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# Unit 3 hw 7 - literal equations

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### Unit 3 hw 7 - literal equations

1. 1. Solving Literal Equations
2. 2. Solving equations with more than 1 variable(Literal Equations) Sometimes equations have more than one variable. Such as 2x - y = 5 or ab + c = d or A = bh Solving for a speciﬁc variable requires the exact same steps as solving for equations with one variable. The only difference is rarely do terms disappear. The just move to the opposite side.
3. 3. Solve for a:ab + c = d
4. 4. Solve for a: Identify the term with the variableab + c = d for which you are solving.
5. 5. Solve for a: Identify the term with the variableab + c = d for which you are solving.
6. 6. Solve for a: Identify the term with the variableab + c = d for which you are solving. Move terms outside the circle to the opposite side.
7. 7. Solve for a: Identify the term with the variableab + c = d for which you are solving. −c −c Move terms outside the circle to the opposite side.
8. 8. Solve for a: Identify the term with the variableab + c = d for which you are solving. −c −c Move terms outside the circle to the opposite side. Only like terms can be added or subtracted. Write both terms because they are not alike.
9. 9. Solve for a: Identify the term with the variableab + c = d for which you are solving. −c −c Move terms outside the circle to the opposite side.ab = d − c Only like terms can be added or subtracted. Write both terms because they are not alike.
10. 10. Solve for a: Identify the term with the variableab + c = d for which you are solving. −c −c Move terms outside the circle to the opposite side.ab = d − c Only like terms can be added or subtracted. Write both terms because they are not alike. The term with ‘a’ is alone but there is another variable with it. Get the ‘a’ by itself by undoing the multiplication.
11. 11. Solve for a: Identify the term with the variableab + c = d for which you are solving. −c −c Move terms outside the circle to the opposite side.ab = d − c Only like terms can be added or subtracted. Write both terms b b because they are not alike. The term with ‘a’ is alone but there is another variable with it. Get the ‘a’ by itself by undoing the multiplication.
12. 12. Solve for a: Identify the term with the variableab + c = d for which you are solving. −c −c Move terms outside the circle to the opposite side.ab = d − c Only like terms can be added or subtracted. Write both terms b b because they are not alike. The term with ‘a’ is alone but there is another variable with it. Get the d−c ‘a’ by itself by undoing thea= multiplication. b Nothing can be simpliﬁed so this is the ﬁnal answer.
13. 13. Solve for h: 1 A = bh 2
14. 14. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving.
15. 15. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving.
16. 16. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving. No terms outside the circle to move.
17. 17. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving. No terms outside the circle to move. Make life easier by getting rid of the fraction by multiplying by 2
18. 18. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving. 1  No terms outside the circle to2 ( A ) =  bh  2 move. 2  Make life easier by getting rid of the fraction by multiplying by 2
19. 19. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving. 1  No terms outside the circle to2 ( A ) =  bh  2 move. 2  Make life easier by getting rid of 2A = bh the fraction by multiplying by 2
20. 20. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving. 1  No terms outside the circle to2 ( A ) =  bh  2 move. 2  Make life easier by getting rid of 2A = bh the fraction by multiplying by 2 Get the ‘h’ by itself by undoing the multiplication.
21. 21. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving. 1  No terms outside the circle to2 ( A ) =  bh  2 move. 2  Make life easier by getting rid of 2A = bh the fraction by multiplying by 2 Get the ‘h’ by itself by undoing b b the multiplication.
22. 22. Solve for h: 1 Identify the term with the A = bh variable for which you are 2 solving. 1  No terms outside the circle to2 ( A ) =  bh  2 move. 2  Make life easier by getting rid of 2A = bh the fraction by multiplying by 2 Get the ‘h’ by itself by undoing b b the multiplication. 2A Nothing can be simpliﬁed so =h this is the ﬁnal answer. b
23. 23. Solve for y:2x − 3y = 5
24. 24. Solve for y: Identify the term with the variable2x − 3y = 5 for which you are solving.
25. 25. Solve for y: Identify the term with the variable2x − 3y = 5 for which you are solving.
26. 26. Solve for y: Identify the term with the variable2x − 3y = 5 for which you are solving. Move terms outside the circle to the opposite side.
27. 27. Solve for y: Identify the term with the variable2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side.
28. 28. Solve for y: Identify the term with the variable2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side. Not like terms. Write both terms. Typically the variable term is written ﬁrst.
29. 29. Solve for y: Identify the term with the variable 2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side.−3y = −2x + 5 Not like terms. Write both terms. Typically the variable term is written ﬁrst.
30. 30. Solve for y: Identify the term with the variable 2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side.−3y = −2x + 5 Not like terms. Write both terms. Typically the variable term is written ﬁrst. Get coefﬁcient of y as 1.
31. 31. Solve for y: Identify the term with the variable 2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side.−3y = −2x + 5 Not like terms. Write both terms.−3 −3 Typically the variable term is written ﬁrst. Get coefﬁcient of y as 1.
32. 32. Solve for y: Identify the term with the variable 2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side.−3y = −2x + 5 Not like terms. Write both terms.−3 −3 Typically the variable term is written ﬁrst. Get coefﬁcient of y as 1. The -3 divides into both terms on the right side.
33. 33. Solve for y: Identify the term with the variable 2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side.−3y = −2x + 5 Not like terms. Write both terms.−3 −3 Typically the variable term is written ﬁrst. −2 5y= x+ Get coefﬁcient of y as 1. −3 −3 The -3 divides into both terms on the right side.
34. 34. Solve for y: Identify the term with the variable 2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side.−3y = −2x + 5 Not like terms. Write both terms.−3 −3 Typically the variable term is written ﬁrst. −2 5y= x+ Get coefﬁcient of y as 1. −3 −3 The -3 divides into both terms on the right side. Simplify. Be sure to follow the rules for signed numbers!
35. 35. Solve for y: Identify the term with the variable 2x − 3y = 5 for which you are solving.−2x −2x Move terms outside the circle to the opposite side.−3y = −2x + 5 Not like terms. Write both terms.−3 −3 Typically the variable term is written ﬁrst. −2 5y= x+ Get coefﬁcient of y as 1. −3 −3 The -3 divides into both terms on the right side. 2 5 Simplify. Be sure to follow the y= x− 3 3 rules for signed numbers!