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# Lesson 6: Limits Involving ∞ (Section 21 slides)

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### Lesson 6: Limits Involving ∞ (Section 21 slides)

1. 1. Section 1.6 Limits involving Infinity V63.0121.021, Calculus I New York University September 23, 2010Announcements Quiz 1 is next week in recitation. Covers Sections 1.1–1.4 . . . . . .
2. 2. Announcements Quiz 1 is next week in recitation. Covers Sections 1.1–1.4 . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 2 / 38
3. 3. Objectives “Intuit” limits involving infinity by eyeballing the expression. Show limits involving infinity by algebraic manipulation and conceptual argument. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 3 / 38
4. 4. Recall the definition of limitDefinitionWe write lim f(x) = L x→aand say “the limit of f(x), as x approaches a, equals L”if we can make the values of f(x) arbitrarily close to L (as close to L aswe like) by taking x to be sufficiently close to a (on either side of a) butnot equal to a. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 4 / 38
5. 5. Recall the unboundedness problem 1Recall why lim+ doesn’t exist. x→0 x y . .?. L . x .No matter how thin we draw the strip to the right of x = 0, we cannot“capture” the graph inside the box. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 5 / 38
6. 6. Recall the unboundedness problem 1Recall why lim+ doesn’t exist. x→0 x y . .?. L . x .No matter how thin we draw the strip to the right of x = 0, we cannot“capture” the graph inside the box. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 5 / 38
7. 7. Recall the unboundedness problem 1Recall why lim+ doesn’t exist. x→0 x y . .?. L . x .No matter how thin we draw the strip to the right of x = 0, we cannot“capture” the graph inside the box. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 5 / 38
8. 8. Recall the unboundedness problem 1Recall why lim+ doesn’t exist. x→0 x y . .?. L . x .No matter how thin we draw the strip to the right of x = 0, we cannot“capture” the graph inside the box. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 5 / 38
9. 9. OutlineInfinite Limits Vertical Asymptotes Infinite Limits we Know Limit “Laws” with Infinite Limits Indeterminate Limit formsLimits at ∞ Algebraic rates of growth Rationalizing to get a limit . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 6 / 38
10. 10. Infinite LimitsDefinitionThe notation y . lim f(x) = ∞ x→ameans that values of f(x) canbe made arbitrarily large (aslarge as we please) by taking xsufficiently close to a but notequal to a. . x . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 7 / 38
11. 11. Infinite LimitsDefinitionThe notation y . lim f(x) = ∞ x→ameans that values of f(x) canbe made arbitrarily large (aslarge as we please) by taking xsufficiently close to a but notequal to a. . x . “Large” takes the place of “close to L”. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 7 / 38
12. 12. Infinite LimitsDefinitionThe notation y . lim f(x) = ∞ x→ameans that values of f(x) canbe made arbitrarily large (aslarge as we please) by taking xsufficiently close to a but notequal to a. . x . “Large” takes the place of “close to L”. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 7 / 38
13. 13. Infinite LimitsDefinitionThe notation y . lim f(x) = ∞ x→ameans that values of f(x) canbe made arbitrarily large (aslarge as we please) by taking xsufficiently close to a but notequal to a. . x . “Large” takes the place of “close to L”. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 7 / 38
14. 14. Infinite LimitsDefinitionThe notation y . lim f(x) = ∞ x→ameans that values of f(x) canbe made arbitrarily large (aslarge as we please) by taking xsufficiently close to a but notequal to a. . x . “Large” takes the place of “close to L”. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 7 / 38
