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Figure out the value (True or False) of these logical expressions with.docx

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Figure out the value (True or False) of these logical expressions with.docx

Figure out the value (True or False) of these logical expressions without using MATLAB. (~ means NO T, && means AND, || means OR) a=1, b=12 (a 7) | (b > 9) x=[0 1 2 3 4], y=[4 3 2 10] z =x==y x=[0 1 2 3 4], y = [4 3 2 1 0] x2)
Solution
a) a= 1, b = 12
=> a <= 0 is False, b < 11 is also False,
Therefore, False || False is False
b) a= 8, b= 2
=> a==10 is False, b not equal to 20 is True
Therefore, False && True is False
c) a= 8, b= -2
a==1000 is False, b>1000 is also False, a<10 is True
not has highest precedence, so its operation is performed first.
and is performed next.
or has the lowest precedence, so it is performed last.
Therefore, False && False || True will be True
d) a= 1, b= 2.3
(a*b) > 0 is True, b==2 is False, a> 7 is False, b >9 is False.
Therefore, (a*b) > 0 && b==2 && a> 7 || b >9 is False
e) x =[0 1 2 3 4] b= [4 3 2 1 0]
here z is not defined so we cannot find the behaviour of z==x==y
f) x =[0 1 2 3 4] b= [4 3 2 1 0]
x <= 2 is false as x has some values greater than 2
g) x = 0.5
(x>2) is false
therefore, not(x>2) is True
.

Figure out the value (True or False) of these logical expressions without using MATLAB. (~ means NO T, && means AND, || means OR) a=1, b=12 (a 7) | (b > 9) x=[0 1 2 3 4], y=[4 3 2 10] z =x==y x=[0 1 2 3 4], y = [4 3 2 1 0] x2)
Solution
a) a= 1, b = 12
=> a <= 0 is False, b < 11 is also False,
Therefore, False || False is False
b) a= 8, b= 2
=> a==10 is False, b not equal to 20 is True
Therefore, False && True is False
c) a= 8, b= -2
a==1000 is False, b>1000 is also False, a<10 is True
not has highest precedence, so its operation is performed first.
and is performed next.
or has the lowest precedence, so it is performed last.
Therefore, False && False || True will be True
d) a= 1, b= 2.3
(a*b) > 0 is True, b==2 is False, a> 7 is False, b >9 is False.
Therefore, (a*b) > 0 && b==2 && a> 7 || b >9 is False
e) x =[0 1 2 3 4] b= [4 3 2 1 0]
here z is not defined so we cannot find the behaviour of z==x==y
f) x =[0 1 2 3 4] b= [4 3 2 1 0]
x <= 2 is false as x has some values greater than 2
g) x = 0.5
(x>2) is false
therefore, not(x>2) is True
.