Date 5/1/13Mole to Mole, Mole to GramBy: Keenan Reardon.Wednesday, May 1, 13
Question 1 Mole to Mole✤ Start with a balanced equation✤ N2 + 3 H2 ---> 2 NH3Wednesday, May 1, 13
Question 1✤ if we have 2.00 mol of N2 reacting, how many moles of NH3 will beproduced?Wednesday, May 1, 13
Process 1✤ Look at the ratios✤ N2 + 3 H2 ---> 2 NH3✤ 2.00 mol of N2-->?molNH3Wednesday, May 1, 13
Answer 2✤ In the balanced equation for every mole ofnitrogen there were 2NH3’s so if we have 2 moles of nitrogen then we w...
Question 2 Mole to Mole✤ Suppose 6.00 mol of H2 reacted. How many moles of ammonia(NH3)would be produced?Wednesday, May 1,...
Answer 2✤ This again is about ratios.✤ N2 + 3 H2 ---> 2 NH3✤ The Hydrogen ammonia ratio is 3/2✤ Since we have 6 moles of h...
Question 3 Mole to Mole✤ We want to produce 2.75 mol of NH3. How many moles of nitrogenwould be required?Wednesday, May 1,...
Process✤ This is tricky so we start with what is given to us.✤ Which is 2.75 mol of NH3--> ?MolN2✤ We then would have to u...
Answer 3✤ The ratio of the equation is 2/1✤ We would then cross multiply 2.75/x =2/1✤ =1.38 mol N2Wednesday, May 1, 13
Question 1 Mole to Mass✤ Start with balanced equation.✤ 2 KClO3 ---> 2 KCl + 3 O2Wednesday, May 1, 13
Questions 1✤ 1.50 mol of KClO3 decomposes. How many grams of O2 will beproduced?Wednesday, May 1, 13
Process✤ 2 KClO3 ---> 2 KCl + 3 O2✤ Find ratios, KClO3 and O2 is 2/3✤ 1.50 mol of KClO3--> ?grams O2✤ Cross multiply - 1.5...
Answer 1✤ Now that we have 2.25mol O2 we convert it to grams.✤ We then multiply 2.25mol O2 by the molar mass of one mole o...
Question 2✤ We want to produce 2.75 mol of KCl. How many grams of KClO3would be required?✤ 2 KClO3 ---> 2 KCl + 3 O2Wednes...
Process✤ Ratios✤ 2/2✤ So we know that we are gonna use the same amount of moles, allwe have to do now is convert it to gra...
Answer✤ 2.75mol KClO3 X 122.55g KCLO3✤ =337g KCLO3✤ 2 KClO3 ---> 2 KCl + 3 O2Wednesday, May 1, 13
Question 3✤ If 80.0 grams of O2 was produced, how many moles of KClO3decomposed?✤ Different question, but same process, on...
Process✤ Find Ratio✤ O2 to KCLO3 is 3/2✤ we then divide 80.0 grams of O2 by the molar mass of O2✤ 80/32 = 2.50molO2✤ 2 KCl...
Answer 3✤ Now we cross multiply 2.50/x = 3/2✤ This equals 1.67 molKClO3✤ 2 KClO3 ---> 2 KCl + 3 O2✤ 80/32 = 2.50molO2Wedne...
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Mole to Mole, Mole to Gram

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Mole to Mole, Mole to Gram

  1. 1. Date 5/1/13Mole to Mole, Mole to GramBy: Keenan Reardon.Wednesday, May 1, 13
  2. 2. Question 1 Mole to Mole✤ Start with a balanced equation✤ N2 + 3 H2 ---> 2 NH3Wednesday, May 1, 13
  3. 3. Question 1✤ if we have 2.00 mol of N2 reacting, how many moles of NH3 will beproduced?Wednesday, May 1, 13
  4. 4. Process 1✤ Look at the ratios✤ N2 + 3 H2 ---> 2 NH3✤ 2.00 mol of N2-->?molNH3Wednesday, May 1, 13
  5. 5. Answer 2✤ In the balanced equation for every mole ofnitrogen there were 2NH3’s so if we have 2 moles of nitrogen then we would need 4molNH3✤ =4mol NH3Wednesday, May 1, 13
  6. 6. Question 2 Mole to Mole✤ Suppose 6.00 mol of H2 reacted. How many moles of ammonia(NH3)would be produced?Wednesday, May 1, 13
  7. 7. Answer 2✤ This again is about ratios.✤ N2 + 3 H2 ---> 2 NH3✤ The Hydrogen ammonia ratio is 3/2✤ Since we have 6 moles of hydrogen then we would need 4 moles ofNH3✤ =4molNH3Wednesday, May 1, 13
  8. 8. Question 3 Mole to Mole✤ We want to produce 2.75 mol of NH3. How many moles of nitrogenwould be required?Wednesday, May 1, 13
  9. 9. Process✤ This is tricky so we start with what is given to us.✤ Which is 2.75 mol of NH3--> ?MolN2✤ We then would have to use the coefficients and cross multiply, leavingwhat we want to be left with on top.Wednesday, May 1, 13
  10. 10. Answer 3✤ The ratio of the equation is 2/1✤ We would then cross multiply 2.75/x =2/1✤ =1.38 mol N2Wednesday, May 1, 13
  11. 11. Question 1 Mole to Mass✤ Start with balanced equation.✤ 2 KClO3 ---> 2 KCl + 3 O2Wednesday, May 1, 13
  12. 12. Questions 1✤ 1.50 mol of KClO3 decomposes. How many grams of O2 will beproduced?Wednesday, May 1, 13
  13. 13. Process✤ 2 KClO3 ---> 2 KCl + 3 O2✤ Find ratios, KClO3 and O2 is 2/3✤ 1.50 mol of KClO3--> ?grams O2✤ Cross multiply - 1.50/x times 2/3✤ =2.25mol O2✤Wednesday, May 1, 13
  14. 14. Answer 1✤ Now that we have 2.25mol O2 we convert it to grams.✤ We then multiply 2.25mol O2 by the molar mass of one mole of O2✤ 2.25mol O2 X 32g O2✤ =72gO2Wednesday, May 1, 13
  15. 15. Question 2✤ We want to produce 2.75 mol of KCl. How many grams of KClO3would be required?✤ 2 KClO3 ---> 2 KCl + 3 O2Wednesday, May 1, 13
  16. 16. Process✤ Ratios✤ 2/2✤ So we know that we are gonna use the same amount of moles, allwe have to do now is convert it to grams✤ 2 KClO3 ---> 2 KCl + 3 O2Wednesday, May 1, 13
  17. 17. Answer✤ 2.75mol KClO3 X 122.55g KCLO3✤ =337g KCLO3✤ 2 KClO3 ---> 2 KCl + 3 O2Wednesday, May 1, 13
  18. 18. Question 3✤ If 80.0 grams of O2 was produced, how many moles of KClO3decomposed?✤ Different question, but same process, only difference if it isbackwards.✤ 2 KClO3 ---> 2 KCl + 3 O2Wednesday, May 1, 13
  19. 19. Process✤ Find Ratio✤ O2 to KCLO3 is 3/2✤ we then divide 80.0 grams of O2 by the molar mass of O2✤ 80/32 = 2.50molO2✤ 2 KClO3 ---> 2 KCl + 3 O2Wednesday, May 1, 13
  20. 20. Answer 3✤ Now we cross multiply 2.50/x = 3/2✤ This equals 1.67 molKClO3✤ 2 KClO3 ---> 2 KCl + 3 O2✤ 80/32 = 2.50molO2Wednesday, May 1, 13

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