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ISARE


                              (J1)2

     (J1)1


    Δ
                       λ

           U1  12000          ...
Δ
      U  12000     n  U 12000
           1
                    ⇒  1 = 1 =       = 30
        =
        U 2 1 4...
(V13)1

60o




(V13)2
(Is3)1
    (V13)1                      D1                                                                                 ...
(Is3)1
                                                                                                                   ...
(V12)1                                        (Is3)2
                             D1                                      ...
(J1)1 = (Ip1)1 - (Ip3)1
                                               x



    (J1)1                             €



   ...
(J1)2 = (Ip1)2                                            n2 
                                                          ...
(J1)1
                                             x
                                                                     ...
(VLC )1 = (VLC 0 )1 − (ΔVX )1 = (VLC 0 )1 − 0.12(VLC 0 )1
                  = (1− 0.12) ⋅ (VLC 0 )1 = 0.88 ⋅ 540 = 475v
Δ
...
[(V ) ⋅ (I ) ] + [(V )             ⋅ (IC ) 2 ]
                  (PLC )1 + (PLC ) 2                                       ...
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EP MINTEGIA 2009/03/04 Azterketa (2008ko Iraila) [ebazpena - A atala]

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EP MINTEGIA 2009/03/04 Azterketa (2008ko Iraila) [ebazpena - A atala]