15. 15. Infinite LimitsDefinitionThe notation y . lim f(x) = ∞ x→ameans that values of f(x) canbe made arbitrarily large (aslarge as we please) by taking xsufficiently close to a but notequal to a. . x . “Large” takes the place of “close to L”. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 7 / 38
16. 16. Infinite LimitsDefinitionThe notation y . lim f(x) = ∞ x→ameans that values of f(x) canbe made arbitrarily large (aslarge as we please) by taking xsufficiently close to a but notequal to a. . x . “Large” takes the place of “close to L”. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 7 / 38
17. 17. Infinite LimitsDefinitionThe notation y . lim f(x) = ∞ x→ameans that values of f(x) canbe made arbitrarily large (aslarge as we please) by taking xsufficiently close to a but notequal to a. . x . “Large” takes the place of “close to L”. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 7 / 38
18. 18. Negative InfinityDefinitionThe notation lim f(x) = −∞ x→ameans that the values of f(x) can be made arbitrarily large negative (aslarge as we please) by taking x sufficiently close to a but not equal to a. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 8 / 38
19. 19. Negative InfinityDefinitionThe notation lim f(x) = −∞ x→ameans that the values of f(x) can be made arbitrarily large negative (aslarge as we please) by taking x sufficiently close to a but not equal to a. We call a number large or small based on its absolute value. So −1, 000, 000 is a large (negative) number. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 8 / 38
20. 20. Vertical AsymptotesDefinitionThe line x = a is called a vertical asymptote of the curve y = f(x) if atleast one of the following is true: lim f(x) = ∞ lim f(x) = −∞ x→a x→a lim f(x) = ∞ lim f(x) = −∞ x→a+ x→a+ lim f(x) = ∞ lim f(x) = −∞ x→a− x→a− . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 9 / 38
21. 21. Infinite Limits we Know y . . . 1 lim+ = ∞ x→0 x . . . . . . . . x . . . . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 10 / 38
22. 22. Infinite Limits we Know y . . . 1 lim+ = ∞ x→0 x . 1 lim = −∞ x→0− x . . . . . . . x . . . . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 10 / 38
23. 23. Infinite Limits we Know y . . . 1 lim+ = ∞ x→0 x . 1 lim = −∞ x→0− x . . . . . . . x . 1 lim =∞ x→0 x2 . . . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 10 / 38
24. 24. Finding limits at trouble spotsExampleLet x2 + 2 f(x) = x2 − 3x + 2Find lim f(x) and lim+ f(x) for each a at which f is not continuous. x→a− x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 11 / 38
25. 25. Finding limits at trouble spotsExampleLet x2 + 2 f(x) = x2 − 3x + 2Find lim f(x) and lim+ f(x) for each a at which f is not continuous. x→a− x→aSolutionThe denominator factors as (x − 1)(x − 2). We can record the signs ofthe factors on the number line. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 11 / 38
26. 26. Use the number line . . x − 1) ( . . . . . . . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
27. 27. Use the number line − .. 0 .. . + . x − 1) . . ( 1 . . . . . . . . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
28. 28. Use the number line − .. 0 .. . + . x − 1) . . ( 1 . − . 0 .. . + . x − 2) . . ( 2 . . . . . . . . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
29. 29. Use the number line − .. 0 .. . + . x − 1) . . ( 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( . . . . . . . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
30. 30. Use the number line − .. 0 .. . + . x − 1) . . ( 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( . . .. . . .. . f .(x) 1 . 2 . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
31. 31. Use the number line − .. 0 .. . + . x − 1) . . ( 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( .+ . .. . . .. . f .(x) 1 . 2 . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
