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Compromise Quality

Adding Resources

Outsourcing Project Work

Scheduling Overtime

Have owner take on more responsibility

Negative Float: If you have negative project float (meaning the estimated completion date is after the desired date), would your first choice be to tell the customer the date cannot be met and to ask for more time? No; the first choice would be to analyze what could be done about the negative float by compressing the schedule. In crashing or fast tracking, it is best to see all potential choices and then select the option or options that have the least negative impact on the project. For the exam, remember that you need to identify all the possible options and, if given a choice between crashing or fast tracking options, select the choice or combination of choices with the least negative impact

Crash time represents a limit—the greatest time reduction possible under realistic conditions.

Normal time assumes low-cost, efficient methods to complete the activity.

Crash time represents a limit—the greatest time reduction possible under realistic conditions.

Slope represents a constant cost per unit of time.

All accelerations must occur within the normal and crash times.

Normal time assumes low-cost, efficient methods to complete the activity.

Crash time represents a limit—the greatest time reduction possible under realistic conditions.

Slope represents a constant cost per unit of time.

All accelerations must occur within the normal and crash times.

- 1. Time Management Compressing the Project
- 2. Crashing Compressing the Project
- 3. Crashing $0.00 $250.00 $500.00 $750.00 $1,000.00 0 5 10 ActivityCosts Duration (Days) Normal Cost & Duration
- 4. Crashing $0.00 $250.00 $500.00 $750.00 $1,000.00 0 5 ActivityCosts Duration (Days) Crash Cost & Duration
- 5. Crashing $0.00 $250.00 $500.00 $750.00 $1,000.00 $1,250.00 0 5 10 ActivityCosts Duration (Days) Normal Cost & Duration Crash Cost & Duration
- 6. Crashing $0.00 $250.00 $500.00 $750.00 $1,000.00 $1,250.00 0 5 10 ActivityCosts Duration (Days) Normal Cost & Duration Crash Cost & Duration Slope Or Amount per Day = $500 / 5 days = $100 per day
- 7. Crashing $0.00 $250.00 $500.00 $750.00 $1,000.00 $1,250.00 0 5 10 ActivityCosts Duration
- 8. Crashing ID Direct costs Slope Maximum Crash Tim Normal Crash Time Cost Time Cost A 5 $500 4 $600 $100 1 B 10 $1200 6 $2000 $200 4 C 13 $3600 11 $4800 $600 2 D 3 $300 1 $600 $150 2 E 9 $1000 8 $1400 $400 1 F 10 $2400 8 $5400 $1500 2 G 5 $700 5 $700 $0 0
- 9. B 10 D 3 E 9 G 5 A 5 Crashing A->C->F->G = 33 C 13 F 10
- 10. B 10 D 3 E 9 G 5 A 5 Crashing A->C->F->G = 33 A->B->E->G = 29 C 13 F 10
- 11. B 10 D 3 E 9 G 5 A 5 Crashing A->C->F->G = 33 A->B->D->E->G = 32 A->B->E->G = 29 C 13 F 10
- 12. B 10 D 3 E 9 G 5 A 5 Crashing A->C->F->G = 33 A->B->D->E->G = 32 A->B->E->G = 29 C 13 F 10 DUR: 33
