Successfully reported this slideshow.
We use your LinkedIn profile and activity data to personalize ads and to show you more relevant ads. You can change your ad preferences anytime.

PD3 paralelo S3 (2T)

897 views

Published on

Published in: Technology
  • Be the first to comment

  • Be the first to like this

PD3 paralelo S3 (2T)

  1. 1. PD3||S3 (2T) -primarioak izarrean-
  2. 2. Tentsio konposatuen arteko transformazio erlazioa: 12000 n1 V p 3 = 17 = = n 2 Vs 706 3 U 2   706  Vo = 2 ⋅   ⇒ Vo = 2 ⋅   = 576.4v  3  3 € € Vo' = 2 ⋅ U 2 ⇒ Vo' = 2 ⋅ 706 = 998.4v
  3. 3. PD3 S3
  4. 4. U = Vl1 − Vl 2 ⇒ 0 ÷ 30º ⇒ U = (V32 )1 − (V12 ) 2 U = 2 ⋅ Vo' ⋅ cos 75 ⋅ sin(α + 165) α = 0º ⇒ U max = 2 ⋅ Vo' ⋅ cos 2 75 = 133.7v α = 15º ⇒ U = 0 α = 30º ⇒ U min = −2 ⋅ Vo' ⋅ cos2 75 = −133.7v €
  5. 5. d( JB ) U = ω ⋅ LB ⋅ dα α U α −2 ⋅ Vo' ⋅ cos 75 ⋅ sin(α −15) 0 ÷ 30º ⇒ J B = ∫ 0 ω ⋅ LB ⋅ dα = ∫ 0 ω ⋅ LB ⋅ dα 2 ⋅ Vo' ⋅ cos 75 JB = ⋅ [cos(α −15) − cos15] ω ⋅ LB α = 0º eta α = 30º ⇒ J B = 0 2 ⋅ Vo' ⋅ cos 75 α = 15º ⇒ J B,max = ⋅ [1− cos15] = 320A (2 ⋅ π ⋅ f SAREA ) ⋅ LB IC , kritikoa = 2 ⋅ J B ,max = 640A f J B = 6 ⋅ f SARE €
  6. 6. 4 + 2 3 n 2 IC 4 + 2 3 1 10000 Ja = ⋅ ⋅ = ⋅ ⋅ = 464 A 3 n1 2 3 17 2 3⋅ 3 ⋅ VO 3⋅ 3 ⋅ 576.4 VLC 0 PD 3 = = = 953.4v π π VLC = VLC 0 − ΔVX ⇒ ΔVX = VLC 0 − VLC = 953.4 − 600 = 353.4v PLC = VLC ⋅ IC = 600 ⋅10000 = 6000000w SSARE = 3 ⋅ U ⋅ J a = 3 ⋅12000 ⋅ 464 = 9644059w PLC 6000000 FSARE = = = 0.622 SSARE 9644059

×