32. 32. Use the number line . mall − .. 0 .. . + s . x − 1) . ( 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( .+ +∞ . . . . . .. . f .(x) 1 . 2 . lim f(x) = + ∞ x→1− . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
33. 33. Use the number line . mall − .. 0 .. . + s . x − 1) . ( 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( .+ +∞ . . ∞ . . − . .. . f .(x) 1 . 2 . lim f(x) = + ∞ x→1− lim f(x) = − ∞ x→1+ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
34. 34. Use the number line − .. 0 .. . + . x − 1) . . ( 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( .+ +∞ . . ∞ . . . − − .. . f .(x) 1 . 2 . lim f(x) = + ∞ x→1− lim f(x) = − ∞ x→1+ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
35. 35. Use the number line − .. 0 .. . + . x − 1) . . ( small 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( .+ +∞ . . ∞ . . ∞ . . . − − − . f .(x) 1 . 2 . lim f(x) = + ∞ lim f(x) = − ∞ x→1− x→2− lim f(x) = − ∞ x→1+ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
36. 36. Use the number line − .. 0 .. . + . x − 1) . . ( small 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( .+ +∞ . . ∞ . . ∞ . . ∞ . − − − + . f .(x) 1 . 2 . lim f(x) = + ∞ lim f(x) = − ∞ x→1− x→2− lim f(x) = − ∞ lim f(x) = + ∞ x→1+ x→2+ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
37. 37. Use the number line − .. 0 .. . + . x − 1) . . ( 1 . − . 0 .. . + . x − 2) . . ( 2 . . + . x2 + 2) ( .+ +∞ . . ∞ . . ∞ . . ∞ . − − − + . + f .(x) 1 . 2 . lim f(x) = + ∞ lim f(x) = − ∞ x→1− x→2− lim f(x) = − ∞ lim f(x) = + ∞ x→1+ x→2+ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 12 / 38
38. 38. In English, nowTo explain the limit, you can say:“As x → 1− , the numerator approaches 3, and the denominatorapproaches 0 while remaining positive. So the limit is +∞.” . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 13 / 38
39. 39. The graph so far lim f(x) = + ∞ lim f(x) = − ∞ x→1− x→2− lim f(x) = − ∞ lim f(x) = + ∞ x→1+ x→2+ y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 14 / 38
40. 40. The graph so far lim f(x) = + ∞ lim f(x) = − ∞ x→1− x→2− lim f(x) = − ∞ lim f(x) = + ∞ x→1+ x→2+ y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 14 / 38
41. 41. The graph so far lim f(x) = + ∞ lim f(x) = − ∞ x→1− x→2− lim f(x) = − ∞ lim f(x) = + ∞ x→1+ x→2+ y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 14 / 38
42. 42. The graph so far lim f(x) = + ∞ lim f(x) = − ∞ x→1− x→2− lim f(x) = − ∞ lim f(x) = + ∞ x→1+ x→2+ y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 14 / 38
43. 43. The graph so far lim f(x) = + ∞ lim f(x) = − ∞ x→1− x→2− lim f(x) = − ∞ lim f(x) = + ∞ x→1+ x→2+ y . . . . . . . x − . 1 1 . 2 . 3 . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 14 / 38
44. 44. Limit Laws (?) with infinite limitsFactThe sum of two positive or two negative infinite limits is infinite. If lim f(x) = ∞ and lim g(x) = ∞, then lim (f(x) + g(x)) = ∞. x→a x→a x→a If lim f(x) = −∞ and lim g(x) = −∞, then lim (f(x) + g(x)) = −∞. x→a x→a x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 15 / 38
45. 45. Rules of Thumb with infinite limits ∞ . +∞=∞FactThe sum of two positive or two negative infinite limits is infinite. . If lim f(x) = ∞ and lim g(x) = ∞, then lim (f(x) + g(x)) = ∞. x→a x→a x→a If lim f(x) = −∞ and lim g(x) = −∞, then lim (f(x) + g(x)) = −∞. x→a x→a x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 15 / 38
46. 46. Rules of Thumb with infinite limits ∞ . +∞=∞ − . ∞ + (−∞) = −∞FactThe sum of two positive or two negative infinite limits is infinite. . If lim f(x) = ∞ and lim g(x) = ∞, then lim (f(x) + g(x)) = ∞. x→a x→a x→a If lim f(x) = −∞ and lim g(x) = −∞, then lim (f(x) + g(x)) = −∞. .x→a x→a x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 15 / 38
