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The density of solid W is 19.3 g/cm. How many atorns are present per cubic centimeter of W? atoms/ cm As a solid, W adopts a body-centered cubic unit cell. How many unit cells are present per cubic centimeter of W? Number unit cells/ em What is the volume of a unit cell of this metal? cm What is the edge length of a unit cell of W? cm Exit- ?Previous @or e Up & View Solution OCheck Answer?Next > 9 Hint Solution (a) (19.3 g/cm 3 ) x [(6.022 x 10 23 W atoms)/(183.84 g W)] = 6.32 x 10 22 atoms/cm 3 (b) In a bcc unit cell there are a total of 2 atoms, hence [(1 unit cell)/(2 atoms)] x [(6.32 x 10 22 atoms)/(1 cm 3 )] = 3.16 x 10 22 unit cells/cm 3 (c) The volume of the unit cell is obtained using, 1 unit cell /(3.16 x 10 22 unit cells/cm 3 ) = 3.16 x 10 -23 cm 3 (d) edge length is obtained using V = a 3 a = (3.16 x 10 -23 cm 3 ) 1/3 = 3.16x10 -8 cm Thank you .

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- The density of solid W is 19.3 g/cm. How many atorns are present per cubic centimeter of W? atoms/ cm As a solid, W adopts a body-centered cubic unit cell. How many unit cells are present per cubic centimeter of W? Number unit cells/ em What is the volume of a unit cell of this metal? cm What is the edge length of a unit cell of W? cm Exit- ?Previous @or e Up & View Solution OCheck Answer?Next > 9 Hint Solution (a) (19.3 g/cm 3 ) x [(6.022 x 10 23 W atoms)/(183.84 g W)] = 6.32 x 10 22 atoms/cm 3 (b) In a bcc unit cell there are a total of 2 atoms, hence [(1 unit cell)/(2 atoms)] x [(6.32 x 10 22 atoms)/(1 cm 3 )] = 3.16 x 10 22 unit cells/cm 3 (c) The volume of the unit cell is obtained using, 1 unit cell /(3.16 x 10 22 unit cells/cm 3 ) = 3.16 x 10 -23 cm 3 (d) edge length is obtained using V = a 3 a = (3.16 x 10 -23 cm 3 ) 1/3 = 3.16x10 -8 cm Thank you

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