: Two or more circles with congruent radii 7. Concentric Circles: Coplanar circles with the same center 8. Circumference: The distance around a circle 9. Pi (π): The irrational number found from the ratio of circumference to the diameterFriday, May 11, 2012
15. 15. VOCABULARY 10. Inscribed: 11. Circumscribed:Friday, May 11, 2012
16. 16. VOCABULARY 10. Inscribed: A polygon inside a circle where all of the vertices of the polygon are on the circle 11. Circumscribed:Friday, May 11, 2012
17. 17. VOCABULARY 10. Inscribed: A polygon inside a circle where all of the vertices of the polygon are on the circle 11. Circumscribed: A circle that is around a polygon that is inscribedFriday, May 11, 2012
18. 18. EXAMPLE 1 a. Name the circle b. Identify a radius c. Identify a chord d. Name the diameterFriday, May 11, 2012
19. 19. EXAMPLE 1 a. Name the circle Circle C or ⊙C b. Identify a radius c. Identify a chord d. Name the diameterFriday, May 11, 2012
20. 20. EXAMPLE 1 a. Name the circle Circle C or ⊙C b. Identify a radius AC or CD c. Identify a chord d. Name the diameterFriday, May 11, 2012
21. 21. EXAMPLE 1 a. Name the circle Circle C or ⊙C b. Identify a radius AC or CD c. Identify a chord d. Name the diameter EBFriday, May 11, 2012
22. 22. EXAMPLE 1 a. Name the circle Circle C or ⊙C b. Identify a radius AC or CD c. Identify a chord d. Name the diameter EB ADFriday, May 11, 2012
23. 23. EXAMPLE 2 If JT = 24 in, what is KM?Friday, May 11, 2012
24. 24. EXAMPLE 2 If JT = 24 in, what is KM? JT = KLFriday, May 11, 2012
25. 25. EXAMPLE 2 If JT = 24 in, what is KM? JT = KL KL = 24 inFriday, May 11, 2012
26. 26. EXAMPLE 2 If JT = 24 in, what is KM? JT = KL KL = 24 in KM is half of KLFriday, May 11, 2012
27. 27. EXAMPLE 2 If JT = 24 in, what is KM? JT = KL KL = 24 in KM is half of KL KM = 12 inFriday, May 11, 2012
28. 28. EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP.Friday, May 11, 2012
29. 29. EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 LN = 2Friday, May 11, 2012
30. 30. EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 LN = =11 2Friday, May 11, 2012
31. 31. EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = 2 2Friday, May 11, 2012
32. 32. EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = = 8 2 2Friday, May 11, 2012
33. 33. EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = = 8 2 2 LP = LN + MP − MNFriday, May 11, 2012
34. 34. EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = = 8 2 2 LP = LN + MP − MN LP =11+ 8 − 5Friday, May 11, 2012
35. 35. EXAMPLE 3 The diameter of ⊙L is 22 cm and the diameter of ⊙P is 16 cm. MN = 5 cm. Find LP. 22 16 LN = =11 MP = = 8 2 2 LP = LN + MP − MN LP =11+ 8 − 5 LP =14 cmFriday, May 11, 2012
36. 36. EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet.Friday, May 11, 2012
37. 37. EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πdFriday, May 11, 2012
38. 38. EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd 65.4 = π dFriday, May 11, 2012
39. 39. EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd 65.4 = π d π πFriday, May 11, 2012
40. 40. EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd 65.4 = π d π π d ≈ 20.82 ftFriday, May 11, 2012
41. 41. EXAMPLE 4 Find the diameter and radius of a circle to the nearest hundredth if the circumference of the circle is 65.4 feet. C = πd 65.4 = π d π π d ≈ 20.82 ft r ≈10.41 ftFriday, May 11, 2012
42. 42. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2Friday, May 11, 2012
43. 43. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2Friday, May 11, 2012
44. 44. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r + r = (3 2 ) 2 2 2Friday, May 11, 2012
45. 45. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r + r = (3 2 ) 2 2 2 2r = (3 2 ) 2 2Friday, May 11, 2012
46. 46. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r + r = (3 2 ) 2 2 2 2r = (3 2 ) 2 2 2r = 9(2) 2Friday, May 11, 2012
47. 47. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r + r = (3 2 ) 2 2 2 2r = (3 2 ) 2 2 2r = 9(2) 2 r =9 2Friday, May 11, 2012
48. 48. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 2r = (3 2 ) 2 2 2r = 9(2) 2 r =9 2Friday, May 11, 2012
49. 49. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 r =3 2r = (3 2 ) 2 2 2r = 9(2) 2 r =9 2Friday, May 11, 2012
50. 50. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 r =3 2r = (3 2 ) 2 2 C = 2π r 2r = 9(2) 2 r =9 2Friday, May 11, 2012
51. 51. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 r =3 2r = (3 2 ) 2 2 C = 2π r 2r = 9(2) 2 C = 2π (3) r =9 2Friday, May 11, 2012
52. 52. EXAMPLE 5 Find the exact circumference of ⊙R. BF = 3 2 (BR) + (RF ) = (BF ) 2 2 2 r = 9 2 r + r = (3 2 ) 2 2 2 r =3 2r = (3 2 ) 2 2 C = 2π r 2r = 9(2) 2 C = 2π (3) r =9 2 C = 6πFriday, May 11, 2012
53. 53. CHECK YOUR UNDERSTANDING p. 687 #1-9Friday, May 11, 2012
54. 54. PROBLEM SETFriday, May 11, 2012
55. 55. PROBLEM SET p. 687 #11-41 odd, 71 “We dont know who we are until we see what we can do.” - Martha GrimesFriday, May 11, 2012