47. 47. Rules of Thumb with infinite limits ∞ . +∞=∞ − . ∞ + (−∞) = −∞FactThe sum of two positive or two negative infinite limits is infinite. . If lim f(x) = ∞ and lim g(x) = ∞, then lim (f(x) + g(x)) = ∞. x→a x→a x→a If lim f(x) = −∞ and lim g(x) = −∞, then lim (f(x) + g(x)) = −∞. .x→a x→a x→aRemarkWe don’t say anything here about limits of the form ∞ − ∞. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 15 / 38
48. 48. Rules of Thumb with infinite limitsKids, dont try this at home!FactThe sum of a finite limit and an infinite limit is infinite. If lim f(x) = L and lim g(x) = ±∞, then lim (f(x) + g(x)) = ±∞. x→a x→a x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 16 / 38
49. 49. Rules of Thumb with infinite limitsKids, dont try this at home!FactThe sum of a finite limit and an infinite limit is infinite. . If lim f(x) = L and lim g(x) = ±∞, then lim (f(x) + g(x)) = ±∞. x→a x→a x→a L+∞=∞ . L − ∞ = −∞ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 16 / 38
50. 50. Rules of Thumb with infinite limitsKids, dont try this at home!FactThe product of a finite limit and an infinite limit is infinite if the finite limitis not 0. If lim f(x) = L, lim g(x) = ∞, and L > 0, then lim f(x) · g(x) = ∞. x→a x→a x→a If lim f(x) = L, lim g(x) = ∞, and L < 0, then lim f(x) · g(x) = −∞. x→a x→a x→a If lim f(x) = L, lim g(x) = −∞, and L > 0, then x→a x→a lim f(x) · g(x) = −∞. x→a If lim f(x) = L, lim g(x) = −∞, and L < 0, then lim f(x) · g(x) = ∞. x→a x→a x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 17 / 38
51. 51. Rules of Thumb with infinite limitsKids, dont try this at home! { ∞ if L > 0 . ·∞= L −∞ if L < 0.FactThe product of a finite limit and an infinite limit is infinite if the finite limitis not 0. . If lim f(x) = L, lim g(x) = ∞, and L > 0, then lim f(x) · g(x) = ∞. x→a x→a x→a If lim f(x) = L, lim g(x) = ∞, and L < 0, then lim f(x) · g(x) = −∞. x→a x→a x→a If lim f(x) = L, lim g(x) = −∞, and L > 0, then x→a x→a lim f(x) · g(x) = −∞. x→a If lim f(x) = L, lim g(x) = −∞, and L < 0, then lim f(x) · g(x) = ∞. x→a x→a x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 17 / 38
52. 52. Rules of Thumb with infinite limitsKids, dont try this at home! { ∞ if L > 0 . ·∞= L −∞ if L < 0.FactThe product of a finite limit and an infinite limit is infinite if the finite limitis not 0. . If lim f(x) = L, lim g(x) = ∞, and L > 0, then lim f(x) · g(x) = ∞. x→a x→a x→a If lim f(x) = L, lim g(x) = ∞, and L < 0, then lim f(x) · g(x) = −∞. x→a x→a { x→a If lim f(x) =(−∞) = −∞−∞,Land0L > 0, then . · L L, lim g(x) = if > x→a x→a lim f(x) · g(x) = −∞. ∞ if L < 0. x→a If lim f(x) = L, lim g(x) = −∞, and L < 0, then lim f(x) · g(x) = ∞. x→a x→a x→a. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 17 / 38
53. 53. Multiplying infinite limitsKids, dont try this at home!FactThe product of two infinite limits is infinite. If lim f(x) = ∞ and lim g(x) = ∞, then lim f(x) · g(x) = ∞. x→a x→a x→a If lim f(x) = ∞ and lim g(x) = −∞, then lim f(x) · g(x) = −∞. x→a x→a x→a If lim f(x) = −∞ and lim g(x) = −∞, then lim f(x) · g(x) = ∞. x→a x→a x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 18 / 38
54. 54. Multiplying infinite limitsKids, dont try this at home! ∞·∞=∞ . ∞ · (−∞) = −∞ (−∞) · (−∞) = ∞FactThe product of two infinite limits is infinite. . If lim f(x) = ∞ and lim g(x) = ∞, then lim f(x) · g(x) = ∞. x→a x→a x→a If lim f(x) = ∞ and lim g(x) = −∞, then lim f(x) · g(x) = −∞. x→a x→a x→a If lim f(x) = −∞ and lim g(x) = −∞, then lim f(x) · g(x) = ∞. x→a x→a x→a . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 18 / 38
55. 55. Dividing by InfinityKids, dont try this at home!FactThe quotient of a finite limit by an infinite limit is zero. f(x) If lim f(x) = L and lim g(x) = ±∞, then lim = 0. x→a x→a x→a g(x) . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 19 / 38
56. 56. Dividing by InfinityKids, dont try this at home!FactThe quotient of a finite limit by an infinite limit is zero. f(x) If lim f(x) = L and lim g(x) = ±∞, then lim = 0. x→a x→a x→a g(x) . L . =0 ∞ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 19 / 38
