AP Calculus BC parametric, vector frq

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  • In my previous post, I am refferring to the 3rd problem.
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  • On Part 'C', It appears you have made an algebra error. when going from (9/t^2) = 6 , You cannot just turn the 1/t^2 to t^2. There are two ways to correctly solve at that point Probably the best way to do it would be to multiply both sides by t^2, so you have 6t^2 = 9. Then divide 9 by 6, which gives you 3/2, and then take the square root of 3/2 , which will give you 'radical 3/2' .

    I appreciate you posting this, but hopefully you can edit this soon so no unsuspecting student will become confused.
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AP Calculus BC parametric, vector frq

  1. 1. AP Calculus BC Parametric and Vector-Based Free Response Questions
  2. 2. 1998 BC 6
  3. 3. 1999 BC 1 Video 1 1999 BC 1 Video 2 1999 BC 1 Video 3 1999 BC 1 Video 4 1999 BC 1 Video 5 1999 BC 1 Video 6
  4. 4. 2000 BC 4
  5. 5. 2001 BC 1
  6. 6. 2002 BC 1 (Form B)

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