Volume

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Volume

  1. 1. VOLUME
  2. 2. How might we find the volume of these prisms? Volume of a prism = (Area of cross-section) X (Height) = AH
  3. 3. b) Find the height of the following prism: b) Find the height of the following prism: Area of cross-section, A Volume = 1 2(a + b)h = 1 2(22 + 30)(14) = 364m2 Examples: a) Find the volume of the storage tank below: = AH = 364 × 50 = 18200m3 Volume = AH 600 = 30Η 600 30 = Η Η = 20χµ
  4. 4. ×10002 kmkm2 mm2 km3 m3 cm3 mm3 ×10003 ×1000 ×1003 ×103 ÷10003 ÷1003 Units of volume ÷103
  5. 5. km3 ×10003 m3 ÷10003 ×1003 cm3 ÷1003 ×103 mm3 ÷103 Convert to and2.4 ×105 cm3 mm3 m3 2.4 ×105 = (2.4 ×105 ×103 ) = 2.4 ×108 cm3 mm3 mm3 2.4 ×105 = (2.4 ×105 ÷1003 ) = (2.4 ×105 ÷106 ) = 2.4 ×10−1 cm3 m3 m3 m3
  6. 6. Capacity Capacity refers to the maximum amount that a container can hold It is usually measured in millilitres (mL), litres (L), kilolitres (kL), or megalitres (ML) We usually refer to the volume of liquid and gases in units of capacity A 1cm x 1cm x 1cm cube has capacity of 1 mL (1 = 1mL) A 10cm x 10cm x10cm cube has capacity of 1 L (1000 = 1 L) cm3 cm3
  7. 7. Units of capacity (m3 ) L mL ×1000 ÷1000 ×1000 ×1000 ÷1000 ÷1000 (cm3 ) kLML 1mL = 1χµ 3 = 1000mL = 1000cm3 1L 1kL = 1000L (= 1000000cm3 ) = 1m3 1ML = 1000κΛ
  8. 8. Example Find the capacity, in ML, of the following storage tank (correct to 1 d.p.) Volume = 18200µ 3 ×1000 ÷1000 ML kL L mL ×1000 ÷1000 ×1000 ÷1000 (m3 ) (cm3 ) 18200m3 = 18200kL = (18200 ÷1000)ML = 18.2ML
  9. 9. Example Find the capacity, in ML, of the following storage tank (correct to 1 d.p.) Volume = 18200µ 3 ×1000 ÷1000 ML kL L mL ×1000 ÷1000 ×1000 ÷1000 (m3 ) (cm3 ) 18200m3 = 18200kL = (18200 ÷1000)ML = 18.2ML

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