57. 57. Dividing by zero is still not allowed 1 . . =∞ 0There are examples of such limit forms where the limit is ∞, −∞,undecided between the two, or truly neither. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 20 / 38
58. 58. Indeterminate Limit forms LLimits of the form are indeterminate. There is no rule for evaluating 0such a form; the limit must be examined more closely. Consider these: 1 −1 lim =∞ lim = −∞ x→0 x2 x→0 x2 1 1 lim+ = ∞ lim = −∞ x→0 x x→0− x 1 LWorst, lim is of the form , but the limit does not exist, even x→0 x sin(1/x) 0in the left- or right-hand sense. There are infinitely many verticalasymptotes arbitrarily close to 0! . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 21 / 38
59. 59. Indeterminate Limit formsLimits of the form 0 · ∞ and ∞ − ∞ are also indeterminate.Example 1 The limit lim+ sin x · is of the form 0 · ∞, but the answer is 1. x→0 x 1 The limit lim+ sin2 x · is of the form 0 · ∞, but the answer is 0. x→0 x 1 The limit lim+ sin x · 2 is of the form 0 · ∞, but the answer is ∞. x→0 xLimits of indeterminate forms may or may not “exist.” It will depend onthe context. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 22 / 38
60. 60. Indeterminate forms are like Tug Of WarWhich side wins depends on which side is stronger. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 23 / 38
61. 61. OutlineInfinite Limits Vertical Asymptotes Infinite Limits we Know Limit “Laws” with Infinite Limits Indeterminate Limit formsLimits at ∞ Algebraic rates of growth Rationalizing to get a limit . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 24 / 38
62. 62. DefinitionLet f be a function defined on some interval (a, ∞). Then lim f(x) = L x→∞means that the values of f(x) can be made as close to L as we like, bytaking x sufficiently large. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 25 / 38
63. 63. DefinitionLet f be a function defined on some interval (a, ∞). Then lim f(x) = L x→∞means that the values of f(x) can be made as close to L as we like, bytaking x sufficiently large.DefinitionThe line y = L is a called a horizontal asymptote of the curve y = f(x)if either lim f(x) = L or lim f(x) = L. x→∞ x→−∞ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 25 / 38
64. 64. DefinitionLet f be a function defined on some interval (a, ∞). Then lim f(x) = L x→∞means that the values of f(x) can be made as close to L as we like, bytaking x sufficiently large.DefinitionThe line y = L is a called a horizontal asymptote of the curve y = f(x)if either lim f(x) = L or lim f(x) = L. x→∞ x→−∞y = L is a horizontal line! . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 25 / 38
65. 65. Basic limits at infinityTheoremLet n be a positive integer. Then 1 lim =0 x→∞ xn 1 lim =0 x→−∞ xn . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 26 / 38
66. 66. Limit laws at infinityFactAny limit law that concerns finite limits at a finite point a is still true ifthe finite point is replaced by ±∞.That is, if lim f(x) = L and lim g(x) = M, then x→∞ x→∞ lim (f(x) + g(x)) = L + M x→∞ lim (f(x) − g(x)) = L − M x→∞ lim cf(x) = c · L (for any constant c) x→∞ lim f(x) · g(x) = L · M x→∞ f(x) L lim = (if M ̸= 0), etc. x→∞ g(x) M . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 27 / 38
67. 67. Using the limit laws to compute limits at ∞Example xFind lim x→∞ x2 +1 . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 28 / 38
68. 68. Using the limit laws to compute limits at ∞Example xFind lim x→∞ x2 +1AnswerThe limit is 0. y . . x . . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 28 / 38
69. 69. SolutionSolutionFactor out the largest power of x from the numerator and denominator.We have x x(1) 1 1 = 2 = · x2 +1 x (1 + 1/x2 ) x 1 + 1/x2 x 1 1 1 1 lim = lim = lim · lim x→∞ x2 + 1 x→∞ x 1 + 1/x2 x→∞ x x→∞ 1 + 1/x2 1 =0· = 0. 1+0 . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 29 / 38
