SHARING GASOLINE
COSTS
The Problem…
The Problem…
HOW MUCH SHOULD EACH
PERSON PAY?
TRY TO FIND THE FAIREST
POSSIBLE METHOD. SHOW
ALL YOUR WORK.
My Method to Solve the ProblemLara
10
Blocks
to
School
20
Blocks
to
School
&
Back
My Method to Solve the ProblemChan
8
Blocks
to
School
16
Blocks
to
School
&
Back
My Method to Solve the ProblemJason
5
Blocks
to
School
10
Blocks
to
School
&
Back
My Method to Solve the ProblemMarla
2
Blocks
to
School
4
Blocks
to
School
&
Back
My Method to Solve the Problem…
Student
Blocks
to School
Blocks
to School
& Back
Lara 10 20
Chan 8 16
Jason 5 10
Marla 2 4
20 (LARA) + 16 (CHAN) + 10 (JASON) + 4
(MARLA) = 50 TOTAL BLOCKS
LARA = 20/50 = 2/5 (SIMPLIFIED)
CHAN = 16/50 = 8/25 (SIMP...
2
-------- X $300 = $120
5
(LARA) (TOTAL) (MONEY OWED)
My Method to Solve the ProblemLara
8
-------- X $300 = $96
25
(CHAN) (TOTAL) (MONEY OWED)
My Method to Solve the ProblemChan
1
-------- X $300 = $60
5
(JASON) (TOTAL) (MONEY OWED)
My Method to Solve the ProblemJason
2
-------- X $300 = $24
25
(MARLA) (TOTAL) (MONEY OWED)
My Method to Solve the ProblemMarla
My Method to Solve this
Problem
 As I started this problem I determined how many
blocks each person was in the car. I fig...
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Sharing Gasoline Costs PBT

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Sharing Gasoline Costs PBT

  1. 1. SHARING GASOLINE COSTS
  2. 2. The Problem…
  3. 3. The Problem…
  4. 4. HOW MUCH SHOULD EACH PERSON PAY? TRY TO FIND THE FAIREST POSSIBLE METHOD. SHOW ALL YOUR WORK.
  5. 5. My Method to Solve the ProblemLara 10 Blocks to School 20 Blocks to School & Back
  6. 6. My Method to Solve the ProblemChan 8 Blocks to School 16 Blocks to School & Back
  7. 7. My Method to Solve the ProblemJason 5 Blocks to School 10 Blocks to School & Back
  8. 8. My Method to Solve the ProblemMarla 2 Blocks to School 4 Blocks to School & Back
  9. 9. My Method to Solve the Problem… Student Blocks to School Blocks to School & Back Lara 10 20 Chan 8 16 Jason 5 10 Marla 2 4
  10. 10. 20 (LARA) + 16 (CHAN) + 10 (JASON) + 4 (MARLA) = 50 TOTAL BLOCKS LARA = 20/50 = 2/5 (SIMPLIFIED) CHAN = 16/50 = 8/25 (SIMPLIFIED) JASON = 10/50 = 1/5 (SIMPLIFIED) MARLA = 4/50 = 2/25 (SIMPLIFIED) My Method to Solve the Problem
  11. 11. 2 -------- X $300 = $120 5 (LARA) (TOTAL) (MONEY OWED) My Method to Solve the ProblemLara
  12. 12. 8 -------- X $300 = $96 25 (CHAN) (TOTAL) (MONEY OWED) My Method to Solve the ProblemChan
  13. 13. 1 -------- X $300 = $60 5 (JASON) (TOTAL) (MONEY OWED) My Method to Solve the ProblemJason
  14. 14. 2 -------- X $300 = $24 25 (MARLA) (TOTAL) (MONEY OWED) My Method to Solve the ProblemMarla
  15. 15. My Method to Solve this Problem  As I started this problem I determined how many blocks each person was in the car. I figured it out for a one way trip and a to school and back. I compared this problem to the fraction unit we did earlier in the year and also the ratio and proportion unit. I figured out the part for each of the students in the car compared to the whole. I created fractions for each of the students to represent their time in the car. I simplified each of the fractions. I knew that the total cost was $300 so I used $300 and multiplied it by the fraction of each student to get my total cost per kid. I figured this is a fair to split the cost because if you are in the car longer you should pay more and if you are in the car less you should pay less.

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