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- 1. Percentage Rank By: Nikkie G.Maristela
- 2. Percentage Rank Indicates the percentage of scores that lies below a given score. Example, test score which is greater than 95% of the scores of the examinees is said to be 95th percentile. If the scores normally distributed, percentile rank can be inferred from the standard score.
- 3. In solving Percentile Rank, use the formula: PR= CF+0.5F X 100 nwhere, PR– percentage rank CF– cumulative frequency below the given score F– frequency of the given score n– number of scores in the distribution
- 4. Steps in solving PercentileRank1. Arrange the test scores (TS) from highest to lowest.2. Make a frequency distribution of each score and the number of students obtaining each score. (F)3. Find the cumulative frequency (CF) by adding the frequency in each score from the bottom upward.4. Find the percentile rank (PR) in each score using the formula and the result as indicated in column 4.
- 5. Example: the table belowshows the summary of the scores of the 40 students in a 45 item multiple choice of test. Find the percentile ranks of the score in the distribution. TS F TS F 45 1 30 3 43 2 29 4 42 2 28 1 41 1 27 1 25 2 40 1 24 1 39 2 22 2 37 3 21 2 36 2 19 1 34 1 18 2 33 2 16 1 32 2 15 1
- 6. Find the cumulative frequency of the frequencydistribution. Third column represents the cumulativeproperty TS F CF TS F CF 45 1 40 30 3 21 43 2 39 29 4 18 42 2 37 28 1 14 41 1 35 27 1 13 40 1 34 25 2 12 39 2 33 24 1 10 37 3 31 22 2 9 36 2 28 21 2 7 34 1 26 19 1 5 33 2 25 18 2 4 32 2 23 16 1 2 15 1 1 40
- 7. Find the percentile rank of each score.a. Solution: score=45 ; CF=39; F=1; n=40 PR= CF+0.5F X 100 n PR= 39+0.5(1) X 100 40 PR= 39+0.5 X 100 40 PR=0.9875 X 100 PR= 98.75 or 99Analysis: A raw score of 45 is equal to percentile rank of 99. this means that 99% of the students who took examination had raw scores equal to or lower than
- 8. 1. Solution:score=43; CF=37; F=2; n=40 PR= CF+0.5F X 100 n PR= 37+0.5(2) X 100 40 PR= 37+1 X 100 40 PR=0.95 X 100 PR= 95Analysis: A raw score of 43 is equal to percentile rank of 95. This means that 95% of the students who took examination had raw scores equal to or lower than 43.
- 9. 2. Solution:score=42; CF=35; F=2; n=40 PR= CF+0.5F X 100 n PR= 35+0.5(2) X 100 40 PR= 35+1 X 100 40 PR=0.9 X 100 PR= 90Analysis: A raw score of 42 is equal to percentile rank of 90. This means that 90% of the students who took examination had raw scores equal to or lower than 42.
- 10. When converting the rawscores to a percentilerank, the raw scores areput on a scale that hasthe same meaning withdifferent number ofgroups and for differentlenghts of tests.
- 11. Frequency and percentileranks distribution of a 45-itemmultiple choice of test conducted to40 studentsPR TS F CF TS F CF PR 45 1 40 99 29 4 18 40 43 2 39 95 28 1 14 34 42 2 37 90 27 1 13 31 41 1 35 86 25 2 12 28 40 1 34 84 24 1 10 24 39 2 33 80 22 2 9 20 37 3 31 74 21 2 7 15 36 2 28 68 19 1 5 11 34 1 26 64 18 2 4 8 33 2 25 60 16 1 2 4 32 2 23 55 15 1 1 1 30 3 21 49 n=4 0

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