70. 70. Using the limit laws to compute limits at ∞Example xFind lim x→∞ x2 +1AnswerThe limit is 0. y . . x .Notice that the graph does cross the asymptote, which contradicts oneof the commonly held beliefs of what an asymptote is. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 30 / 38
71. 71. SolutionSolutionFactor out the largest power of x from the numerator and denominator.We have x x(1) 1 1 = 2 = · x2 +1 x (1 + 1/x2 ) x 1 + 1/x2 x 1 1 1 1 lim = lim = lim · lim x→∞ x2 + 1 x→∞ x 1 + 1/x2 x→∞ x x→∞ 1 + 1/x2 1 =0· = 0. 1+0RemarkHad the higher power been in the numerator, the limit would have been∞. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 31 / 38
72. 72. Another ExampleExampleFind 2x3 + 3x + 1 lim x→∞ 4x3 + 5x2 + 7if it exists.A does not existB 1/2C 0D ∞ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 32 / 38
73. 73. Another ExampleExampleFind 2x3 + 3x + 1 lim x→∞ 4x3 + 5x2 + 7if it exists.A does not existB 1/2C 0D ∞ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 32 / 38
74. 74. SolutionSolutionFactor out the largest power of x from the numerator and denominator.We have 2x3 + 3x + 1 x3 (2 + 3/x2 + 1/x3 ) = 3 4x3 + 5x2 + 7 x (4 + 5/x + 7/x3 ) 2x3 + 3x + 1 2 + 3/x2 + 1/x3 lim = lim x→∞ 4x3 + 5x2 + 7 x→∞ 4 + 5/x + 7/x3 2+0+0 1 = = 4+0+0 2 . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 33 / 38
75. 75. SolutionSolutionFactor out the largest power of x from the numerator and denominator.We have 2x3 + 3x + 1 x3 (2 + 3/x2 + 1/x3 ) = 3 4x3 + 5x2 + 7 x (4 + 5/x + 7/x3 ) 2x3 + 3x + 1 2 + 3/x2 + 1/x3 lim = lim x→∞ 4x3 + 5x2 + 7 x→∞ 4 + 5/x + 7/x3 2+0+0 1 = = 4+0+0 2UpshotWhen finding limits of algebraic expressions at infinity, look at thehighest degree terms. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 33 / 38
76. 76. Still Another ExampleExampleFind √ 3x4 + 7 lim x→∞ x2 + 3 . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 34 / 38
77. 77. Still Another Example √ √ √ . 3x4 + 7 ∼ 3x4 = 3x2ExampleFind √ 3x4 + 7 . lim x→∞ x2 + 3Answer √The limit is 3. . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 34 / 38
78. 78. SolutionSolution √ √ 3x4 + 7 x4 (3 + 7/x4 ) lim = lim x→∞ x2 + 3 x→∞ x2 (1 + 3/x2 ) √ x2 (3 + 7/x4 ) = lim x→∞ x2 (1 + 3/x2 ) √ (3 + 7/x4 ) = lim x→∞ 1 + 3/x2 √ 3+0 √ = = 3. 1+0 . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 35 / 38
79. 79. Rationalizing to get a limitExample (√ )Compute lim 4x2 + 17 − 2x . x→∞ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 36 / 38
80. 80. Rationalizing to get a limitExample (√ )Compute lim 4x2 + 17 − 2x . x→∞SolutionThis limit is of the form ∞ − ∞, which we cannot use. So werationalize the numerator (the denominator is 1) to get an expressionthat we can use the limit laws on. (√ ) (√ ) √4x2 + 17 + 2x lim 4x 2 + 17 − 2x = lim 4x 2 + 17 − 2x · √ x→∞ x→∞ 4x2 + 17 + 2x (4x2 + 17) − 4x2 = lim √ x→∞ 4x2 + 17 + 2x 17 = lim √ =0 x→∞ 4x2 + 17 + 2x . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 36 / 38
81. 81. Kick it up a notchExample (√ )Compute lim 4x2 + 17x − 2x . x→∞ . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 37 / 38
82. 82. Kick it up a notchExample (√ )Compute lim 4x2 + 17x − 2x . x→∞SolutionSame trick, different answer: (√ ) lim 4x2 + 17x − 2x x→∞ (√ √ ) 4x2 + 17 + 2x = lim + 17x − 2x · √ 4x2 x→∞ 4x2 + 17x + 2x (4x2 + 17x) − 4x2 = lim √ x→∞ 4x2 + 17x + 2x 17x 17 17 = lim √ = lim √ = x→∞ 4x2 + 17x + 2x x→∞ 4 + 17/x + 2 4 . . . . . . V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 37 / 38
83. 83. Summary Infinity is a more complicated concept than a single number. There are rules of thumb, but there are also exceptions. Take a two-pronged approach to limits involving infinity: Look at the expression to guess the limit. Use limit rules and algebra to verify it. . . . . . .V63.0121.021, Calculus I (NYU) Section 1.6 Limits involving Infinity September 23, 2010 38 / 38