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- 1. Section 5.2 The Deﬁnite Integral Math 1a December 7, 2007 Announcements my next oﬃce hours: Monday 1–2, Tuesday 3–4 (SC 323) MT II is graded. You’ll get it back today Final seview sessions: Wed 1/9 and Thu 1/10 in Hall D, Sun 1/13 in Hall C, all 7–8:30pm Final tentatively scheduled for January 17
- 2. Outline The deﬁnite integral as a limit Estimating the Deﬁnite Integral Properties of the integral Comparison Properties of the Integral
- 3. The deﬁnite integral as a limit Deﬁnition If f is a function deﬁned on [a, b], the deﬁnite integral of f from a to b is the number n b f (x) dx = lim f (ci ) ∆x ∆x→0 a i=1
- 4. Notation/Terminology b f (x) dx a
- 5. Notation/Terminology b f (x) dx a — integral sign (swoopy S)
- 6. Notation/Terminology b f (x) dx a — integral sign (swoopy S) f (x) — integrand
- 7. Notation/Terminology b f (x) dx a — integral sign (swoopy S) f (x) — integrand a and b — limits of integration (a is the lower limit and b the upper limit)
- 8. Notation/Terminology b f (x) dx a — integral sign (swoopy S) f (x) — integrand a and b — limits of integration (a is the lower limit and b the upper limit) dx — ??? (a parenthesis? an inﬁnitesimal? a variable?)
- 9. Notation/Terminology b f (x) dx a — integral sign (swoopy S) f (x) — integrand a and b — limits of integration (a is the lower limit and b the upper limit) dx — ??? (a parenthesis? an inﬁnitesimal? a variable?) The process of computing an integral is called integration
- 10. The limit can be simpliﬁed Theorem If f is continuous on [a, b] or if f has only ﬁnitely many jump discontinuities, then f is integrable on [a, b]; that is, the deﬁnite b integral f (x) dx exists. a
- 11. The limit can be simpliﬁed Theorem If f is continuous on [a, b] or if f has only ﬁnitely many jump discontinuities, then f is integrable on [a, b]; that is, the deﬁnite b integral f (x) dx exists. a Theorem If f is integrable on [a, b] then n b f (x) dx = lim f (xi )∆x, n→∞ a i=1 where b−a ∆x = and xi = a + i ∆x n
- 12. Outline The deﬁnite integral as a limit Estimating the Deﬁnite Integral Properties of the integral Comparison Properties of the Integral
- 13. Estimating the Deﬁnite Integral Given a partition of [a, b] into n pieces, let xi be the midpoint of ¯ [xi−1 , xi ]. Deﬁne n Mn = f (¯i ) ∆x. x i=1
- 14. Example 1 4 Estimate dx using the midpoint rule and four divisions. 1 + x2 0
- 15. Example 1 4 Estimate dx using the midpoint rule and four divisions. 1 + x2 0 Solution 1 1 3 The partition is 0 < < < < 1, so the estimate is 4 2 4 1 4 4 4 4 M4 = + + + 2 2 2 1 + (7/8)2 4 1 + (1/8) 1 + (3/8) 1 + (5/8)
- 16. Example 1 4 Estimate dx using the midpoint rule and four divisions. 1 + x2 0 Solution 1 1 3 The partition is 0 < < < < 1, so the estimate is 4 2 4 1 4 4 4 4 M4 = + + + 2 2 2 1 + (7/8)2 4 1 + (1/8) 1 + (3/8) 1 + (5/8) 1 4 4 4 4 = + + + 4 65/64 73/64 89/64 113/64
- 17. Example 1 4 Estimate dx using the midpoint rule and four divisions. 1 + x2 0 Solution 1 1 3 The partition is 0 < < < < 1, so the estimate is 4 2 4 1 4 4 4 4 M4 = + + + 2 2 2 1 + (7/8)2 4 1 + (1/8) 1 + (3/8) 1 + (5/8) 1 4 4 4 4 = + + + 4 65/64 73/64 89/64 113/64 150, 166, 784 ≈ 3.1468 = 47, 720, 465