  1. 1. ISARE
 (J1)2
 (J1)1
 Δ
 λ
  U1  12000  U1  12000  =  =  U 2 1 400  U 2 2 400 Δ
 λ
 € € (IC)1
 (IC)2
=
(IC)1
=
IC

  2. 2. Δ
  U  12000  n  U 12000 1 ⇒  1 = 1 = = 30  =  U 2 1 400  n 2 1 U 2 400 Δ
 λ
 U1 12000  U1  12000  n1  3= 3 = 30 = ⇒  =   n2 2 U 2 400  U 2 2 400 λ
 3 3 €
  3. 3. (V13)1 60o (V13)2
  4. 4. (Is3)1 (V13)1 D1 1 IC 3 2 1 IC − IC € 3 3 IS1 IS2 RL € IS3 € (Is1)1 1 2 IC IC 3 3 € IC € D3 2 − IC 3 2 IS1 = IC (VL)1 3 € (V12)1 (V13)1 (V23)1 (V21)1 (V31)1 (V32)1 1 IS 2 = − IC 3 1 IS 3 = − IC 3 30 60 90 120 150 180 210 240 270 300 330 360 €
  5. 5. (Is3)1 2 1 IC IC 3 3 1 IC 3 € € (V23)1 1 − IC € 3 2 − IC IS1 3 IS2 € D1 (Is1)1 IS3 2 € IC 3 2 1 IC IC RL 3 3 € 1 − IC € IC 3 D3 € 2 − IC 3 € (VL)1 1 IS1 = IC € 3 (V12)1 (V13)1 (V23)1 (V21)1 (V31)1 (V32)1 1 IS 2 = IC 3 2 IS 3 = − IC 3 30 60 90 120 150 180 210 240 270 300 330 360 €
  6. 6. (V12)1 (Is3)2 D1 2 IC 3 1 IC 1 3 IC 2 3 IC € IS1 RL 3 1 IS2 − IC € 3 2 IS3 € − IC 3 € IC € D2 (Is1)2 2 € 1 IC 3 IS1 = IC 1 3 IC 3 2 € IS 2 = − IC 1 3 − IC € 3 2 1 − IC 3 IS 3 = IC 3 € (VL)1 € (V12)1 (V13)1 (V23)1 (V21)1 (V31)1 (V32)1 € 30 60 90 120 150 180 210 240 270 300 330 360
  7. 7. (J1)1 = (Ip1)1 - (Ip3)1 x (J1)1 € −x Δ  n1  € 2 (Ip3)1 x  3 1  n 2 1 x Δ 3 € 1 −x € 3 2 −x 3 € € (Ip1)1 2 € x 3 1 x 3 € IC 1 −x € 3 2 −x 3 30 60 90 120 150 180 210 240 270 300 330 360 € €
  8. 8. (J1)2 = (Ip1)2  n2    ⋅ ( IC )1 = x (J1)2
  n1 1 € λ
 n  −  2  ⋅ ( IC )1 = −x  n1 1  n1   n1    =   (Is1)2 €  n 2  2  n 2 1 IC λ
 -IC € (VL)2 (V32)2 (V12)2 (V13)2 (V23)2 (V21)2 (V31)2 IC
 60 90 120 150 180 210 240 270 300 330 360 30
  9. 9. (J1)1 x  2π 2 1 ⋅ ( x)  (J1 )1 = (J1 ) 2 = ⋅ 2 ⋅ 2π 3  € −x 2  n2  (J1 )1 = (J1 ) 2 = ⋅   ⋅ IC 3  n1 1 € (J1)2 x 21 € (J1 )1 = (J1 ) 2 = ⋅ 600 = 16.33A ⋅ 3 30 −x € € ISARE  2π 2 1 ⋅ (2x )  ISARE = ⋅ 2 ⋅ 2x 2π 3  € 2  n2  ISARE = 2 ⋅ ⋅   ⋅ IC 3  n1 1 21 −2x ISARE = 2 ⋅ ⋅ 600 = 32.66A ⋅ 3 30 30 60 90 120 150 180 210 240 270 300 330 360 €
  10. 10. (VLC )1 = (VLC 0 )1 − (ΔVX )1 = (VLC 0 )1 − 0.12(VLC 0 )1 = (1− 0.12) ⋅ (VLC 0 )1 = 0.88 ⋅ 540 = 475v Δ
 ( ) = 540v 3⋅ 400 2 3VO S 3 (VLC 0 )1 = VLC 0 S 3 = = Δ
 π π VO S 3 = 2 ⋅ U 2 = 400 2 € (VLC ) 2 = (VLC 0 ) 2 − (ΔVX ) 2 = (VLC 0 ) 2 − 0.12(VLC 0 ) 2 = (1− 0.12) ⋅ (VLC 0 ) 2 = 0.88 ⋅ 540 = 475v λ
  2 3⋅ 3 ⋅  400  3 3 3 ⋅ VO PD 3  λ
 (VLC 0 ) 2 = VLC 0 PD 3 = = 540v = π π 2   VO PD 3 = 2 ⋅ U 2  = 400 3  3
  11. 11. [(V ) ⋅ (I ) ] + [(V ) ⋅ (IC ) 2 ] (PLC )1 + (PLC ) 2 [475 ⋅ 600] + [475 ⋅ 600] = 0.84 LC 1 C1 LC 2 FSARE = = = 3 ⋅ U1 ⋅ ISARE 3 ⋅ U1 ⋅ ISARE 3 ⋅12000 ⋅ 32.66  ΔV  cos(ϕ1 )1 = 1−  X  € VR  VLC 0 1 cos(ϕ1 )1 = 1− 0.12 = 0.88 (ϕ1 )1 = (ϕ1 ) 2 (I1)1 (ϕ1 )1 = arccos(0.88) = 28.35º  ΔVX  (I1)2 cos(ϕ1 ) 2 = 1−   VLC 0  2  (I1)SARE = (I1)1 + (I1)2 € cos(ϕ1 ) 2 = 1− 0.12 = 0.88 (ϕ1 ) 2 = arccos(0.88) = 28.35º (VLC 0 )1 ⋅ (IC )1 (VLC 0 ) 2 ⋅ (IC ) 2 540 ⋅ 600 + 540 ⋅ 600 (I1 ) SARE = (I1 )1 + (I1 ) 2 = = 31.17A + = € 3 ⋅ U1 3 ⋅ U1 3 ⋅12000 2 2 2 I  32.66  2 ISARE − ( I1 ) SARE (I≈ ) SARE =  SARE  −1 =   −1 = 0.31 τ SARE = =  (I )  € (I1 ) SARE ( I1) SARE  32.17   1 SARE 

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