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# Force system in space

Force system in space

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### Force system in space

1. 1. Force system in space<br />Equilibrium of Concurrent Forces <br />in Space<br />Statics<br />Of rigid bodies<br />
2. 2. EQUILIBRIUM is defined as that condition when the resultant of the system of force is zero.<br />Statics<br />Of rigid bodies<br />Equilibrium Equations;<br />
3. 3. Example:<br />The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10)<br />Neglecting the weights of the members, determine the forces in AB, AC & AD.<br />y<br />1000 lb<br />A<br />20 ft<br />C<br />10 ft<br />D<br />B<br />10 ft<br />x<br />o<br />10 ft<br />5 ft<br />6 ft<br />z<br />
4. 4. Example:<br />The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10)<br />Neglecting the weights of the members, determine the forces in AB, AC & AD.<br />y<br />1000 lb<br />A<br />20 ft<br />Cz<br />Cx<br />C<br />10 ft<br />Cy<br />Dx<br />D<br />B<br />x<br />o<br />10 ft<br />5 ft<br />6 ft<br />Dz<br />By<br />Dy<br />z<br />
5. 5. y<br />Yc<br />1000 lb<br />0<br />(10)<br />(15)<br />-Dx<br />+(1000)<br />=<br />A<br />=<br />Dx<br />667 lb<br />20 ft<br />x = 10 ft<br />Cz<br />Cx<br />15 ft<br />y = 20 – 6 = 14 ft<br />z = 5 ft<br />C<br />10 ft<br />Cy<br />10 ft<br />Dx<br />D<br />B<br />d = 17.916 ft<br />x<br />o<br />10 ft<br />6 ft<br />5 ft<br />Dy = 933 lb<br />Dz<br />By<br />Dy<br />Dz = 333 lb<br />z<br />AD = 1192 lb T<br />

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Sep. 23, 2014
• #### rexonrex

Sep. 30, 2014
• #### NaicyBalakrishnan

Dec. 15, 2018
• #### ChesterLumahan

Dec. 11, 2019

Force system in space

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