- 18. Outline The deﬁnite integral as a limit Estimating the Deﬁnite Integral Properties of the integral Comparison Properties of the Integral
- 19. Properties of the integral Theorem (Additive Properties of the Integral) Let f and g be integrable functions on [a, b] and c a constant. Then b c dx = c(b − a) 1. a
- 20. Properties of the integral Theorem (Additive Properties of the Integral) Let f and g be integrable functions on [a, b] and c a constant. Then b c dx = c(b − a) 1. a b b b 2. [f (x) + g (x)] dx = f (x) dx + g (x) dx. a a a
- 21. Properties of the integral Theorem (Additive Properties of the Integral) Let f and g be integrable functions on [a, b] and c a constant. Then b c dx = c(b − a) 1. a b b b 2. [f (x) + g (x)] dx = f (x) dx + g (x) dx. a a a b b 3. cf (x) dx = c f (x) dx. a a
- 22. Properties of the integral Theorem (Additive Properties of the Integral) Let f and g be integrable functions on [a, b] and c a constant. Then b c dx = c(b − a) 1. a b b b 2. [f (x) + g (x)] dx = f (x) dx + g (x) dx. a a a b b 3. cf (x) dx = c f (x) dx. a a b b b [f (x) − g (x)] dx = f (x) dx − 4. g (x) dx. a a a
- 23. More Properties of the Integral Conventions: a b f (x) dx = − f (x) dx b a
- 24. More Properties of the Integral Conventions: a b f (x) dx = − f (x) dx b a a f (x) dx = 0 a
- 25. More Properties of the Integral Conventions: a b f (x) dx = − f (x) dx b a a f (x) dx = 0 a This allows us to have c b c 5. f (x) dx = f (x) dx + f (x) dx for all a, b, and c. a a b
- 26. Example Suppose f and g are functions with 4 f (x) dx = 4 0 5 f (x) dx = 7 0 5 g (x) dx = 3. 0 Find 5 [2f (x) − g (x)] dx (a) 0 5 (b) f (x) dx. 4
- 27. Solution We have (a) 5 5 5 [2f (x) − g (x)] dx = 2 f (x) dx − g (x) dx 0 0 0 = 2 · 7 − 3 = 11
- 28. Solution We have (a) 5 5 5 [2f (x) − g (x)] dx = 2 f (x) dx − g (x) dx 0 0 0 = 2 · 7 − 3 = 11 (b) 5 5 4 f (x) dx − f (x) dx = f (x) dx 4 0 0 =7−4=3
- 29. Outline The deﬁnite integral as a limit Estimating the Deﬁnite Integral Properties of the integral Comparison Properties of the Integral
- 30. Comparison Properties of the Integral Theorem Let f and g be integrable functions on [a, b].
- 31. Comparison Properties of the Integral Theorem Let f and g be integrable functions on [a, b]. 6. If f (x) ≥ 0 for all x in [a, b], then b f (x) dx ≥ 0 a
- 32. Comparison Properties of the Integral Theorem Let f and g be integrable functions on [a, b]. 6. If f (x) ≥ 0 for all x in [a, b], then b f (x) dx ≥ 0 a 7. If f (x) ≥ g (x) for all x in [a, b], then b b f (x) dx ≥ g (x) dx a a
- 33. Comparison Properties of the Integral Theorem Let f and g be integrable functions on [a, b]. 6. If f (x) ≥ 0 for all x in [a, b], then b f (x) dx ≥ 0 a 7. If f (x) ≥ g (x) for all x in [a, b], then b b f (x) dx ≥ g (x) dx a a 8. If m ≤ f (x) ≤ M for all x in [a, b], then b m(b − a) ≤ f (x) dx ≤ M(b − a) a
- 34. Example 2 1 Estimate dx using the comparison properties. x 1
- 35. Example 2 1 Estimate dx using the comparison properties. x 1 Solution Since 1 1 ≤x ≤ 2 1 for all x in [1, 2], we have 2 1 1 ·1≤ dx ≤ 1 · 1 2 x 1

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