- 13. Crashing ID Direct costs Slope Maximum Crash Time Normal Crash Time Cost Time Cost A 5 $500 4 $600 $100 1 B 10 $1200 6 $2000 $200 4 C 13 $3600 11 $4800 $600 2 D 3 $300 1 $600 $150 2 E 9 $1000 8 $1400 $400 1 F 10 $2400 8 $5400 $1500 2 G 5 $700 5 $700 $0 0 $9700
- 14. B 10 D 3 E 9 G 5 A 5 Crashing A->C->F->G = 33 A->B->D->E->G = 32 A->B->E->G = 29 C 13 F 10 DUR: 33 $9700
- 15. B 10 D 3 E 9 G 5x A 5 Crashing A->C->F->G = 33 A->B->D->E->G = 32 A->B->E->G = 29 C 13 F 10 ID Slope Max Crash A $100 1 C $600 2 F $1500 2 G $0 0 DUR: 33 $9700
- 16. B 10 D 3 E 9 G 5x A 4x Crashing A->C->F->G = 32 A->B->D->E->G = 31 A->B->E->G = 28 C 13 F 10 ID Slope Max Crash A $100 1 C $600 2 F $1500 2 G $0 0 DUR: 32 $9700+$100=$9800
- 17. B 10 D 3 E 9 G 5x A 4x Crashing A->C->F->G = 31 A->B->D->E->G = 31 A->B->E->G = 28 C 12 F 10 ID Slope Max Crash A $100 1 C $600 1 F $1500 2 G $0 0 DUR: 31 $9700+$100+$600=$10,400
- 18. B 10 D 3 E 9 G 5x A 4x Crashing A->C->F->G = 31 A->B->D->E->G = 31 A->B->E->G = 28 C 12 F 10 ID Slope Max Crash A $100 1 C $600 1 F $1500 2 G $0 0 DUR: 31 $9700+$100+$600=$10,400
- 19. B 10 D 3 E 9 G 5x A 4x Crashing A->C->F->G = 31 A->B->D->E->G = 31 A->B->E->G = 28 C 12 F 10 DUR: 31 $9700+$100+$600=$10,400 ID Slope Max Crash B $200 4 C $600 1 D $150 2 E $400 1
- 20. B 10 D 3 E 9 G 5x A 4x Crashing A->C->F->G = 31 A->B->D->E->G = 31 A->B->E->G = 28 C 12 F 10 DUR: 31 $9700+$100+$600=$10,400 ID Slope Max Crash B $200 4 C $600 1 D $150 2 E $400 1
- 21. B 10 D 2 E 9 G 5x A 4x Crashing A->C->F->G = 30 A->B->D->E->G = 30 A->B->E->G = 28 C 11x F 10 DUR: 30 $9700+$100+$600+$600+150=$ 11,150 ID Slope Max Crash B $200 4 C $600 1 D $150 1 E $400 1
- 22. Crashing $11,150.00 $10,400.00 $9,800.00 $9,700.00 0 3750 7500 11250 15000 28 30 31 32 33 Direct Costs
- 23. Crashing $11,150.00 $10,400.00 $9,800.00 $9,700.00 9000 9750 10500 11250 12000 28 30 31 32 33 Direct Costs
- 24. Crashing $11,150.00 $10,400.00 $9,800.00 $9,700.00 0 3750 7500 11250 15000 28 30 31 32 33 Direct Costs
- 25. Crashing $11,150.00 $10,400.00 $9,800.00 $9,700.00 $8,150.00 $8,400.00 $8,800.00 $9,700.00 0 3750 7500 11250 15000 28 30 31 32 33 Direct Costs Cost w Incentive Optimum Cost/Time
- 26. Crashing $11,150.00 $10,400.00 $9,800.00 $9,700.00 0 3750 7500 11250 15000 28 30 31 32 33 Direct Costs
- 27. Crashing $11,150.00 $10,400.00 $9,800.00 $9,700.00 $1,400.00 $1,600.00 $1,800.00 $2,000.00 $12,550.00 $12,000.00 $11,600.00 $11,700.00 0 3750 7500 11250 15000 28 30 31 32 33 Direct Costs Indirect Total Costs Optimum Cost/Time
- 28. Crashing 0 12.5 25 37.5 50 0 2 4 6 8 10 12 14 16 18 20 Indirect Costs Direct Costs Total Costs Optimum Cost/Time
- 29. Pros • Reduces project time • Can find optimum project time. Crashing Cons • Increases Direct Costs • Increased Management Time • May Increate Risk

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